IB Maths AA SL Topic 3 — Geometry & Trig Paper 1 & 2 ~10 min read

Pythagoras & Right-Angled Trigonometry

If a triangle has a right angle, you’ve got two huge tools at your disposal: Pythagoras’ theorem for sides, and SOH CAH TOA for angles. Master both and you’ll handle any right-angled triangle problem in seconds.

📘 What you need to know

Pythagoras’ Theorem

The most famous result in geometry: in a right-angled triangle, the square of the hypotenuse equals the sum of the squares of the other two sides. This works for any right-angled triangle — full stop.

Pythagoras’ Theorem a2 + b2 = c2
A right-angled triangle
a (base) b (height) c (hypotenuse) vertex opposite the right angle
The hypotenuse is always the longest side — it’s the one opposite the right angle. Identify it first; everything else depends on knowing which side is c.

Finding a missing side

If you know two sides of a right-angled triangle, you can always find the third using Pythagoras. Just rearrange the formula based on what you’re solving for:

Solving for any side Hypotenuse: c = √(a2 + b2)
Shorter side: a = √(c2b2)
If you’re finding the hypotenuse, you’re adding the squares. If you’re finding a shorter side, you’re subtracting. The longest side is always the biggest, so when you subtract you take the smaller from the bigger.

Right-Angled Trigonometry — SOH CAH TOA

Pythagoras only relates sides. To bring angles into the picture, use trigonometry. There are three trig ratios you need: sine, cosine, and tangent — each of which connects an angle to two specific sides.

Step 1: Label the sides relative to your angle

Pick the angle you care about (call it θ). Now label the three sides:

H
Hypotenuse
Longest side, opposite the right angle
O
Opposite
The side opposite the angle θ
A
Adjacent
The side next to θ (not the hypotenuse)
Labelling sides relative to angle θ
θ A — adjacent O — opposite H — hypotenuse
The hypotenuse never changes regardless of which angle you pick — it’s always opposite the right angle. But “opposite” and “adjacent” depend on which angle you’ve chosen. If you switch to the other (non-right) angle, opp and adj swap.

Step 2: Use SOH CAH TOA

SOH
sin θ = OH
Sine = Opposite over Hypotenuse
CAH
cos θ = AH
Cosine = Adjacent over Hypotenuse
TOA
tan θ = OA
Tangent = Opposite over Adjacent

🧠 Memory hooks for SOH CAH TOA

“Some Old Hippie / Caught Another Hippie / Tripping On Acid” — silly but it sticks. Or pick whichever phrase makes you remember S-O-H, C-A-H, T-O-A.

Side or angle? — pick the right tool

Two routes through every right-angled trig question. Look at what you’re given and what you’re finding:

🔍 Finding a SIDE?

You’ll have an angle + one side. Pick the trig ratio that matches the two sides you have/want.

Rearrange and solve directly:

side = sin θ × H  or  Osin θ

🔍 Finding an ANGLE?

You’ll have two sides. Pick the trig ratio that matches them, then use inverse trig.

Apply sin⁻¹, cos⁻¹, or tan⁻¹:

θ = sin⁻¹(OH)  etc.
The 3-step method: (1) label the sides relative to your angle, (2) tick which two sides you have or want — that tells you S, C, or T, (3) substitute and solve.

Angles of elevation and depression

Both are measured from the horizontal. Looking up at something gives you an angle of elevation. Looking down gives you an angle of depression. They appear in word problems about towers, planes, ships — anywhere you’ve got a “height + distance” setup.

Elevation vs depression
ground 📦 target up elevation horizontal 📦 target down depression observer observer

🤔 The angles are equal across the line of sight

If you’re standing on the ground and your friend is on a roof, the angle of elevation from you up to them equals the angle of depression from them down to you. They’re alternate angles between two parallel horizontal lines. Useful when a question gives you one and asks for the other.

Worked examples

WE 1

Pythagoras — find the hypotenuse

A right-angled triangle has shorter sides of 5 cm and 12 cm. Find the length of the hypotenuse.

Step 1: Apply Pythagoras c2 = 52 + 122 Step 2: Compute = 25 + 144 = 169 Step 3: Take the square root c = √169 = 13 cm classic 5-12-13 triangle — worth memorising!
WE 2

Pythagoras — find a shorter side

A right-angled triangle has hypotenuse 17 cm and one shorter side of 8 cm. Find the other shorter side.

Step 1: Rearrange Pythagoras b2 = c2a2 Step 2: Substitute c = 17, a = 8 b2 = 172 − 82 = 289 − 64 = 225 Step 3: Square root b = √225 = 15 cm 8-15-17 is another classic Pythagorean triple
WE 3

Trig — find a side using cosine

A right-angled triangle has hypotenuse 10 cm and one of its angles is 35°. Find the length of the side adjacent to the 35° angle.

Step 1: Label the sides Hypotenuse = 10, want the adjacent side. Step 2: Pick the right ratio Adjacent + Hypotenuse → use cosine (CAH). Step 3: Set up and solve cos 35° = A10 A = 10 × cos 35° = 10 × 0.8192… A ≈ 8.19 cm (3 s.f.) make sure your calculator is in DEG mode!
WE 4

Inverse trig — find an angle

A right-angled triangle has its opposite side = 7 cm and hypotenuse = 12 cm. Find the angle θ.

Step 1: Identify the sides Have Opposite (7) and Hypotenuse (12), finding angle θ. Step 2: Use SOH (since O and H) sin θ = 712 Step 3: Apply inverse sine θ = sin⁻¹(712) = sin⁻¹(0.5833…) θ ≈ 35.7° (3 s.f.) finding angles → always use inverse trig (sin⁻¹, cos⁻¹, tan⁻¹)
WE 5

Angle of elevation (real-world)

From a point on horizontal ground, the angle of elevation to the top of a tower is 28°. The point is 50 m from the base of the tower. Find the height of the tower to 3 s.f.

Step 1: Sketch + label 28° angle, 50 m adjacent (horizontal), height = opposite Step 2: Pick the ratio Have A = 50, want Ouse TAN (TOA). Step 3: Set up and solve tan 28° = O50 O = 50 × tan 28° = 50 × 0.5317… Height ≈ 26.6 m (3 s.f.) always sketch the situation first — even a rough triangle helps

💡 Top tips

⚠ Common mistakes

Right-angled trig is the foundation for everything trigonometric you’ll meet in IB. Get fluent with SOH CAH TOA and the rest of trig — sine rule, cosine rule, identities — comes much more easily.

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