IB Chemistry HL Topic 2 — Models of Bonding & Structure Paper 1 & 2 Core skill ~11 min read

Molecular Shapes

Molecules are not flat and they are not random. Every shape in this topic comes from one stubborn fact: electron pairs are negative, so they get as far away from each other as they possibly can. Learn to count electron domains and you can predict any shape on the syllabus without memorising a single one.

📘 What you need to know

How to count electron domains

This is the only skill on the page. Everything else follows from it.

🧩 The method

  1. Draw the Lewis formula of the species, lone pairs included.
  2. Look only at the central atom. Count every group of electrons attached to it.
  3. One domain for each single bond, each double bond, each triple bond, and each lone pair.
  4. Use the total number of domains to get the electron domain geometry.
  5. Ignore the lone pairs when you name the shape — but remember they are still pushing.
The word “domain” trips people up. Think of it as a lump of negative charge. A triple bond is one fat lump, not three thin ones, so it takes up one position around the central atom.

The six shapes you must know

Two, three or four domains. That is the whole of the standard level list, and it covers the large majority of exam questions.

Two, three and four electron domains
Every shape comes from counting domains and spreading them out Amber lobes are lone pairs. Blue circles are bonded atoms. linear 180° CO₂, BeCl₂ trigonal planar 120° BF₃, CH₂=CH₂ bent about 118° SO₂, 1 lone pair tetrahedral 109.5° CH₄, NH₄⁺ trigonal pyramidal 107° NH₃, 1 lone pair bent 104.5° H₂O, 2 lone pairs Top row: 2, 3 and 3 domains. Bottom row: 4 domains every time. Each lone pair you add closes the bond angle a little further.
Look down the right-hand column and along the bottom row: same number of domains, different number of lone pairs, and the angle drops every time.

Why lone pairs squash the angles

A bonding pair is stretched between two nuclei, so it is held out at arm’s length. A lone pair belongs to one atom only, so it sits closer in and spreads out more. A fatter, closer lump of charge pushes harder.

Not all repulsions are equal
Lone pairs push harder than bonding pairs That is why water closes to 104.5° instead of the ideal 109.5° two lone pairs, pushing down O H H 104.5° STRONGEST lone pair to lone pair lone pair to bonding pair bonding pair to bonding WEAKEST so lone pairs close the angle Count the lone pairs, then knock a couple of degrees off the ideal angle. Four domains: 109.5° with none, 107° with one, 104.5° with two.
The pattern is worth learning as a number line: each lone pair takes roughly 2.5° off the bond angle. It is a rule of thumb, but it matches the real values well.

Two different questions, two different answers

Examiners love this distinction because it separates students who understand from students who memorised.

Ammonia has a tetrahedral electron domain geometry but a trigonal pyramidal molecular geometry. Both are correct answers — to different questions.

Bonding pairsLone pairsTotal domainsDomain geometryMolecular geometryBond angle
202linearlinear180°
303trigonal planartrigonal planar120°
213trigonal planarbentabout 118°
404tetrahedraltetrahedral109.5°
314tetrahedraltrigonal pyramidal107°
224tetrahedralbent104.5°

🧠 The IB has no single word for the bent shape

Past mark schemes have accepted bent, angular, non-linear and V-shaped. Pick one and stick with it. What you must not write is “trigonal planar” for SO2 or “tetrahedral” for water — those are the domain geometries, not the shapes.

Higher level: expanded octets

Period 3 atoms can hold more than eight electrons, which unlocks five and six domain shapes. The counting method does not change at all.

Bonding pairsLone pairsDomain geometryMolecular geometryExample
50trigonal bipyramidaltrigonal bipyramidalPCl5
41trigonal bipyramidalseesawSF4
32trigonal bipyramidalT-shapedClF3
23trigonal bipyramidallinearI3−
60octahedraloctahedralSF6
51octahedralsquare pyramidalBrF5
42octahedralsquare planarXeF4
Where do the lone pairs go? In a trigonal bipyramid they always take the equatorial positions (the three round the middle), because there is more room there. In an octahedron two lone pairs go opposite each other, which is why XeF4 ends up flat and square.

Worked examples

WE 1

Predict the shape and bond angle of NH3 [3]

Step 1: Lewis formula N has 5 valence electrons + 3 from H = 8. Three N–H bonds use 6, leaving 1 lone pair. Step 2: count domains 3 bonding + 1 lone = 4 domains → tetrahedral domain geometry Step 3: name the shape and adjust the angle Ignore the lone pair when naming, but it repels more strongly, so the angle closes from 109.5°. Trigonal pyramidal, about 107° say “because the lone pair repels more than the bonding pairs” for the third mark
WE 2

Deduce the shape of SO2, which contains a double bond

Step 1: Lewis formula S has 6 valence electrons, two O attached. One S=O double bond, one S–O bond and 1 lone pair on S. Step 2: count domains — carefully The double bond is one domain, not two. 2 bonding domains + 1 lone pair = 3 domains Step 3: geometry then shape Three domains → trigonal planar arrangement. One is a lone pair, so the shape is bent. Bent, about 118° sulfur ends up with 10 electrons here — a legitimate expanded octet
WE 3

State the electron domain geometry and molecular geometry of XeF4

Step 1: count valence electrons Xe: 8 + (4 × 7) = 36 electrons Step 2: bonds and lone pairs Four Xe–F bonds use 8. Each F takes 3 lone pairs = 24. 36 − 8 − 24 = 4 electrons = 2 lone pairs on Xe Step 3: total the domains 4 bonding + 2 lone = 6 domains → octahedral Step 4: place the lone pairs opposite each other That leaves the four fluorines in a flat square. Octahedral domains, square planar molecule two answers required — do not give just one

💡 Exam tips

⚠ Common mix-ups

Up next: Bond Polarity — now that you can work out where the atoms sit, you can start asking whether the electrons in each bond are shared fairly.

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