IB Chemistry SL Topic 2 — Covalent Bonding Paper 1 & 2 Core skill ~9 min read

Molecular Polarity

A molecule can be stuffed with polar bonds and still be completely nonpolar. Whether the whole molecule is polar depends on two things: how polar the bonds are, and how they are arranged in space. This is where bond polarity and molecular shape finally meet.

📚 What you need to know

Think of it as a tug of war

Each polar bond pulls electron density in a particular direction. Those pulls are vectors — they have a size and a direction — so they can add together or cancel each other out.

Imagine four people pulling on ropes tied to a ring. If they pull equally hard in opposite directions, the ring doesn’t move. If one of them lets go, or one pulls harder, the ring shifts. Molecules work the same way.

Case 1: no polar bonds at all

If both atoms in every bond are the same element, there are no dipoles to begin with, so there is nothing to add up. H2, Cl2, O2 and N2 are all nonpolar. Simple.

Case 2: polar bonds that cancel

This is the case students get wrong. CO2 has two very polar C=O bonds — oxygen is much more electronegative than carbon. But the molecule is linear, so the two pulls point in exactly opposite directions and cancel perfectly. The result is a nonpolar molecule made of polar bonds.

Compare that with water. The O–H bonds are polar in the same way, but water is bent. The two pulls are both angled upwards towards the oxygen, so instead of cancelling they reinforce each other and give one overall dipole.

CO₂ — DIPOLES CANCELH₂O — DIPOLES ADD UPCOOδ+δ−δ−equal pulls in opposite directionsNO NET DIPOLE → NONPOLAROHHδ+δ+δ−the shape is bent, so they do not cancelNET DIPOLE → POLARδ−δ+net dipole
Same kind of polar bond in both, but the linear shape cancels the dipoles and the bent shape does not.
Same bond type, completely different answer — and the only thing that changed was the shape. That is why you should never try to judge polarity from the formula alone.

Symmetry is the deciding factor

The shortcut is to look for symmetry. A molecule is nonpolar when the polar bonds are spread out evenly around the central atom, so that every pull has an equal and opposite partner.

Two conditions have to be met for the dipoles to cancel:

CCl4 passes both tests: four identical Cl atoms in a perfect tetrahedron, no lone pairs. Nonpolar. CH3Cl fails the first test — three H atoms and one Cl — so the strong C–Cl pull has nothing to balance it.

CCl₄ — SYMMETRICALCH₃Cl — NOT SYMMETRICALCClClClClfour identical pulls, evenly spreadTHEY CANCEL → NONPOLARCClδ−HHHone strong C–Cl pull, nothing to cancel itNET DIPOLE → POLARδ−δ+net dipole
Replacing just one chlorine with a hydrogen destroys the symmetry and turns a nonpolar molecule into a polar one.

And here is the lone pair effect on its own. BF3 and NH3 both have three bonds to a central atom, but BF3 is flat with no lone pair while NH3 is pyramidal because of one:

BF₃ — FLAT AND SYMMETRICALNH₃ — PYRAMIDALBFFFthree equal pulls at 120° cancel exactlyNONPOLARNHHHthe lone pair breaks the symmetryPOLARδ−δ+net dipole
The lone pair on nitrogen means there is no bond dipole pointing upwards to balance the three pointing down.

🧩 Is this molecule polar? Four steps

  1. Draw the Lewis formula and work out the shape using VSEPR.
  2. Check the bonds. Are the atoms different elements? If every bond is between identical atoms, stop — it’s nonpolar.
  3. Draw the dipole arrows, one per polar bond, pointing towards the more electronegative atom.
  4. Add them up. Do they cancel? Symmetrical with identical outer atoms and no lone pairs → nonpolar. Anything else → polar.
MoleculeShapePolar bonds?Do they cancel?Molecule
Cl2linearNoNonpolar
CO2linearYesYes, symmetricalNonpolar
BF3trigonal planarYesYes, symmetricalNonpolar
CCl4tetrahedralYesYes, symmetricalNonpolar
H2ObentYesNo — lone pairsPolar
NH3trigonal pyramidalYesNo — lone pairPolar
CH3CltetrahedralYesNo — different atomsPolar
WORKED EXAMPLE

CCl4 and CHCl3 both contain polar C–Cl bonds. Explain why one is polar and the other is not.

Both are tetrahedral with four bonding pairs and no lone pairs CCl₄: all four outer atoms are identical Four equal dipoles spread evenly cancel exactly. CCl₄ is nonpolar CHCl₃: one Cl has been swapped for an H The C–H bond is barely polar, so the three C–Cl pulls are no longer balanced. CHCl₃ is polar
WORKED EXAMPLE

Deduce whether SO2 is polar.

Step 1 — shape: 2 bonding domains + 1 lone pair → bent Step 2 — bonds: O (3.4) is more electronegative than S (2.6), so S=O is polar Step 3 — the bent shape means both dipoles point the same general way SO₂ is polar CO₂ and SO₂ look similar on paper but behave completely differently — because of that one lone pair.

💡 Exam tip

⚠️ Common mix-up

Up next: Giant Covalent Structures — what happens when covalent bonding doesn’t stop at a molecule but carries on through an entire crystal.

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