IB & GCSE Maths
A trig exact value chart gives you sin, cos and tan for the five angles you are expected to know without a calculator: 0°, 30°, 45°, 60° and 90°. The full table is below, in degrees and radians.
But a table you only memorised is a table you can forget. So after the chart, this page shows you where every single value comes from — two triangles and one hand trick — so that if your memory goes blank in a non-calculator paper, you can rebuild the whole thing from scratch in about twenty seconds.
The short answer
Every exact value in the chart is √n ÷ 2, where n counts up 0, 1, 2, 3, 4 as the angle grows. So sin of 0°, 30°, 45°, 60°, 90° is √0/2, √1/2, √2/2, √3/2, √4/2 — which simplifies to 0, ½, √2/2, √3/2, 1. Cos is the same list backwards. Tan is just sin ÷ cos.
This is the complete trigonometry table for the five special angles. These are the only exact trig values you are expected to recall in a non‑calculator paper.
| Angle | Radians | sin | cos | tan |
|---|---|---|---|---|
| 0° | 0 | 0 | 1 | 0 |
| 30° | π6 | 12 | √32 | √33 |
| 45° | π4 | √22 | √22 | 1 |
| 60° | π3 | √32 | 12 | √3 |
| 90° | π2 | 1 | 0 | undefined |
You will see this same exact trig values table called several different things — a sin cos tan table, a trig table, a trigonometry table, a trig values table or an exact value trig chart. They all mean the chart above, so if you arrived here searching for one of those, you are in the right place.
Three things that halve what you memorise
Pick your angle in the left column, then read across to the ratio you need. Two worked reads:
Both are correct and both equal 0.5773… They differ only by rationalising the denominator — multiplying top and bottom by √3 to clear the surd out of the bottom of the fraction:
Most exam boards accept either form unless the question says “give your answer with a rational denominator”. If in doubt, write √3/3 — it is never marked wrong.
This is the part most revision pages skip, and it is the part that makes the chart impossible to forget. Every value in the table comes from just two triangles. If you can draw these two shapes, you never need the table again.
Start with a square of side 1 and cut it along the diagonal. You get a right‑angled triangle with two legs of 1 and two equal angles, so each must be 45°. Pythagoras gives the hypotenuse:
Scroll the diagram sideways →
Now just read the ratios off the shape, using SOH‑CAH‑TOA with 45° as the angle:
That is the whole 45° row, derived in three lines. Notice why sin 45° and cos 45° are equal: the two legs are the same length, so “opposite” and “adjacent” are the same number.
Start with an equilateral triangle of side 2. All three angles are 60°. Drop a perpendicular from the apex to the base: it cuts the base exactly in half (giving 1 and 1) and cuts the 60° apex angle exactly in half (giving 30°). Pythagoras gives the height:
Scroll the diagram sideways →
This single triangle gives you two rows of the chart, because it contains both a 30° angle and a 60° angle. The only thing that changes is which side counts as “opposite”.
Looking at the 30° angle at the top. The side opposite it is the short one (1). The side next to it is the long one (√3). The hypotenuse is 2.
Now looking at the 60° angle at the bottom. Opposite and adjacent swap over: the side opposite 60° is the long one (√3), and the side next to it is the short one (1).
Two triangles give you every exact trig value. The 45‑45‑90 gives the 45° row; the 30‑60‑90 gives the 30° and 60° rows. 0° and 90° you can reason out in seconds.
These two are not from a triangle — you cannot have a triangle with a 0° angle. Instead, picture a right‑angled triangle and imagine squashing the angle down towards 0° or opening it up towards 90°.
If drawing triangles feels slow under exam pressure, there is a faster method that uses nothing but your left hand. It gives you sin and cos for all five angles in a couple of seconds, and it works because of the √n ÷ 2 pattern already noted at the top of this page.
Hold up your left hand, palm towards you. Starting at the thumb and moving across to the little finger, the five fingers stand for the five angles: 0°, 30°, 45°, 60°, 90°.
Say you want sin 60°. Fold down the ring finger, because that is the 60° finger. Now count the fingers left standing on each side of the fold:
Scroll the diagram sideways →
In the example above, folding the 60° finger leaves three fingers below it and one above:
Both match the chart exactly. Here is every angle worked through the same way, so you can check the trick against the table:
| Fold this finger | Below | sin | Above | cos |
|---|---|---|---|---|
| Thumb — 0° | 0 | √0/2 = 0 | 4 | √4/2 = 1 |
| Index — 30° | 1 | √1/2 = ½ | 3 | √3/2 |
| Middle — 45° | 2 | √2/2 | 2 | √2/2 |
| Ring — 60° | 3 | √3/2 | 1 | √1/2 = ½ |
| Little — 90° | 4 | √4/2 = 1 | 0 | √0/2 = 0 |
What about tan? The hand trick does not give tan directly, and that is fine — divide the sin you just found by the cos you just found. For 60°: tan 60° = (√3/2) ÷ (1/2) = √3.
The trick is not magic. It works because the number of fingers below the fold counts up 0, 1, 2, 3, 4 exactly as the angle grows — which is the same √n ÷ 2 pattern the chart follows. The hand is just a way of counting it without writing anything down.
If you are doing IB Maths, A‑level or anything beyond GCSE, you will meet these same exact values written in radians rather than degrees. Nothing about the values changes — only the label on the angle.
A radian is just a different unit for measuring turn, in the same way that kilometres and miles are different units for measuring distance. The one fact that connects them:
π radians = 180°
Everything else follows from that single line. To convert in either direction:
So 60° becomes 60 × π/180 = π/3, which is the value already shown in the radians column of the chart. Working the other way, π/4 becomes (π/4) × (180/π) = 45°.
Check your calculator mode. The single most common source of lost marks in trigonometry is a calculator left in the wrong mode. If a question is in radians and your calculator is in degrees, every answer will be wrong even though every method is right. Look for DEG or RAD on the display before you start.
It is not to make life harder. Radians make the calculus of trigonometry work cleanly — the derivative of sin x is cos x only when x is in radians. In degrees you would be stuck carrying an awkward factor of π/180 through every single line. Arc length and sector area formulas are also far simpler in radians.
If you are heading into IB Maths, it is worth getting comfortable reading the radian column of the chart as fluently as the degrees column, because past the first year you will rarely see degrees again.
The five‑angle chart covers 0° to 90°. But exam questions ask for things like sin 150° or cos 240° too. You do not need to learn a second, longer table — every one of those values is a value you already know, with a sign attached.
Picture a circle of radius 1 with its centre at the origin. Measure your angle anticlockwise from the positive x‑axis, and mark the point where that angle lands on the circle. The coordinates of that point are exactly (cos θ, sin θ).
Angles past 90° land in the other three quarters of the circle, but they are always the same distance from the horizontal axis as one of your five known angles. That known angle is called the reference angle. So:
Find the reference angle, look up its value in the five‑angle chart, then decide the sign using the rule in the next section. That is the entire method.
Here is every exact trigonometric value you will be asked for in a full turn. Notice that no new numbers appear — it is the same short list of values from the five‑angle chart, repeating with different signs.
| Angle | Radians | sin | cos | tan |
|---|---|---|---|---|
| 0° | 0 | 0 | 1 | 0 |
| 30° | π6 | 12 | √32 | √33 |
| 45° | π4 | √22 | √22 | 1 |
| 60° | π3 | √32 | 12 | √3 |
| 90° | π2 | 1 | 0 | undefined |
| 120° | 2π3 | √32 | −12 | −√3 |
| 135° | 3π4 | √22 | −√22 | −1 |
| 150° | 5π6 | 12 | −√32 | −√33 |
| 180° | π | 0 | −1 | 0 |
| 210° | 7π6 | −12 | −√32 | √33 |
| 225° | 5π4 | −√22 | −√22 | 1 |
| 240° | 4π3 | −√32 | −12 | √3 |
| 270° | 3π2 | −1 | 0 | undefined |
| 300° | 5π3 | −√32 | 12 | −√3 |
| 315° | 7π4 | −√22 | √22 | −1 |
| 330° | 11π6 | −12 | √32 | −√33 |
| 360° | 2π | 0 | 1 | 0 |
Read down the sin column and you will see the values of trigonometric ratios repeat: 0, ½, √2/2, √3/2, 1 climb and fall and climb again. There are only five distinct sizes in the whole table. Learn those five and the signs, and you have all seventeen rows.
Once you have the reference angle, you need one more thing: the sign. Whether sin, cos or tan comes out positive or negative depends only on which quarter of the circle your angle lands in, and the pattern never changes.
The memory aid is the word CAST, read starting from the bottom‑right quadrant and moving anticlockwise.
Scroll the diagram sideways →
Find the exact value of sin 150° without a calculator.
Find the exact value of cos 240° without a calculator.
Every other cell in the chart holds a number. The tan 90° cell says “undefined”, and it is worth understanding why rather than just memorising the word.
Since tan is sin divided by cos:
Dividing by zero has no answer, so tan 90° simply does not exist. The same happens at 270°, where cos is also zero.
There is a nice way to picture it. On the unit circle, tan θ is the gradient of the line from the origin out to your point. As the angle climbs towards 90° that line gets steeper and steeper, and a perfectly vertical line has no gradient at all — it rises without ever moving sideways.
Write “undefined”, not “infinity” and not “error”. Examiners want the word undefined. Writing ∞ is treated as wrong because tan approaches +∞ from one side and −∞ from the other, so there is no single value to approach.
These are the slips that cost marks most often. None of them are about not knowing the values — they are about using them carelessly.
| The mistake | What goes wrong | Do this instead |
|---|---|---|
| Calculator in the wrong mode | A radian question answered in DEG mode gives a completely different number, with no warning on screen. | Check DEG or RAD before question 1, not after you lose marks. |
| Reading √3/2 as √(3/2) | √3/2 = 0.866 but √(3/2) = 1.225. Only the 3 is under the root sign. | Read it as “root three, all over two“. The 2 is never under the root. |
| Swapping the sin and cos columns | Giving cos 30° = ½ instead of √3/2. The two columns hold the same numbers, so a slip is easy to miss. | Sanity check against 45°: below 45°, sin is the smaller one; above 45°, cos is. |
| Assuming the values scale evenly | sin 30° = 0.5, so students guess sin 60° = 1. It is actually 0.866. Sine is not a straight line. | Always read the value from the chart rather than scaling a known one up. |
| Writing tan 90° = ∞ | Marked wrong. Tan runs off to +∞ on one side of 90° and −∞ on the other, so there is no single value. | Write undefined. That is the word examiners are looking for. |
| Forgetting the sign past 90° | Giving cos 240° = ½ when it is −½. The size was right; the quadrant was ignored. | Always do the CAST check as a separate, deliberate step before writing the answer. |
Work each one out on paper first, then tap to check. They get harder as you go. Every answer below has been checked symbolically, so if your answer disagrees, look again at your working.
Straight read from the 60° row, sin column
sin 60° = √3 / 2
As a decimal that is 0.866, but leave it as a surd
The 45° triangle has two equal legs, so opposite = adjacent
tan 45° = 1
This is the only whole-number tan value in the chart
From the triangle, tan 30° = 1 / √3
= (1 / √3) × (√3 / √3)
= √3 / 3
Multiplying top and bottom by √3 clears the surd from below
Multiply by π/180
135 × π / 180
= 135π / 180
= 3π / 4
Divide top and bottom by 45 to simplify
π/3 radians is 60°, so this is sin 60°
sin(π/3) = √3 / 2
Same value, different unit on the angle
Reference angle: 180° − 150° = 30°
cos 30° = √3 / 2
150° is in the S quadrant, so cos is negative there
cos 150° = −√3 / 2
Reference angle: 225° − 180° = 45°
sin 45° = √2 / 2
225° is in the T quadrant, where only tan is positive
sin 225° = −√2 / 2
sin = opposite / hypotenuse
sin 30° = opp / 12
1/2 = opp / 12
opp = 6 cm
The side opposite 30° is always half the hypotenuse
Substitute the exact values from the chart
= (√3/2)(√3/2) + (1/2)(1/2)
= 3/4 + 1/4
= 1
This is the addition formula: sin(60° + 30°) = sin 90° = 1
A trig exact value chart is a table giving sin, cos and tan for the angles 0°, 30°, 45°, 60° and 90° as exact surds and fractions rather than rounded decimals. It is the set of values you are expected to recall without a calculator. The values come from two triangles: the 45-45-90 triangle and the 30-60-90 triangle.
For sin: 0, 1/2, √2/2, √3/2 and 1 at 0°, 30°, 45°, 60° and 90°. For cos it is the same five numbers in reverse order: 1, √3/2, √2/2, 1/2 and 0. For tan: 0, √3/3, 1, √3 and undefined. Tan is always just sin divided by cos, so it never needs memorising separately.
You need to be able to produce them, but memorising is not the only route. Sketching the 30-60-90 and 45-45-90 triangles takes about twenty seconds and gives you every value in the chart. The hand trick is faster still. Most students end up remembering the table through use, with the triangles as a backup when memory fails under pressure.
Hold up your left hand and let the fingers stand for 0°, 30°, 45°, 60° and 90° from thumb to little finger. Fold down the finger for your angle. The sine is the square root of the number of fingers below the fold, divided by 2. The cosine is the square root of the number of fingers above the fold, divided by 2. For 60° you fold the ring finger, leaving three below and one above, giving sin 60° = √3/2 and cos 60° = √1/2 = 1/2.
The first is the 45-45-90 triangle, made by cutting a unit square along its diagonal. It has legs of 1 and 1 and a hypotenuse of √2. The second is the 30-60-90 triangle, made by halving an equilateral triangle of side 2. It has sides 1, √3 and 2. Between them these two shapes produce every value in the chart.
sin 30° = 1/2 exactly. In the 30-60-90 triangle, the side opposite the 30° angle is the short one of length 1 and the hypotenuse is 2, so the ratio is 1/2. This is the only exact trig value that is a simple fraction with no surd.
cos 45° = √2/2, which is the same number as 1/√2 and equals about 0.7071. In the 45-45-90 triangle the adjacent side is 1 and the hypotenuse is √2. Because that triangle is symmetrical, sin 45° has the same value.
tan 60° = √3. In the 30-60-90 triangle, the side opposite 60° is √3 and the side adjacent to it is 1, so the ratio is √3 ÷ 1 = √3. As a decimal that is about 1.732.
Because tan is sin divided by cos, and cos 90° = 0. That makes tan 90° equal to 1 ÷ 0, which has no answer. Geometrically, tan is the gradient of the line from the origin to the point on the unit circle, and at 90° that line is vertical, so it has no gradient. Write ‘undefined’ rather than infinity, because tan runs to +∞ on one side of 90° and −∞ on the other.
No, and confusing them is a common error. √3/2 means the square root of 3, then divided by 2, which is about 0.866. √(3/2) means the square root of the whole fraction 3/2, which is about 1.225. In the exact value chart only the number under the root sign is inside the root; the 2 on the bottom is always outside it.
They are the same number, about 0.5774. The second form has been rationalised, meaning top and bottom were multiplied by √3 to remove the surd from the denominator. Most exam boards accept either, but √3/3 is never marked wrong, so it is the safer form to write if a question asks for a rational denominator.
Find the reference angle, which is the distance to the nearest horizontal axis, then look that angle up in the five-angle chart and attach the right sign. For 150° the reference angle is 30°, so the size matches sin 30° = 1/2. Then use CAST to decide the sign: 150° is in the second quadrant where sin is positive, so sin 150° = +1/2.
CAST tells you which ratios are positive in each quarter of the circle, read starting from the bottom-right quadrant and moving anticlockwise. C is cos positive from 270° to 360°, A is all three positive from 0° to 90°, S is sin positive from 90° to 180°, and T is tan positive from 180° to 270°. Anything not named in a quadrant is negative there.
sin 0° = 0 and cos 0° = 1. These two do not come from a triangle, because a triangle cannot have a 0° angle. Instead picture the angle shrinking towards zero: the opposite side shrinks away to nothing while the adjacent side becomes the whole hypotenuse. tan 0° is then 0 ÷ 1 = 0.
Multiply by π/180. So 60° becomes 60 × π/180 = π/3. To go back the other way, multiply by 180/π, so π/4 becomes 45°. Everything follows from the single fact that π radians equals 180°.
In a non-calculator paper you are expected to produce them yourself, either from memory or by sketching one of the two triangles. That is why knowing where the values come from is more useful than memorising the table alone: a sketched triangle gives you the whole 30°, 45° and 60° set in seconds, even if your memory has gone blank.
The exact values are rarely the whole question. They turn up inside something larger — solving a trig equation, simplifying an expression, finding an area, working through a problem in IB Maths. What examiners are really checking is whether you can produce the right value quickly and attach the right sign, without reaching for a calculator you are not allowed.
So the useful test is not “can I recite the table”. It is this: given any angle between 0° and 360°, in degrees or radians, can you write down its sin, cos and tan exactly, in under ten seconds, with the correct sign? If you can draw the two triangles and run the CAST check, you can.
The whole page in six lines
A wrong sign or a calculator in the wrong mode turns correct method into zero marks. Our tutors teach IB and A‑level maths and work through your own past papers rather than a generic worksheet, so the mistakes we fix are the ones you are actually making.
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