IB Maths AA HL
Topic 3 — Geometry & Trigonometry
Paper 1 & 2
~5 min read
HL only
Adding & Subtracting Vectors
Add corresponding components — that’s all there is to it. The sum is called the resultant. Geometrically, place vectors nose-to-tail and the resultant goes from start to finish. Subtraction is just adding the reverse: a − b = a + (−b).
📘 What you need to know
- Add componentwise: (a₁, a₂, a₃) + (b₁, b₂, b₃) = (a₁ + b₁, a₂ + b₂, a₃ + b₃).
- Subtract componentwise: same idea, just minus signs. Or treat it as a − b = a + (−b).
- The result is called the resultant, and it’s a vector.
- Base vector form: collect like terms — the i‘s, the j‘s, the k‘s — separately.
- Mix forms? Convert both to the same form first, then operate.
- Geometric meaning: nose-to-tail addition. a + b goes from start of a to end of b.
- Same start point? a + b is the diagonal of the parallelogram they form.
The component rule
Component-wise addition & subtraction
a ± b = (a₁ ± b₁, a₂ ± b₂, a₃ ± b₃)
In base vector form, that means collecting i, j, and k terms separately.
(3i − 2j + 5k) + (i + 4j − k) = 4i + 2j + 4k
If a term is missing from a base form vector, treat it as 0. i − 4k means the j coefficient is 0 — handy for clean addition.
The geometric picture
Addition (nose-to-tail)
a + b
place tail of b at head of a; resultant goes from start of a to end of b
Subtraction (reverse + add)
a − b = a + (−b)
flip b‘s direction, then add nose-to-tail
Two vectors with the same start? Their sum is the diagonal of the parallelogram they form. Their difference (a − b) is the vector from the head of b to the head of a.
🧭 Recipe — add or subtract two vectors
- Write both in the same form (column or base vector).
- Fill in zeros for any missing components.
- Operate on each component separately (top with top, middle with middle, bottom with bottom).
- Watch the signs — subtraction flips every component of the second vector.
- Convert back to the form the question asks for.
Worked examples
WE 1Add two column vectors
Given u = 4−31 and v = 25−7, find u + v.
Add corresponding components
x: 4 + 2 = 6
y: −3 + 5 = 2
z: 1 + (−7) = −6
u + v = 62−6
WE 2Subtract two column vectors
Given p = −148 and q = 3−25, find p − q.
Subtract corresponding components
x: −1 − 3 = −4
y: 4 − (−2) = 4 + 2 = 6
z: 8 − 5 = 3
p − q = −463
subtracting a negative becomes addition — easy place to drop a sign
WE 3Subtract base vectors with a missing term
Given u = 6i + 4k and v = 5i − 3j + 2k, find u − v in base vector form.
Step 1: Fill in the missing j term in u (coefficient 0)
u = 6i + 0j + 4k
Step 2: Subtract like terms
i: 6 − 5 = 1
j: 0 − (−3) = 3
k: 4 − 2 = 2
u − v = i + 3j + 2k
WE 4Multi-step combination with scalars
Given a = (2, 1, −3), b = (−1, 4, 0), and c = (5, −2, 6), find 2a + b − c.
Step 1: Compute 2a (scalar multiplication first)
2a = (4, 2, −6)
Step 2: Add b
2a + b = (4 + (−1), 2 + 4, −6 + 0) = (3, 6, −6)
Step 3: Subtract c
(3 − 5, 6 − (−2), −6 − 6) = (−2, 8, −12)
2a + b − c = (−2, 8, −12)
do scalar multiples first, then add and subtract componentwise
WE 5Find unknown components from a known sum
Given a = (3, p, 5) and b = (−1, 4, q), and that a + b = (2, 7, −1), find the values of p and q.
Equate components of a + b with the given resultant
Step 1: x-check (no unknowns here)
3 + (−1) = 2 ✓
Step 2: y-component
p + 4 = 7 → p = 3
Step 3: z-component
5 + q = −1 → q = −6
p = 3, q = −6
WE 6Resultant velocity of boat in current
A boat sails at velocity v = 6i + 2j m/s in still water. A current pushes it with velocity w = −i + 3j m/s. Find the boat’s resultant velocity.
Step 1: Resultant velocity = v + w
v + w = (6i + 2j) + (−i + 3j)
Step 2: Collect like terms
i: 6 + (−1) = 5
j: 2 + 3 = 5
resultant velocity = 5i + 5j m/s
the resultant tells you the boat’s actual motion over the ground
💡 Top tips
- Convert to columns first for messy operations — it lines up the components and reduces errors.
- Insert zeros for missing terms before adding/subtracting in base form.
- Do scalar multiples first, then add/subtract.
- Treat the components like normal arithmetic — the algebra is independent across each axis.
- For geometric problems, drawing arrows nose-to-tail confirms the resultant before any algebra.
⚠ Common mistakes
- Mixing up components — always pair x with x, y with y, z with z. Lining up as columns prevents this.
- Sign errors with subtracting negatives: 4 − (−2) = 6, not 2.
- Forgetting missing terms in base form. i + 4k has a 0 j-coefficient.
- Doing the scalar multiple at the end instead of the start — apply it before combining.
- Treating a − b as b − a. Order matters when subtracting.
Next note: Position & Displacement Vectors. The position vector OA places a point relative to the origin, while displacement vectors AB = b − a link any two points — the bridge between coordinates and vectors.
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