IB Maths AA HL Topic 1 — Number & Algebra Paper 1 & 2 ~8 min read

Laws of Indices

“Indices” is just IB-speak for “powers” or “exponents”. The laws below sit underneath nearly every algebraic simplification you’ll meet — from solving exponential equations, to differentiating, to handling logs. None of them are in the formula booklet, so they have to live in your head. Don’t worry though — the rules are short, and once you spot the pattern, the rest follows automatically.

📘 What you need to know

The five core rules

If you only memorise five things from this whole topic, make it these. They show up in every paper.

Rule
In plain English
Quick example
am × an = am+n
Same base, multiplying — add the powers.
52 × 54 = 56
am ÷ an = amn
Same base, dividing — subtract the powers.
97 ÷ 93 = 94
(am)n = amn
Power of a power — multiply the powers.
(32)4 = 38
a0 = 1
Anything (non-zero) raised to the power 0 equals 1.
170 = 1
a1 = a
Anything raised to the power 1 is itself.
61 = 6

🤔 Why is anything to the power 0 equal to 1?

It falls out of the divide-rule. Take 53 ÷ 53. By cancellation, that’s 1. By the rule, it’s 53−3 = 50. So 50 must equal 1. Same logic works for any non-zero base.

Distributing across products and fractions

When the thing inside the bracket is a product or a quotient, the power applies to each piece.

Rule
In plain English
Quick example
(ab)n = anbn
A product to a power — apply the power to each factor.
(2 × 7)2 = 22 × 72
(ab)n = anbn
A fraction to a power — apply the power to top and bottom.
(52)2 = 254
These rules do not work for sums. (a + b)2 is not a2 + b2. That’s the most expensive mistake at SL/HL — easily caught by trying numbers: (3 + 4)2 = 49, but 32 + 42 = 25.

Negative powers — flip into a fraction

A negative power means “take the reciprocal”. That’s it.

Negative power an = 1an ✗ not in the formula booklet
Quick examples:   4−1 = 14  |  2−3 = 18  |  x−5 = 1x5

For a fraction with a negative power, the same idea gives a clean shortcut: flip the fraction and make the power positive.

Fraction with negative power — flip (ab)n = (ba)n

For instance, (35)−2 = (53)2 = 259.

Fractional powers — they’re just roots

The power 1n means “take the nth root”.

Unit fractional power a1/n = na
Quick examples:   491/2 = √49 = 7  |  1251/3 = 3√125 = 5  |  811/4 = 4√81 = 3

The general fractional power: am/n

If the fraction has a numerator that isn’t 1, the power splits into a root and a power — and you can do them in either order.

General fractional power am/n = (na)m = n√(am)
Two routes to evaluate 163/4
163/4 root first (⁴√16)³ = 2³ = 8 power first ⁴√(16³) = ⁴√4096 = 8
Always take the root first when the numbers are friendly. ⁴√16 = 2 is fast; 163 = 4096 is a calculator job. Same answer, much less arithmetic.

Changing the base

The laws above all need matching bases. When they don’t match, the trick is to rewrite one (or both) as a power of a common base.

🧭 Recipe — change of base

  1. Spot a common base. Often everything in the question is a power of 2, 3, or 5.
  2. Rewrite each term using that base. e.g. 8 = 23, 27 = 33, 125 = 53.
  3. Apply the index laws. With matching bases, simplification is straightforward.
  4. For equations, once both sides have the same base, the powers must be equal — set them equal and solve.
Worked through: 32 × 82  =  25 × (23)2  =  25 × 26  =  211.

Worked examples

WE 1

Numerical simplification — multiple laws

Simplify 75 × 7−2 ÷ 70, leaving your answer as a power of 7.

Step 1: Apply the multiplication rule 75 × 7−2 = 75+(−2) = 73 Step 2: Apply the division rule (and remember 70 = 1) 73 ÷ 70 = 73−0 = 73 = 73 = 343
WE 2

Evaluate a fractional power without a calculator

Evaluate 322/5.

Step 1: Take the 5th root first (the friendlier route) 321/5 = 5√32 = 2 Step 2: Now apply the power 2 322/5 = (321/5)2 = 22 = 4 root-first beats power-first here — 32² = 1024 is a calculator detour
WE 3

Negative and fractional power together

Evaluate 64−1/3, giving your answer as a fraction.

Step 1: Negative power → reciprocal 64−1/3 = 1641/3 Step 2: Fractional power → cube root 641/3 = 3√64 = 4 = 14 handle the sign of the power first, then the size
WE 4

Algebraic simplification

Simplify (2x4y)38x5y2, giving your answer with positive indices only.

Step 1: Expand the numerator using (ab)n = anbn (2x4y)3 = 23x12y3 = 8x12y3 Step 2: Divide by the denominator = 8x12y38x5y2 = x12−5 y3−2 = x7 y
WE 5

Algebraic — finish with positive indices

Simplify (3x−2y4)2 × (x3y)−1, giving your answer with positive indices only.

Step 1: Distribute the outer powers (3x−2y4)2 = 9x−4y8 (x3y)−1 = x−3y−1 Step 2: Multiply — same base, add powers = 9 × x−4+(−3) × y8+(−1) = 9x−7y7 Step 3: Rewrite negative powers as fractions = 9y7x7
WE 6

Solve an equation by changing the base

Solve 4x = 8 for x.

Step 1: Both sides are powers of 2 4 = 22,   8 = 23 Step 2: Rewrite the equation (22)x = 23 22x = 23 Step 3: Same base — equate the powers 2x = 3 x = 32 no logs needed — change of base does the whole job

💡 Top tips

⚠ Common mistakes

Index laws are the bedrock of nearly everything in algebra and calculus — exponential/log questions, polynomial differentiation, integration of xn, even basic equation solving. The earlier you get fluent, the easier later topics become.

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