IB Maths AA SL Topic 4 — Probability Paper 1 & 2 ~10 min read

Probability & Types of Events

Probability is the maths of chance — what’s the likelihood that something will happen? This note covers all the basic vocabulary and rules: outcomes, events, the probability formula, and how to combine events using AND and OR.

📘 What you need to know

The vocabulary you’ll meet

Probability has a few specific words you need to know. They sound technical, but they’re really just everyday concepts:

Experiment

Any repeatable activity with a result you can record.
e.g. rolling a dice, flipping a coin

Trial

One single repeat of the experiment.
e.g. one roll of the dice

Outcome

A possible result of one trial.
e.g. rolling a 4

Event

An outcome OR a collection of outcomes. Usually denoted by capital letters (A, B).
e.g. “rolling an odd number” = {1, 3, 5}

Sample space (U)

The set of all possible outcomes of an experiment.
e.g. {1, 2, 3, 4, 5, 6} for a dice

n(A) and n(U)

n(A) = number of outcomes in event A.   n(U) = total number of outcomes.
e.g. for “odd dice”: n(A) = 3, n(U) = 6

The basic probability formula

If every outcome is equally likely (a fair dice, an unbiased coin), the probability of an event is just:

Theoretical probability
P(A) = n(A)n(U) = favourable outcomestotal outcomes

This formula is in your formula booklet. As long as the outcomes are equally likely, it always works. To use it: count how many outcomes count as the event you care about, count the total, divide.

The probability scale

All probabilities live between 0 and 1
0
0.25
0.5
0.75
1
impossible
even chance
certain
If you ever calculate a probability above 1 or below 0, you’ve made a mistake!

Theoretical vs experimental probability

For a fair coin, theoretical P(heads) = 0.5. But if you flip it 10 times and get 7 heads, the experimental probability is 0.7. Run more and more trials and the experimental probability gets closer to 0.5 — that’s the “law of large numbers”.

Expected number of occurrences

If the probability of an outcome is p, and you repeat the experiment n times, you expect it to occur:

Expected occurrences
Expected number = n × p

Example: If you roll a dice 60 times, the expected number of 6’s is 60 × 16 = 10.

📍

“Expected” doesn’t mean “guaranteed”

If you roll a dice 60 times you might get 8 sixes, or 13, or 7 — not exactly 10. But on average, over many sets of 60 rolls, you’d expect 10 sixes. The expected value is a long-run average, not a promise.

The complement of an event

The complement of event A is “everything except A” — the event that A doesn’t happen. We write it as A‘.

The complement formula
P(A) + P(A‘) = 1   ⟹   P(A‘) = 1 − P(A)

Example: If P(“rolling a 6”) = 16, then P(“not rolling a 6”) = 1 − 16 = 56.

🧠

Memory trick: “1 minus the easy one”

If finding “A” is hard but finding “not A” is easy, calculate the easy one and subtract from 1. This is a powerful exam shortcut — especially for “at least one” questions.

Combining events — AND, OR, NOT

When you have two events A and B, you can combine them in different ways:

A’ — complement

A
“NOT A — event A does not happen.
e.g. NOT rolling a 6 → {1,2,3,4,5}

A ∩ B — intersection

AB
A AND B — both events happen.
e.g. rolling an even number AND a multiple of 3 → just {6}

A ∪ B — union

AB
A OR B (or both)” — at least one happens.
e.g. rolling an even number OR a multiple of 3 → {2,3,4,6}

A | B — conditional

A | B
A GIVEN B — probability of A happening given that B already happened.
covered in detail in the conditional probability note
🧠

Memory trick: “U for Union, like a U-shape holding both”

The union symbol ∪ looks like a cup — it holds both circles. The intersection symbol ∩ looks like a bridge — it’s only the bit where they overlap. AND = overlap = ∩. OR (or both) = full cup = ∪.

Formulas for combined events

The OR formula (union)

Probability of A or B (or both)
P(AB) = P(A) + P(B) − P(AB)

🤔 Why subtract P(A ∩ B)?

If you just added P(A) + P(B), you’d be counting the overlap twice — once in P(A) and once in P(B). Subtracting P(AB) once removes the duplicate.

Imagine 60% of students play football and 30% play tennis. If 20% play both, then the percentage who play at least one is 60 + 30 − 20 = 70% (not 90%).

The AND formula (intersection)

Probability of A and B both happening
P(AB) = P(A) × P(B | A)

In words: “probability of A, multiplied by the probability of B happening given that A has happened”. The conditional bit P(B|A) handles the case where the events affect each other (covered fully in the conditional probability note).

📍

Quick test for spotting which formula to use

Look at the wording:
A AND B” or “both” or “and then” → use the intersection formula (P(A) × P(B|A)).
A OR B” or “at least one” or “either” → use the union formula.

Worked examples

WE 1

List outcomes and find probabilities

Dave has two fair spinners. Spinner A has three sides numbered 1, 4, 9 and Spinner B has four sides numbered 2, 3, 5, 7. Dave spins both and forms a two-digit number using A for the first digit and B for the second digit.

Let T be the event that the two-digit number is a multiple of 3.

(a) List all possible two-digit numbers.   (b) Find P(T).   (c) Find P(T‘).

Use a 2-way table to list all outcomes systematically.part (a) — list outcomes First digit (A): 1, 4, 9. Second digit (B): 2, 3, 5, 7. 3 × 4 = 12 possible two-digit numbers. 2 3 5 7 1 4 9 12 15 15 17 42 43 45 47 92 93 95 97 Outcomes: 12, 13, 15, 17, 42, 43, 45, 47, 92, 93, 95, 97part (b) — find p(t) Find which numbers are multiples of 3: 12, 15, 42, 45, 93 → 5 multiples of 3 Use formula: P(T) = n(T)n(U) = 512 P(T) = 512part (c) — find p(t’) Use complement: P(T’) = 1 − P(T) = 1 − 512 P(T’) = 712 a 2-way table is the safest way to list all outcomes — fewer mistakes!
WE 2

Use the OR formula

In a class, P(plays football) = 0.6, P(plays tennis) = 0.3, and P(plays both) = 0.2. Find the probability that a student picked at random plays football or tennis (or both).

“OR (or both)” → use the union formula. Use: P(F ∪ T) = P(F) + P(T) − P(F ∩ T) P(F ∪ T) = 0.6 + 0.3 − 0.2 P(F ∪ T) = 0.7 P(F ∪ T) = 0.7 don’t forget to subtract the overlap — otherwise you’d count it twice!
WE 3

Find the expected number of occurrences

A spinner has 5 equal sectors, one of which is red. The spinner is spun 200 times.

(a) Find the probability of getting red on a single spin.   (b) Find the expected number of red sectors in 200 spins.

Equally likely sectors → use n(A)/n(U). Expected = np.part (a) 1 red out of 5 sectors: P(red) = 15 = 0.2 P(red) = 0.2part (b) Use np with n = 200, p = 0.2: 200 × 0.2 = 40 Expected = 40 reds “expected” is a long-run average — won’t be exact every time
WE 4

Use the complement for “at least one”

A coin is flipped 3 times. Find the probability of getting at least one head.

“At least one head” is hard to count directly — but its complement (no heads at all) is easy. Complement: “no heads” = “all tails” P(all 3 tails): 0.5 × 0.5 × 0.5 = 18 Use complement: P(at least 1 head) = 1 − 18 = 78 P(at least 1 head) = 78 “at least one” is almost always solved by the complement trick
WE 5

Use the AND formula

A bag contains 5 red balls and 7 blue balls. Two balls are drawn without replacement. Find the probability that both balls are red.

“Both red” = R₁ AND R₂ → use the intersection formula. P(first red): 512 After drawing 1 red, 4 reds left out of 11 balls. P(second red | first red): 411 Multiply: P(both red) = 512 × 411 = 20132 = 533 P(both red) = 533 “without replacement” → second probability changes — that’s why we use P(B|A)

💡 Top tips

⚠ Common mistakes

You’ve got the foundations now. The next note covers independent and mutually exclusive events — two special types of events that simplify the formulas above. After that, things get even more interesting with conditional probability, Venn diagrams, and tree diagrams.

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