IB Chemistry HL Topic 6 — Electron Transfer Paper 1 & 2 Core idea ~9 min read

The Hydrogen Electrode

You can never measure the voltage of one half-cell on its own. A voltmeter has two leads, so it can only ever tell you the difference between two things. Chemists got around this by picking one half-cell, calling it zero, and measuring everything else against it. That half-cell is the standard hydrogen electrode.

📚 What you need to know

Why you cannot measure one half-cell

Dip a zinc rod into zinc sulfate solution and something real happens: zinc atoms leave the rod as Zn2+ ions and dump electrons behind, so the rod builds up a negative charge. There is a genuine potential difference between the rod and the solution.

The problem is getting at it. To read a voltage you must touch both leads of the voltmeter to something. One lead goes on the zinc rod — fine. But the moment you dip the other lead into the solution, that lead becomes a second electrode with its own potential, and now you are reading two things at once.

Think about altitude. You can say a mountain is 3000 m high, but 3000 m above what? We all agreed on sea level. Sea level is not “no height” in any deep sense — it is just the line everyone decided to call zero. The hydrogen electrode is chemistry’s sea level.

What the standard hydrogen electrode actually is

It is a half-cell built out of hydrogen gas and hydrogen ions, with a piece of platinum acting as the metal that carries electrons in and out.

The standard hydrogen electrode The agreed zero point for every other half-cell H₂(g) in at 100 kPa (the standard pressure) platinum electrode inert, and roughened for a big surface areato voltmeter glass tube holds the gas against the metal H⁺(aq), 1.00 mol dm⁻³ held at 298 K2H⁺(aq) + 2e⁻ ⇌ H₂(g) This value is defined as zero. Everything else is measured from it.
The platinum does not react — it is there purely as a landing strip where hydrogen gas and hydrogen ions can swap electrons.

Why platinum, and why roughened?

The reference half-equation 2H+(aq) + 2e− ⇌ H2(g)    Eθ = 0.00 V

Using it to measure another half-cell

Connect the SHE to the half-cell you want to measure, join the solutions with a salt bridge, and read the voltmeter. Because the left-hand value is zero, whatever the meter says is the standard electrode potential of the other half-cell.

Measuring a half-cell against the hydrogen electrode The hydrogen electrode always goes on the left V electronsvoltmeter reads −0.76 V STANDARD HYDROGEN ELECTRODE 2H⁺ + 2e⁻ ⇌ H₂ Eθ = 0.00 V always the left-hand cell (defined as zero)ZINC HALF-CELL Zn²⁺ + 2e⁻ ⇌ Zn Eθ = −0.76 V the reading is exactly this half-cell’s valuesalt bridgeEMF = E(right) − E(left) = −0.76 − 0.00 = −0.76 V Because the left-hand value is zero, the reading is the other half-cell.
Zinc comes out negative, so electrons push from the zinc towards the hydrogen electrode. A negative Eθ means “loses electrons more readily than hydrogen does”.

🧩 Reading a hydrogen-electrode cell

  1. Put the SHE on the left. That is the convention, and it is what makes the maths easy.
  2. Read the meter. EMF = E(right) − E(left), and E(left) = 0, so EMF = E(right).
  3. Check the sign. If the unknown electrode is the negative terminal, its Eθ is negative.
  4. Write it as a reduction. Data booklet values always show electrons being gained, e.g. Zn2+ + 2e− ⇌ Zn.

Why nobody actually uses one

The SHE is the definition, not the everyday tool. In a real lab it is a nuisance:

The workaround: once a half-cell has been measured against the SHE, it can be used as a stand-in reference. A silver/silver chloride electrode is the usual choice — small, stable and no gas cylinder required. Its value is still traceable back to hydrogen.

Worked examples

WORKED EXAMPLE

A standard hydrogen electrode is connected to a standard nickel half-cell. The voltmeter reads 0.26 V and the nickel is the negative terminal. Find Eθ for Ni2+/Ni.

Set the cell up the standard way SHE on the left, so E(left) = 0.00 V. Nickel on the right. Apply the rule EMF = E(right) − E(left) = E(Ni) − 0.00 Fix the sign from the polarity Nickel is negative, so it is pushing electrons out. Its value must be below zero. Eθ(Ni2+/Ni) = −0.26 V the size comes from the meter, the sign comes from which terminal is negative
WORKED EXAMPLE

Write the conventional cell diagram for a standard hydrogen electrode joined to a standard silver half-cell, Eθ(Ag+/Ag) = +0.80 V.

Start on the left with the hydrogen electrode Platinum, then the gas, then the ions. Single lines are phase boundaries. Pt(s) | H2(g) | H+(aq) Double line for the salt bridge, then the right-hand cell Highest oxidation state sits next to the salt bridge on both sides. Pt(s) | H2(g) | H+(aq) || Ag+(aq) | Ag(s)   Eθ = +0.80 V positive value, so silver is the positive terminal and gains electrons
WORKED EXAMPLE

In a cell made from a SHE and an unknown metal half-cell, the hydrogen electrode is the positive terminal and the reading is 0.44 V. What is Eθ of the unknown, and what happens at each electrode?

Work out the sign first Hydrogen is positive, so the unknown metal is negative — it loses electrons more readily than hydrogen. Eθ(unknown) = −0.44 V Decide the electrode reactions Negative electrode = oxidation. Positive electrode = reduction. M(s) → M2+(aq) + 2e−  and  2H+(aq) + 2e− → H2(g) −0.44 V — the metal is oxidised, hydrogen gas is produced that value belongs to iron: Fe2+ + 2e− ⇌ Fe is −0.45 V in the booklet

💡 Exam tip

⚠ Common mix-up

Up next: Standard Cell Potentials — now that every half-cell has a number, you can put any two together and work out the voltage, and predict whether the reaction goes at all.

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