IB Maths AI HL Normal Distribution Paper 1 & 2 ~7 min read

Calculations with Normal Distribution

With X ∼ N(μ, σ2), every probability is an area under the bell curve, found on your GDC. Use the normal CD (cumulative) function for any range — never the normal PD, which gives density, not probability. For one-sided tails, plug in a “very big” bound. And to go backwards from a probability to a value of x, use the inverse normal. A quick sketch of the area each time keeps you out of trouble.

📘 What you need to know

Probabilities with the normal CD

The area under the curve between a and b is P(a < X < b). Because P(X = x) = 0, you never worry about < versus ≤. Find the area with the normal CD function.

Range probability = area P(a < X < b) = P(aXb) = normal CD(a, b, μ, σ) use the normal CD on your GDC — NOT the normal PD

🧭 Recipe — P(a < X < b) on the GDC

  1. Identify μ and σ (square-root the variance if you’re given σ2).
  2. Sketch the curve and shade the area you want.
  3. Open the normal CD function and enter lower, upper, μ, σ (mind the input order).
  4. Read off the probability and round (usually 3 sf).

🧠 Memory aid — “CD not PD”

The normal PD (Pdf) gives the height of the curve at a point — useless for probability, and zero-width anyway. Always reach for the normal CD (Cdf), which gives the area. PD = point/density, CD = cumulative/area.

WE 1

A single value

Y ∼ N(20, 52). Find P(Y = 20).

single value of a continuous variable the area of a single line is zero. P(Y = 20) = 0 always zero for any exact value of a normal variable.
WE 2

A range probability

Y ∼ N(20, 52). Find P(18 ≤ Y < 27).

identify μ and σ μ = 20, σ = 5 (already given as 5²) use normal CD on GDC lower = 18, upper = 27 → P = 0.574665… P(18 ≤ Y < 27) ≈ 0.575 (3sf) ≤ and < make no difference for a normal variable.

One-sided tails & identities

For a one-sided probability you still use the normal CD, but one bound is “infinity”. The trick is to enter a number far enough into the tail that the missing area is negligible.

P(X > a) — upper tail
huge upper
lower = a, upper = a very big number like 1099 (or 99999…).
P(X < b) — lower tail
huge negative
lower = a very big negative like −1099, upper = b.
Useful identities P(X < μ) = P(X > μ) = 0.5
P(X > a) = 1 − P(X < a)     P(a < X < b) = P(X < b) − P(X < a) handy when μ/σ are unknown or you only have a diagram
An upper tail: P(Y > 29) on N(20, 5²)
20 (μ) 29 P(Y > 29) no upper bound → enter a big number (e.g. 99999)
For an upper tail set lower = 29, upper = a very big number; here the area is ≈ 0.0359.
WE 3

An upper-tail probability

Y ∼ N(20, 52). Find P(Y > 29).

no upper bound → use a big number lower = 29, upper = 99999 use normal CD on GDC P(Y > 29) = 0.035930… P(Y > 29) ≈ 0.0359 (3sf) 29 is well above the mean of 20, so a small tail probability makes sense.

The inverse normal

The inverse normal (InvN) goes the other way: you give it an area to the left and it returns the value of x. To use it, every probability must first be written as a left tail P(X < a).

🧭 Recipe — inverse normal

  1. Rewrite as a left tail: if you’re given P(X > a) = p, use P(X < a) = 1 − p.
  2. Open InvN and enter the area (left), then μ, then σ.
  3. Read off the value of a.
  4. Sense-check: left-area < 0.5 → a below μ; left-area > 0.5 → a above μ.

🤔 Why turn P(X > a) into a left tail?

The basic inverse normal expects the area to the left of the value. If a question gives a right-tail probability, subtract it from 1 first: P(X < a) = 1 − P(X > a). (Some calculators have a “tail: right” option that skips this step.) Then the calculator can find the matching a.

WE 4

Inverse normal from a right tail

W ∼ N(50, 36). Find the value of w such that P(W > w) = 0.175.

identify μ and σ μ = 50, σ² = 36 → σ = 6 rewrite as a left tail P(W < w) = 1 − 0.175 = 0.825 use InvN with area 0.825 w = 55.6075… w ≈ 55.6 (3sf) area 0.825 > 0.5, so w is above the mean of 50 — checks out.
WE 5

Inverse normal from a left tail

W ∼ N(50, 36). Find the value of w such that P(W < w) = 0.30.

already a left tail area = 0.30, μ = 50, σ = 6 use InvN directly w = 46.853… w ≈ 46.9 (3sf) area 0.30 < 0.5, so w is below the mean — makes sense.

💡 Top tips

⚠ Common mistakes

That completes the Normal Distribution unit! You can now describe a normal model, read off its mean and standard deviation, find probabilities with the normal CD, handle one-sided tails, and run the inverse normal to recover a value from a probability. These GDC skills carry straight into hypothesis testing and confidence intervals, where normal probabilities underpin critical values and test statistics.

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