IB Maths AA SL Paper 1 & 2 15 min read

Solving Quadratic Equations

A quadratic equation looks like ax2 + bx + c = 0. There are three reliable methods for solving it on a non-calculator paper — factorising, the quadratic formula, and completing the square — plus the GDC shortcut on Paper 2. The trick is picking the right method for each question.

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What you need to know

  • A quadratic equation must be in the form ax2 + bx + c = 0 before you can solve it
  • Factorising works when the quadratic factors with integers — fastest when it works
  • The quadratic formula always works — it’s in the formula booklet
  • Completing the square always works too — best when factoring fails or when the question asks for it
  • On calculator papers, the GDC solves any quadratic instantly
  • If b2 − 4ac < 0, the equation has no real solutions

Which Method Should I Use?

Pick the fastest tool for the job:

GDC

When: Calculator paper

Fastest. Just type in a, b, c and read the roots. Use this on Paper 2.

1

Factorising

When: Roots are nice

If you can factorise with integers, this is the fastest non-calculator method.

2

Quadratic Formula

When: Default fallback

Always works. Especially useful when factorising fails or roots are irrational.

3

Complete the Square

When: Asked, or for vertex info

Always works too. Best if the question asks, or if it gives vertex/min info too.

Method 1: Solving by Factorising

If you can factorise the quadratic into the form a(xp)(xq) = 0, then by the zero product rule, at least one of the factors must equal zero:

If (xp)(xq) = 0,   then   x = p   or   x = q
  1. Get the equation into the form ax2 + bx + c = 0 (right side equals 0).
  2. Factorise the left side.
  3. Set each factor equal to zero and solve.

Reminder of the sign flip: if the factor is (x − 3), the root is x = +3 (not −3). The root is the value that makes the bracket zero.

Method 2: The Quadratic Formula

The quadratic formula always works, no matter how ugly the numbers are. It’s given in the formula booklet:

Anatomy of the Quadratic Formula
x = b ± √(b2 − 4ac)2a
b   (red)

Negative of the x coefficient. Watch the sign carefully if b is itself negative.

±   (purple)

Gives you two solutions: one with +, one with −.

b2 − 4ac   (green)

The discriminant. If it’s negative, no real solutions. If 0, one repeated solution.

2a   (blue)

Twice the x2 coefficient. Sits as the denominator.

  1. Rearrange to ax2 + bx + c = 0.
  2. Identify a, b, c — including signs!
  3. Calculate the discriminant first: b2 − 4ac. This avoids sign mistakes.
  4. Substitute into the formula and simplify.

Examiner trick: when the values are awkward, work out the discriminant b2 − 4ac on its own first. It cuts down on negative-sign errors and makes the rest easier.

Method 3: Solving by Completing the Square

Once the quadratic is in vertex form a(xh)2 + k = 0, you can solve it by isolating the squared bracket and taking square roots:

  1. Complete the square on the left side.
  2. Isolate the squared bracket: (xh)2 = −ka.
  3. If the right side is negative, there are no real solutions.
  4. Otherwise, take ± square root of both sides.
  5. Solve for x:   x = h ± √(−k/a).

Don’t forget the ±! Taking the square root of both sides gives two answers — a positive and a negative. Forgetting the minus loses you half the solutions.

Worked Examples

Example 1 — Solve by factorising (monic)

Solve x2 − 5x + 6 = 0.

Answer:

Step 1: factorise. Find p, q with p+q = −5, p×q = 6. p = −2, q = −3 (x − 2)(x − 3) = 0 Step 2: set each factor to zero. x − 2 = 0 → x = 2 x − 3 = 0 → x = 3 x = 2 or x = 3

Example 2 — Solve by factorising (non-monic)

Solve 4x2 + 4x − 15 = 0.

Answer:

Step 1: factorise (covered in Factorising Quadratics). (2x + 5)(2x − 3) = 0 Step 2: set each factor to zero. 2x + 5 = 0 → 2x = −5 → x = −5/2 2x − 3 = 0 → 2x = 3 → x = 3/2 x = −5/2 or x = 3/2

Example 3 — Quadratic formula (rearrange first)

Solve 7 − 3x − 5x2 = 0.

Answer:

Step 1: identify a, b, c carefully. a = −5, b = −3, c = 7 Step 2: discriminant first. b² − 4ac = (−3)² − 4(−5)(7) = 9 + 140 = 149 Step 3: substitute into the formula. x = (−(−3) ± √149) / (2 × −5) x = (3 ± √149) / (−10) x = (3 ± √149) / (−10) Or equivalently: x = −(3 ± √149) / 10. Both forms are accepted.

Example 4 — Quadratic formula (clean numbers)

Solve 2x2 − 7x + 3 = 0 using the quadratic formula.

Answer:

Step 1: identify a, b, c. a = 2, b = −7, c = 3 Step 2: discriminant. b² − 4ac = 49 − 24 = 25 Step 3: substitute. x = (7 ± √25) / 4 x = (7 ± 5) / 4 Step 4: split into the two solutions. x = (7 + 5) / 4 = 12/4 = 3 x = (7 − 5) / 4 = 2/4 = 1/2 x = 3 or x = 1/2 Check: this could have been factorised as (2x − 1)(x − 3) = 0.

Example 5 — Solve by completing the square

Solve 3x2 + 12x − 5 = 0 by completing the square.

Answer:

Step 1: complete the square (covered in Completing the Square). 3(x + 2)² − 17 = 0 Step 2: isolate the squared bracket. 3(x + 2)² = 17 (x + 2)² = 17/3 Step 3: take ± square root. x + 2 = ± √(17/3) Step 4: solve for x. x = −2 ± √(17/3) Don’t forget the ± — that gives both solutions.
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Tips

  • Try factorising first — if it works in 5 seconds, great. If not, move to the formula.
  • Compute the discriminant alone first when using the quadratic formula. It’s easier to spot sign errors when the calculation is small.
  • Always make right side equal to zero. 2x2 = x + 6 must become 2x2x − 6 = 0 before you can solve.
  • Check your answer by plugging it back into the original equation. Quick and catches careless mistakes.
  • If the discriminant is negative, stop and write “no real solutions” — don’t waste time trying to compute square roots of negatives.

Common mistakes

  • Sign errors with negative b. If b = −3, then −b = +3, not −3. The minus inside the formula flips the sign of b.
  • Forgetting the ±. Both the quadratic formula and completing-the-square need both solutions. Skipping one loses half the marks.
  • Forgetting to set the equation to zero first. The quadratic formula only works on ax2 + bx + c = 0 form.
  • Reading the sign of a, b, c wrong. In −5x2 + 3x − 7, a = −5, b = 3, c = −7. Carry the negative signs over.
  • Confusing factor with root. Factor (x − 3) means root x = +3. The sign flips.
  • Stopping at (xh)2 = number. You still need to take the square root and add h to finish.

Final word: Three methods that always work, and one shortcut (the GDC). Pick the easiest for the question you’ve got — and watch the signs like a hawk.

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