IB Chemistry SL & HL Topic 5 — The Rate of Chemical Change Paper 1 & 2 Core idea ~11 min read

Factors Affecting Reaction Rate

There are five things you can change to speed a reaction up. That sounds like five explanations to memorise, but it is really only two — every one of them works by changing how often particles collide, or what fraction of those collisions actually works.

📘 What you need to know

The two levers

Before the details, get this framework straight. Rate is the number of successful collisions per second, and that number is made of two parts:

The whole topic in one line successful collisions per second = (collisions per second) × (fraction that succeed)

So there are exactly two ways to speed a reaction up: increase the first bracket, or increase the second. Every factor below does one or both.

FactorWhat to doMore collisions per second?Bigger fraction with E ≥ Ea?
ConcentrationUse a more concentrated solutionYes — particles are closer togetherNo change
Pressure (gases)Squeeze the gas into a smaller volumeYes — same particles, less spaceNo change
Surface area (solids)Break the solid into smaller piecesYes — more of the solid is exposedNo change
TemperatureHeat the mixtureYes — but only slightlyYes — this is the main effect
CatalystAdd a catalystNo changeYes — a lower Ea route is available
If you can fill in that table from memory, you can answer almost any “explain why the rate increases” question. Just name the lever, then say what it does to successful collisions per second.

Concentration and pressure

These two are the same idea wearing different clothes. Concentration is about particles per unit volume in a solution; pressure is about particles per unit volume in a gas. Increase either and the particles are simply closer together, so they run into each other more often.

More particles in the same space means more collisions Raising concentration or pressure both work this wayDILUTE CONCENTRATED add more same volume few hits per second many hits per secondSqueeze more particles into the same space and they meet far more often. Raising the pressure of a gas does exactly the same job as raising a concentration.
Yellow haloes mark places where two particles are meeting. Nothing about the particles themselves has changed — there are just more chances for a collision.
The fraction does not change here. Packing particles closer together does not make any individual particle more energetic. So the proportion of collisions that succeed is exactly the same — there are simply more attempts per second.

Surface area

When one reactant is a solid, the reaction can only happen on the outside of it. Particles buried in the middle of a lump are doing nothing until the layers above them have dissolved away.

Break the lump up and you expose surfaces that were previously hidden inside. The amount of solid is identical — but the number of places a collision can happen goes up a lot.

Cutting a solid up creates new surface Same mass of solid, far more places to be attackedONE 2 cm CUBE EIGHT 1 cm CUBES surface = 24 cm² surface = 48 cm² volume still 8 cm³Halving the side length in each direction doubles the surface the acid can reach. Cut the same lump into 0.5 cm pieces instead and the surface reaches 96 cm².
The orange dots are acid particles. On the right they can get into the gaps as well as around the outside, and those gaps are surface that did not exist before.

Temperature

Temperature is the odd one out, because it pulls both levers at once. Almost every student names the first effect and stops, and that is where marks go missing.

Effect 1: particles move faster, so they collide more often

True, but small. Going from 25 °C to 35 °C (298 K to 308 K) speeds the particles up by only about 2%, because average speed depends on the square root of the temperature. On its own that would barely change the rate at all.

Effect 2: a much bigger fraction of particles has energy above Ea

This is the real story. Those same ten degrees can almost double the fraction of collisions carrying enough energy to react. That is where the familiar “rate doubles for every 10 °C” rule comes from — not from particles moving faster.

Put numbers on it. For a reaction with Ea of about 50 kJ mol−1, warming from 298 K to 308 K increases collision frequency by roughly 2%, but increases the fraction of collisions with enough energy by a factor of about 1.9. The second effect does essentially all the work.
If a question is worth 2 or 3 marks, give both effects but make clear which dominates. Something like: “particles collide slightly more often, but far more importantly a much greater proportion of collisions now has energy greater than or equal to Ea.”

One warning about the doubling rule: it is a rough guide, not a law. Depending on the reaction it might be every 9 °C or every 11 °C, and the interval drifts as the temperature climbs. Do not use it in a calculation unless a question specifically tells you to.

Catalysts

A catalyst speeds a reaction up without being used up itself. It is chemically unchanged by the end, which is why a tiny amount can process an enormous quantity of reactant.

It works by offering the reactants a different route to the products — one with a lower activation energy. Because the bar is lower, a much larger fraction of the ordinary collisions already clears it.

Say it this way a catalyst provides an alternative pathway of lower Ea

Two other points examiners like:

Rate is not yield. A catalyst gets you to the finishing line faster. It does not move the finishing line. For a reversible reaction it speeds up both directions equally, so the position of equilibrium is unchanged.

Worked examples

WORKED EXAMPLE

Which changes speed the reaction up?

Zinc granules react with dilute sulfuric acid. Which of these would increase the rate?
I. Using the same mass of zinc as a powder
II. Diluting the acid with water
III. Warming the mixture from 20 °C to 40 °C
A. I only   B. I and III only   C. II and III only   D. I, II and III

I: powder instead of granules More surface area, so more collisions per second. Speeds it up. II: diluting the acid Lower concentration, so fewer collisions per second. Slows it down. III: warming it More collisions, and a much bigger fraction above Ea. Speeds it up. Answer: B “same mass as a powder” is the giveaway — the amount is unchanged, only the surface
WORKED EXAMPLE

Explaining the temperature effect properly

Explain why raising the temperature by 10 °C roughly doubles the rate of a reaction, even though the particles only speed up by about 2%. (3 marks)

Mark 1: the small effect Faster particles collide a little more often, so collision frequency rises slightly. Mark 2: the big effect The spread of energies shifts, so a much greater proportion of particles has energy greater than or equal to Ea. Mark 3: the comparison Almost all of the increase in rate comes from the bigger proportion of successful collisions, not from the faster movement. the word “proportion” is what earns the second mark — “more collisions” alone does not
WORKED EXAMPLE

Putting a number on surface area

A single cube of calcium carbonate has sides of 2.0 cm. Calculate its total surface area. It is then cut into eight identical 1.0 cm cubes. Calculate the new total surface area, and comment on the effect on rate.

Step 1: the single cube (6 faces) 6 × (2.0 × 2.0) = 24 cm² Step 2: one small cube 6 × (1.0 × 1.0) = 6 cm² Step 3: all eight together 8 × 6 = 48 cm² Surface area doubles, from 24 cm² to 48 cm² Comment the volume is still 8 cm³, so the same amount of solid now has twice as many sites for collisions — the reaction goes faster

💡 Exam tip

⚠ Common mix-up

Up next: Activation Energy — where Ea actually sits on an energy profile, how to read it off for exothermic and endothermic reactions, and how to find Ea for the reverse reaction.

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