IB Maths AI SL Topic 1 — Number & Algebra Paper 2 GDC essential ~6 min read

Solving Equations using a GDC

Your GDC can solve almost any equation — quadratics, cubics, exponentials, even messy ones with no algebraic solution. Three tools to know: polynomial root finder, numerical solver, and graph intersection. Pick the right one.

📘 What you need to know

Three GDC tools — which to use

Equation typeBest toolWhy
Polynomial = 0 (degree 2, 3, 4…)Polynomial Root FinderFinds all roots in one go.
Exponential, logarithmic, mixedGraph Intersection or Numerical SolverNot polynomial — root finder won’t accept it.
Simultaneous linear equationsLinear System SolverDirect — type in coefficients.
Anything weird with no algebraic formGraph IntersectionVisual — easy to spot all solutions.
Solving x² = 2^x by graph intersection −2 −1 0 1 2 3 4 5 x 5 10 15 20 y y = x² y = 2ˣ x ≈ −0.766 x = 2 x = 4
x² = 2ˣ has no neat algebraic solution — but the GDC finds three intersections easily. Always set a wide enough window to catch them all.

🧭 Recipe — solve any equation on the GDC

  1. Rearrange if helpful: get it into f(x) = 0 form (for solver/root finder), or leave both sides for graph intersection.
  2. Pick the tool: polynomial = 0 → Polynomial Root Finder. Anything else → Graph Intersection (safest, shows all roots).
  3. Set a sensible window: x and y wide enough to see all crossings. Zoom out if unsure.
  4. Use the GDC’s feature: “intersect”, “zero”, or “solve” — never just read off the graph by eye.
  5. Round to 3 s.f. on the final answer, unless GDC shows exact.

Worked examples

WE 1

Quadratic — Polynomial Root Finder

Solve x² − 7x + 10 = 0.

It’s a polynomial = 0 → use Polynomial Root Finder degree: 2 coefficients: a=1, b=−7, c=10 GDC returns both roots x = 2 or x = 5 exact integers — no rounding needed.
WE 2

Cubic — Polynomial Root Finder

Solve x³ − 6x² + 11x − 6 = 0.

Cubic = 0 → Polynomial Root Finder degree: 3 coefficients: 1, −6, 11, −6 GDC returns three roots x = 1, x = 2, x = 3 root finder handles higher degrees just as easily — type all coefficients in order.
WE 3

Exponential — Graph Intersection

Solve 2ˣ = 50, giving your answer to 3 s.f.

Not a polynomial — graph the two sides y₁ = 2^x y₂ = 50 Use “intersect” — single crossing point x = 5.6438… x ≈ 5.64 (3 s.f.) also solvable by hand: x = log₂(50). Both give the same number.
WE 4

No algebraic solution — Graph Intersection finds ALL

Solve x² = 2ˣ, giving each solution to 3 s.f.

Graph both sides; look for all crossings y₁ = x², y₂ = 2^x Window: x from −2 to 5 catches all 3 intersections use “intersect” three times — left, middle, right x ≈ −0.766, x = 2, x = 4 if you only spot 2 intersections, your window is too narrow. ALWAYS sketch first to know how many to expect.
WE 5

Simultaneous linear — Linear System Solver

Solve simultaneously: 2x + 3y = 13  and  x + y = 5.

GDC Linear System Solver 2 unknowns, 2 equations enter coefficients row by row: [2, 3 | 13] [1, 1 | 5] x = 2, y = 3 faster than substitution. Same tool handles 3 unknowns / 3 equations in HL, AI HL.
WE 6

Real-world — when does a population exceed a target?

A population is modelled by P(t) = 500 × 1.05ᵗ. Find the smallest time t at which the population first exceeds 1000.

Set up 500 × 1.05^t = 1000 Graph intersection y₁ = 500 × 1.05^x y₂ = 1000 intersect → t = 14.2066… t ≈ 14.2 years (or 15 if whole years only) read the question — “first exceeds” with whole-year context would round UP to 15.

💡 Top tips

⚠ Common mistakes

That wraps the Number Toolkit. Up next: Exponentials & Logs — now that you can SOLVE exponential equations on the GDC, the next note shows how to solve them BY HAND using logarithm rules.

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