IB Maths AI HL Number Toolkit Paper 2 GDC solver ~6 min read

Solving Equations using a GDC

Your GDC can solve equations that would be slow or impossible by hand. This note covers the two it solves directly — systems of linear equations and polynomial equations — how to enter them, and how to read and interpret the solutions it returns.

📘 What you need to know

Systems of linear equations

A system of linear equations is a set of equations solved together. “Linear” means every term is a constant or a single variable to the power 1 — no squares, no products of variables. The GDC solves an n×n system: n equations in n unknowns.

Standard form of a linear system 2×2:   ax + by = e  ,  cx + dy = f 3×3:   ax + by + cz = p  ,  …  (three equations) rearrange each equation into this form before entering it into the GDC

To find the point of intersection of two straight lines, rearrange both into ax + by = e form, solve the 2×2 system, and write the answer as coordinates (x, y).

Polynomial equations

A polynomial equation is built from terms axk with k a non-negative integer, set equal to zero. The highest power is the order (or degree). Negative or fractional powers are not allowed.

Polynomial equation of order n anxn + an−1xn−1 + … + a1x + a0 = 0 n is a positive integer — e.g. 2x3 + 4x2x + 1 = 0 has order 3

The GDC’s polynomial solver asks for the order first, then the coefficients. It returns the roots — the values of x that satisfy the equation.

How many solutions?

A polynomial of order n has up to n real solutions. If n is odd there is always at least one; if n is even there may be none. To count them, plot y = … and see how often the graph meets the x-axis.

Each x-axis crossing is one solution x y −3 −2 −1 1 2 y = x³ − 7x + 6 solution 1 solution 2 solution 3order 3 → up to 3 solutions; here the curve crosses the x-axis 3 times
The cubic y = x³ − 7x + 6 meets the x-axis three times, so the equation x³ − 7x + 6 = 0 has three real solutions: x = −3, 1, 2.
Exam phrasing: if a question says “using technology, solve…”, you may go straight to the GDC — no algebraic working is needed, but state the equations clearly first.

🧭 Recipe — solving an equation on the GDC

  1. Identify the type: a system of linear equations, or a single polynomial equation.
  2. Rearrange — linear equations into ax + by = e form; a polynomial into “… = 0”.
  3. Open the solver: choose the system size n×n, or enter the polynomial’s order.
  4. Enter the coefficients exactly as written, then read off the solutions the GDC gives.
  5. Interpret — write intersections as coordinates, and reject any solution that doesn’t fit the context.

Worked examples

WE 1

A 2×2 linear system

Use technology to solve the system  4x + 3y = 27  and  2xy = 1.

both equations are already in ax + by = e form enter into the GDC’s 2×2 solver read off the solution x = 3,   y = 5 check: 4(3) + 3(5) = 27 and 2(3) − 5 = 1. ✓
WE 2

A 3×3 linear system

Solve the system  x + y + z = 6,   2xy + z = 3,   x + 2yz = 2.

3 equations, 3 unknowns — a 3×3 system enter all three into the GDC’s 3×3 solver read off the solution x = 1,   y = 2,   z = 3 enter the coefficients in the same order in every row, including any zeros.
WE 3

Point of intersection of two lines

Find the coordinates of the point where the lines y = 2x + 1 and y = −x + 7 intersect.

rearrange both into ax + by = e 2x − y = −1  and  x + y = 7 solve the 2×2 system on the GDC x = 2, y = 5 intersection at (2, 5) the solution of the system is the point of intersection — write it as coordinates.
WE 4

Solving a polynomial equation

Use your GDC to solve the equation x3 − 7x + 6 = 0.

a polynomial equation of order 3 enter order 3 and the coefficients 1, 0, −7, 6 the GDC returns the roots x = −3,   x = 1,   x = 2 don’t forget the coefficient of x2 is 0 — it still must be entered.
WE 5

How many solutions?

By considering the graph of y = x2 − 4x + 7, state how many real solutions the equation x2 − 4x + 7 = 0 has.

plot the graph on the GDC the parabola has a minimum value of 3 it stays entirely above the x-axis no crossings ⇒ no real solutions 0 real solutions order 2 is even — so having no real solutions is possible.
WE 6

Full question: forming a linear system

At a café, 4 teas and 3 muffins cost $19, while 2 teas and 5 muffins cost $20. (a) Set up a system of linear equations. (b) Using technology, find the price of one tea and one muffin.

(a) let t = tea price, m = muffin price 4t + 3m = 19 2t + 5m = 20 (b) solve the 2×2 system on the GDC t = 2.5, m = 3 (a) above · (b) tea $2.50, muffin $3.00 define your variables clearly, then convert each sentence into one equation.

💡 Top tips

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That completes the Number Toolkit. Next chapter: Sequences & Series — arithmetic and geometric patterns and their sums. The GDC stays close at hand: it solves the equations these problems often lead to, and lets you check answers quickly.

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