Topic B.5 — Current & Circuits Paper 1 & 2 V = W / q ~6 min read

Electric Potential Difference

Okay, let’s slow down and build this one up together. We already know current is charge on the move — but what actually pushes it around the circuit? That’s the job of potential difference, also called voltage. Grab a cup of tea, and let’s work through it step by step.

📘 What You Need to Know

Let’s start with an everyday picture

Imagine you’re pushing a trolley up a small hill so it can roll back down again. To get it to the top, you have to do work on it — you’re giving it energy. Once it’s at the top, it has the potential to roll all the way back down, giving up that energy as it goes (maybe as heat from the wheels, or noise, or warming the ground).

A cell does exactly this, but to charge instead of a trolley. Inside the cell, chemical reactions do work on the charge and “lift” it to a higher electrical potential. As that charge then travels round the circuit and through components like resistors and lamps, it gives that energy back up again — mostly as heat and light. By the time it gets back to the negative terminal, it has “rolled all the way down” and is ready to be lifted again.

high potential low potential cell lifts the charge charge rolls through the resistor CELL RESISTOR
Think of the cell as “lifting” charge up to a high potential. As the charge passes through a component like a resistor, it gives that energy up again and drops back down.

Turning that idea into a formula

So potential difference is really just: how much energy did each little bit of charge gain (or lose)? We write it like this:

Potential difference V = W / q

Here, V is the potential difference in volts (V), W is the work done — or energy transferred — in joules (J), and q is the charge in coulombs (C). So a p.d. of 6 V simply means every coulomb of charge that passes through gets 6 joules of energy. Bigger voltage, bigger “push” of energy per bit of charge.

This also gives us a nice, simple way to think about the unit itself: 1 volt is just 1 joule per coulomb. If someone tells you a battery is “9 volts”, they’re really telling you it gives 9 joules of energy to every coulomb of charge that flows through it.

How do we actually measure it?

We use a voltmeter. But here’s the important bit — a voltmeter doesn’t sit “in the road” of the current like an ammeter does. Instead, it sits off to the side, connected across the two ends of the component you’re interested in, like it’s comparing the potential at one end with the potential at the other.

+ RESISTOR V CELL
The voltmeter branches off and reconnects on either side of the resistor — it’s “comparing” the potential just before and just after the component.
Quick recap: V = W/q, 1 V = 1 J per C, the cell lifts charge to a higher potential, and a voltmeter (parallel connection) compares the potential either side of a component.
WE 1

Moving 4.0 C of charge through a light bulb transfers 18 J of energy to it. What is the potential difference across the bulb?

Start with the formula: V = W / q Plug in the numbers: V = 18 ÷ 4.0 V = 4.5 V Every coulomb passing through this bulb gives up 4.5 J of energy.

A little extra: the electronvolt

Here’s something neat. Electrons are tiny, so the energy they gain moving through a p.d. is a very small number of joules — awkward to write out every time. Physicists invented a friendlier unit for this: the electronvolt (eV), which is just the energy gained by a single electron moving through a p.d. of 1 volt.

WE 2

How much energy, in joules, does one electron gain moving through a potential difference of 12 V?

Use W = qV: Here, q is the charge on one electron: 1.6 × 10⁻¹⁹ C W = (1.6 × 10⁻¹⁹) × 12 W = 1.92 × 10⁻¹⁸ J Or, more simply, we’d just say the electron gained 12 eV.

💡 Top Tips

⚠ Common Mistakes

Up next: Electrical Conductors & Insulators — now we know what pushes charge around, let’s look at which materials actually let it flow.

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