IB Maths AI SL Topic 1 — Sequences & Series Paper 1 & 2 In formula booklet ~7 min read

Arithmetic Sequences & Series

An arithmetic sequence goes up (or down) by the same amount each step. That fixed step is the common difference, d. Two formulae do all the work — one for any term, one for the sum.

šŸ“˜ What you need to know

Finding the nth term

nth term — formula booklet un = u1 + (n āˆ’ 1)d
Arithmetic sequence: u1 = 7, d = 4 7 u1 11 u2 15 u3 19 u4 23 u5 +4 +4 +4 +4 USE un = u1 + (n āˆ’ 1)d — e.g. find u15 u15 = 7 + (15 āˆ’ 1)(4) = 7 + 56 = 63
The common difference d is the same between every consecutive pair. To jump straight to u15 without listing all 14 terms, use the formula.

Finding the sum Sn

Sum of n terms — both in formula booklet Sn = n2(2u1 + (n āˆ’ 1)d)    or    Sn = n2(u1 + un)
Which version to use? If the question gives you u1 and d, use the first. If it gives you the first AND last term (u1 and un), the second is faster.

🧭 Recipe — solve any arithmetic problem

  1. Identify u1 and d: from the sequence, or from two given terms (solve simultaneously).
  2. To find a specific term: plug n into un = u1 + (n āˆ’ 1)d.
  3. To find which term equals a value: set un = value and solve for n.
  4. To find a sum: plug into the Sn formula.
  5. To find n from Sn: get a quadratic in n, solve on GDC, take the positive integer root.

Worked examples

WE 1

Find a specific term

An arithmetic sequence has first term 7 and common difference 4. Find u15.

Apply u_n = u_1 + (n āˆ’ 1)d u_15 = 7 + (15 āˆ’ 1)(4) = 7 + 56 u15 = 63
WE 2

Find which term equals a value

An arithmetic sequence has u1 = 5 and d = 3. Find the value of n for which un = 80.

Set u_n = 80 and solve 5 + (n āˆ’ 1)(3) = 80 3(n āˆ’ 1) = 75 n āˆ’ 1 = 25 n = 26 check: u_26 = 5 + 25(3) = 80 āœ“
WE 3

Given two terms — solve simultaneously

The 3rd term of an arithmetic sequence is 17 and the 8th term is 47. Find u20.

Write each term in u_1, d form u_3 = u_1 + 2d = 17 u_8 = u_1 + 7d = 47 Subtract (eliminate u_1) 5d = 30 → d = 6 Find u_1 u_1 + 2(6) = 17 → u_1 = 5 Find u_20 u_20 = 5 + 19(6) = 5 + 114 u20 = 119 subtracting the two equations eliminates u_1 — fastest way to find d.
WE 4

Find a sum Sn

Find the sum of the first 20 terms of the sequence 4, 7, 10, 13, …

Identify u_1, d, n u_1 = 4, d = 3, n = 20 Use S_n = n/2 (2u_1 + (n āˆ’ 1)d) S_20 = 20/2 Ɨ (2(4) + 19(3)) = 10 Ɨ (8 + 57) = 10 Ɨ 65 S20 = 650
WE 5

Find n given Sn (quadratic)

An arithmetic sequence has u1 = 2 and d = 3. Find the value of n for which Sn = 345.

Apply S_n formula n/2 Ɨ (2(2) + (n āˆ’ 1)(3)) = 345 n/2 Ɨ (3n + 1) = 345 n(3n + 1) = 690 Quadratic in n 3n² + n āˆ’ 690 = 0 Solve on GDC (Polynomial Root Finder) n = 15 or n = āˆ’15.33… (reject negative) n = 15 always reject negative or non-integer roots — n must be a positive whole number.
WE 6

Real-world — stadium seating

A theatre has 12 seats in the front row, and each subsequent row has 2 more seats than the row in front. How many seats are there in total across 25 rows?

Identify the arithmetic sequence u_1 = 12, d = 2, n = 25 Apply S_n S_25 = 25/2 Ɨ (2(12) + 24(2)) = 25/2 Ɨ (24 + 48) = 25/2 Ɨ 72 S25 = 900 seats whenever something grows by a FIXED amount each step, it’s arithmetic — reach for these formulae.

šŸ’” Top tips

⚠ Common mistakes

Up next: Geometric Sequences & Series — same idea but you MULTIPLY by a fixed amount (common ratio r) instead of adding. Same two formulae structure: one for terms, one for sums.

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