IB Physics SL Topic B.2 — Climate & the Greenhouse Effect Paper 1 & 2 Energy Balance · One-Layer Model ~8 min read

Energy Balance Calculations

Everything from this topic — albedo, emissivity, the solar constant, greenhouse gases — comes together here. If you can balance incoming and outgoing radiation for a planet or an atmosphere layer, you can calculate an equilibrium temperature from scratch.

📘 What you need to know

What “Energy Balance” Actually Means

Every worked problem in this topic reduces to the same underlying statement: at a stable temperature, a body radiates away exactly as much energy as it takes in. Push more energy in — by increasing solar intensity, lowering albedo, or thickening a greenhouse gas layer — and the temperature has to rise until outgoing radiation catches back up.

Condition for a stable temperature intensity absorbed = intensity emitted

The Simplest Case — A Planet With No Atmosphere

Strip everything back to a bare planet in space. It absorbs a fraction (1 − a) of the mean solar intensity S⁄4 falling on it, and radiates according to the Stefan–Boltzmann law. Setting these equal and solving for temperature gives a genuinely useful formula:

Equilibrium temperature (no atmosphere) T = 4√[ (1 − a)S ÷ (4eσ) ]

Adding an Atmosphere — The One-Layer Model

Real planets aren’t bare — an atmosphere layer sits above the surface, absorbing some outgoing infrared and sending part of it straight back down. The surface then has to balance two incoming contributions against its own emission: the solar radiation that makes it through the atmosphere, plus the radiation the atmosphere itself re-emits downward.

incoming solar intensity, S⁄4 ATMOSPHERE emissivity e, temperature T_atm solar reaching surface directly atmosphere radiates downward, I = eσT_atm⁴ EARTH’S SURFACE black body, e = 1, temperature T_s
The surface absorbs both the solar intensity that reaches it directly and the infrared intensity the atmosphere radiates back down — both contributions have to be added before solving for the new surface temperature.

🧮 Solving an energy-balance problem

  1. List the knowns — temperatures, emissivities, albedo and the incoming solar intensity.
  2. Find the solar intensity reaching the surface directly, usually using the atmosphere’s emissivity as the fraction that gets through.
  3. Use I = eσT4 to find the intensity the atmosphere itself radiates back down.
  4. Add the two contributions together to get the total intensity absorbed at the surface.
  5. Solve I = σT4 for the surface, treating it as a black body (e = 1), to find its new temperature.
  6. Subtract the original surface temperature to get ΔT.
Quick recap: at equilibrium, absorbed intensity equals emitted intensity. In a one-layer model, add the solar contribution and the atmospheric contribution before solving for the surface’s new temperature.
WE 1

Model a planet with no atmosphere. Its albedo is 0.30 and it behaves as a black body. The solar constant at its orbit is 1360 W m⁻². Calculate its equilibrium surface temperature.

Step 1 — Find the mean absorbed intensity absorbed = (1 − 0.30) × 1360 ÷ 4 = 238 W m⁻² Step 2 — Apply the Stefan–Boltzmann law (e = 1) 238 = (5.67 × 10⁻⁸) × T⁴ T⁴ = 4.20 × 10⁹ T ≈ 255 K That’s roughly 33 K colder than Earth’s actual average surface temperature of 288 K — the difference is exactly the warming the greenhouse effect provides.
WE 2

In a one-layer model, the mean solar intensity above the atmosphere is 340 W m⁻² and the atmosphere’s emissivity is 0.75. The atmosphere’s temperature is 255 K, and the surface — treated as a black body currently at 288 K — absorbs both the solar radiation reaching it directly and the radiation the atmosphere emits downward. Estimate the surface’s new equilibrium temperature and the resulting increase, ΔT.

Step 1 — Solar intensity reaching the surface directly I_s(solar) = 0.75 × 340 = 255 W m⁻² Step 2 — Intensity radiated downward by the atmosphere I_atm = 0.75 × (5.67 × 10⁻⁸) × 255⁴ ≈ 180 W m⁻² Step 3 — Total intensity absorbed at the surface I_total = 255 + 180 = 435 W m⁻² Step 4 — Solve for the new surface temperature (e = 1) 435 = (5.67 × 10⁻⁸) × T_s⁴ → T_s ≈ 296 K Step 5 — Find ΔT ΔT = 296 − 288 ΔT ≈ 8 K Small changes in atmospheric temperature and emissivity translate into a real shift in surface temperature — this is exactly the kind of reasoning behind climate-model predictions.

💡 Top tips

⚠ Common mistakes

That’s Topic B.2 complete — albedo, emissivity, the solar constant, greenhouse gases and full energy-balance models, all working together. Next up, we’ll move into a new topic building on these same black-body ideas.

Want this to actually stick before the exam?

Book a free session and we’ll work through energy-balance problems, step by step, until they’re second nature.

Book your free meeting