IB Maths AI HL Exponentials & Logs Paper 1 & 2 logab ~6 min read

Introduction to Logarithms

A logarithm is the inverse of a power — it answers the question “what power do I raise this base to?” That makes logarithms the tool for solving equations where the unknown sits in the exponent.

📘 What you need to know

What is a logarithm?

A power such as ax = b links three numbers: the base a, the exponent x and the result b. A logarithm rearranges that statement to make the exponent the subject.

A logarithm finds the power 23 = 8 base the power result log2 8 = 3 “what power of 2 gives 8?”same three numbers — the log just makes the power the subject
The power statement 23 = 8 and the logarithm log28 = 3 say exactly the same thing — a logarithm isolates the exponent.
Logarithm — the inverse of a power ax = b  ⇔  x = logab for a > 0, b > 0, a ≠ 1 — this relationship is in the formula booklet

Natural logs and base 10

Two bases appear so often they get their own notation. The natural logarithm uses the constant e; the common logarithm, written with no base shown, uses base 10.

Two special logarithms ln x = logex   ·   log x = log10x e ≈ 2.718 (Euler’s number) — your GDC has ln, log and a logab key

Solving exponential equations

An exponential equation has the unknown in the power. If the result is a neat power of the base, solve it by inspection — 2x = 8 clearly gives x = 3.

When the result is not a neat power — like 2x = 10 — rewrite the equation as a logarithm, x = log210, and evaluate it on the GDC.

GDC tip: for any base, use the logab key — enter the base and the number directly. The ln and log keys handle base e and base 10.

🧭 Recipe — evaluating a log or solving a x = b

  1. Identify the base — the number being raised to a power.
  2. Ask “what power of the base gives the result?” — try inspection first.
  3. If it is a neat power of the base, state the answer directly.
  4. If not, rewrite ax = b as x = logab.
  5. Evaluate logab on the GDC, rounding as the question asks.

Worked examples

WE 1

Evaluating a logarithm by inspection

Find the value of log381.

ask: what power of 3 gives 81? 31=3, 32=9, 33=27, 34=81 34 = 81, so the power is 4 log381 = 4 a logarithm is just “the power” — here, the power of 3 that makes 81.
WE 2

Switching between the two forms

(a) Write 54 = 625 in logarithmic form. (b) Write log7343 = 3 in exponential form.

use ax = b ⇔ x = logab (a) base 5, power 4, result 625 54 = 625 ⇒ log5625 = 4 (b) base 7, log equals 3, result 343 log7343 = 3 ⇒ 73 = 343 (a) log5625 = 4  ·  (b) 73 = 343 the base stays the base; the log value is the power.
WE 3

An exponential equation by inspection

Solve the equation 3x = 243.

is 243 a neat power of 3? 34 = 81,   35 = 243 the power that works is 5 x = 5 when the result is a clean power of the base, no logarithm is needed.
WE 4

An exponential equation needing a log

Solve the equation 5x = 90, giving your answer correct to 3 significant figures.

90 is not a neat power of 5 — use a log 5x = 90 ⇒ x = log590 evaluate on the GDC x = 2.79588… x ≈ 2.80 (3 s.f.) rewrite ax = b as x = logab, then use the logab key.
WE 5

Natural log and base 10

Solve, correct to 3 significant figures: (a) ex = 20  and  (b) 10x = 0.05.

(a) base e — the log is ln ex = 20 ⇒ x = ln 20 = 2.99573… (b) base 10 — the log is log 10x = 0.05 ⇒ x = log 0.05 = −1.30103… (a) x ≈ 3.00  ·  (b) x ≈ −1.30 the log of a number less than 1 is negative — that is fine.
WE 6

Full question: bacteria growth

A colony of bacteria doubles every hour. Starting from 50 bacteria, the number after t hours is N = 50 × 2t. (a) Find N after 4 hours. (b) Find the exact time when N = 3200. (c) Find the time when N = 5000, to 3 s.f.

(a) substitute t = 4 N = 50 × 24 = 50 × 16 = 800 (b) 50 × 2t = 3200 ⇒ 2t = 64 26 = 64, so t = 6 (by inspection) (c) 50 × 2t = 5000 ⇒ 2t = 100 t = log2100 = 6.6439… (a) 800 · (b) t = 6 hours · (c) t ≈ 6.64 hours divide out the 50 first, then inspect or take a log of 2t = …

💡 Top tips

âš  Common mistakes

Next up: Laws of Logarithms — rules for adding, subtracting and scaling logs, which mirror the index laws exactly. They let you combine several logarithms into one and solve far richer equations.

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