IB Maths AI HLTransformations of GraphsPaper 1 & 2x-axis, y-axis, asymptotes~8 min read
Reflections of Graphs
A reflection flips the graph across an axis, keeping shape and size but swapping orientation. y = −f(x) flips vertically (across the x-axis), y = f(−x) flips horizontally (across the y-axis). Only one coordinate of each point changes sign.
📘 What you need to know
Reflection in the x-axis: y = −f(x). y-coordinates change sign; x-coordinates stay the same.
Reflection in the y-axis: y = f(−x). x-coordinates change sign; y-coordinates stay the same.
Points on the axis of reflection are unchanged.
Max ↔ min flip under x-axis reflection; max stays max, min stays min under y-axis reflection.
Asymptotes after −f(x): horizontal y = k → y = −k; vertical asymptote unchanged.
Asymptotes after f(−x): vertical x = k → x = −k; horizontal asymptote unchanged.
The two reflections side by side
Two simple rules cover this topic. Putting a minus sign outside the function — y = −f(x) — multiplies every output by −1, so the curve flips top-to-bottom across the x-axis. Putting a minus sign inside the bracket — y = f(−x) — feeds in the negative of the input, so the curve flips left-to-right across the y-axis. In both cases the shape is identical to the original: same widths, same heights, same maxima and minima — just relocated.
What changes (and what doesn’t)
For y = −f(x): each y-coordinate is negated. A maximum becomes a minimum (and vice versa). Any point that was on the x-axis stays where it is. Horizontal asymptotes flip sign (y = 3 becomes y = −3); vertical asymptotes don’t move. For y = f(−x): each x-coordinate is negated. A maximum stays a maximum (the curve isn’t tipped over, just mirrored sideways). Points on the y-axis stay put. Vertical asymptotes flip sign (x = 4 becomes x = −4); horizontal asymptotes are untouched.
The vertex (2, −3) mirrors to (−2, −3) under y-axis reflection (still a minimum) and to (2, 3) under x-axis reflection (now a maximum).
Reflection at a glancey = −f(x) ↔ reflect in x-axis · y = f(−x) ↔ reflect in y-axis
point (p, q) → (p, −q) under −f; → (−p, q) under f(−x)
Reflecting equations and asymptotes
For an explicit function, the reflection is mechanical. To get y = −f(x), put a minus sign in front of the whole formula and expand. To get y = f(−x), substitute −x wherever x appears, then simplify. Asymptotes follow the same rules: only the asymptote of the matching orientation moves. Vertical asymptotes follow horizontal reflections (y-axis reflection); horizontal asymptotes follow vertical reflections (x-axis reflection).
One-axis rule: a reflection moves only the coordinate matching its name. x-axis reflection → y-coordinates flip. y-axis reflection → x-coordinates flip. Asymptotes obey the same rule.
🧭 Recipe — reflecting a graph
Identify the axis of reflection: minus outside → x-axis; minus inside → y-axis.
Apply to the equation: y = −f(x) or y = f(−x); expand or simplify.
Reflect every key point: negate the matching coordinate (y for x-axis; x for y-axis).
Reflect the asymptotes: horizontal asymptotes flip under x-axis reflection; vertical asymptotes flip under y-axis reflection.
Sketch: the new curve is identical in shape, mirrored across the chosen axis.
Worked examples
WE 1
Identify the reflection type
For the graph of y = f(x): (a) Write the equation of the graph reflected in the x-axis. (b) Write the equation of the graph reflected in the y-axis. (c) State which coordinate changes for each reflection.
(a) x-axis reflection → minus outsidey = −f(x)(b) y-axis reflection → minus insidey = f(−x)(c) which coordinate changes−f(x): y-coordinates change sign, x staysf(−x): x-coordinates change sign, y staysthe axis of reflection’s coordinate is the one that flips.
WE 2
Image of a point
The point Q(−2, 7) lies on the graph of y = f(x). Find the corresponding point on the graph of: (a) y = −f(x); (b) y = f(−x).
Given f(x) = 2x + 3 with horizontal asymptote y = 3. For each reflection, find the new asymptote and the y-intercept: (a) y = −f(x); (b) y = f(−x).
f(0) = 1 + 3 = 4(a) y = −f(x) = −2ᵛ − 3asymp: y = 3 → y = −3 (horizontal flips)y-intercept: −f(0) = −4asymp y = −3; (0, −4)(b) y = f(−x) = 2⁻ᵛ + 3asymp: y-axis reflection doesn’t change horizontal asymptotey = 3 (unchanged); y-intercept f(0) = 4asymp y = 3; (0, 4)
WE 5
Rational function with both asymptotes
Given f(x) = 1x − 4 + 2 with vertical asymptote x = 4 and horizontal asymptote y = 2. State the asymptotes of: (a) y = f(−x); (b) y = −f(x).
(a) y-axis reflectionvertical asymp x = 4 → x = −4horizontal asymp y = 2 (unchanged)x = −4; y = 2(b) x-axis reflectionvertical asymp x = 4 (unchanged)horizontal asymp y = 2 → y = −2x = 4; y = −2the reflection’s name tells you which asymptote moves.
WE 6
Comprehensive: features under both reflections
The graph of y = f(x) has a maximum at (4, 9), a minimum at (−1, −3) and a vertical asymptote x = 2. State the new max/min and asymptote for: (a) y = −f(x); (b) y = f(−x).
(a) x-axis reflection: y flips, max↔min(4, 9) max → (4, −9) min(−1, −3) min → (−1, 3) maxvertical asymp x = 2 (unchanged)min (4, −9), max (−1, 3), asymp x = 2(b) y-axis reflection: x flips, max stays max(4, 9) max → (−4, 9) max(−1, −3) min → (1, −3) minvertical asymp x = 2 → x = −2max (−4, 9), min (1, −3), asymp x = −2
💡 Top tips
Minus position tells you everything: outside the function = x-axis; inside the bracket = y-axis.
Only one coordinate changes per reflection: never both unless you’re combining transformations.
Max ↔ min flip only for x-axis reflection: y-axis reflection keeps them the same type.