IB Physics SL Topic 4 — Electric & Magnetic Fields Paper 1 & 2 F = kq₁q₂/r² ~8 min read

Coulomb’s Law

Last page gave the rule: opposites attract, likes repel. Coulomb’s law now tells you exactly how hard. It’s the electric twin of Newton’s law of gravitation — same inverse-square shape — but with one dramatic twist: this force can push as well as pull.

📘 What you need to know

The Law Itself

Every charge sits in its own electric field, and any other charge nearby feels a force from it. Coulomb measured exactly how that force depends on the charges and their separation:

The electric force between two point charges is proportional to the product of the charges and inversely proportional to the square of their separation.

Coulomb’s law F = k q1q2 ÷ r²

Where:

Attractive or Repulsive?

The size of the force comes from the formula; the direction comes from the signs. Two charges of the same type push apart; two opposite charges pull together. Whatever the charges, the pair always feel equal and opposite forces — Newton’s third law never takes a day off.

r (centre to centre) + q1 q2 F F ATTRACT opposite charges + + F F REPEL like chargesthe two forces are always equal and opposite (Newton’s third law)
The magnitude comes from F = kq1q2 ÷ r²; the direction comes from the signs. Opposite charges attract, like charges repel — and each charge feels the same size force. Remember to measure r centre to centre.

It’s an Inverse-Square Law

That r² on the bottom does the heavy lifting. Because the force depends on 1 ÷ r², moving the charges apart makes it fall away fast: double the separation and the force drops to a quarter; treble it and the force is just a ninth.

separation, r force, F F0 ¼F0 r 2rF ∝ 1 ÷ r² double the distance → quarter the force
The inverse-square shape: the force plunges as the charges separate. Go from r to 2r and the force falls to a quarter — exactly the same curve as gravity, just far stronger.
Newton’s gravity
F = GMm ÷ r²
both ∝ 1 ÷ r²
(same shape)
Coulomb’s law
F = kq1q2 ÷ r²

The two laws are near-identical twins. The big difference: mass only ever attracts, but charge comes in two signs, so the electric force can pull or push — and it’s enormously stronger than gravity for everyday amounts of charge.

Where k Comes From: Permittivity

The constant k isn’t random — it’s built from a property of space itself, the permittivity of free space ε0:

The Coulomb constant k = 1 ÷ (4πε0)

Here ε0 = 8.85 × 10⁻¹² C² N⁻¹ m⁻². Permittivity measures how easily an electric field forms in a material. Air is so close to a vacuum that we take its permittivity as ε0. Every other material has a higher permittivity, and we compare them using the relative permittivity (or dielectric constant):

Relative permittivity (dielectric constant) εr = ε ÷ ε0

It’s a ratio of two permittivities, so it has no units. Put a material between the charges and the Coulomb constant becomes k = 1 ÷ (4πε): a bigger permittivity means a smaller force. In practice the force in a medium is just the vacuum force divided by εr — water (εr ≈ 80) weakens it dramatically.

The Point-Charge Rule

One catch worth memorising: Coulomb’s law only works for point charges, or for uniformly charged spheres that you can treat as a point charge sitting at the centre — and only when the objects are much smaller than their separation. Always measure r from the centres. You can’t use it for oddly shaped charged objects, where the charge is smeared out unevenly.

🧭 Using Coulomb’s law

  1. List the charges in coulombs and the separation r in metres, measured centre to centre
  2. Put the magnitudes into F = kq1q2 ÷ r² to get the size of the force
  3. Read the direction off the signs — like charges repel, opposite charges attract
  4. In a medium, swap ε0 for ε = εrε0 — or simply divide the vacuum force by εr
  5. Sanity-check with the inverse square — ×2 distance means ×¼ force
Quick recap: F = kq1q2 ÷ r² with k = 8.99 × 10⁹ = 1 ÷ (4πε0). Like charges repel, opposite attract; it’s inverse-square like gravity but two-signed; and it only applies to point charges with r taken centre to centre.
WE 1

Two small charged spheres carry charges of +4.0 μC and +6.0 μC and are held 0.30 m apart in air. (a) Calculate the electric force between them. (b) State whether it is attractive or repulsive. (c) The separation is now tripled. State the new force.

Part (a) — Coulomb’s law (convert: μC → C, cm → m) F = kq₁q₂ ÷ r² = (8.99 × 10⁹ × 4.0 × 10⁻⁶ × 6.0 × 10⁻⁶) ÷ (0.30)² F = (8.99 × 10⁹ × 2.4 × 10⁻¹¹) ÷ 0.090 F ≈ 2.4 N Part (b) — direction from the signs Both charges are positive (like charges), so the force is repulsive Part (c) — inverse square: ×3 distance → ×1/9 force F’ = 2.4 ÷ 9 F’ ≈ 0.27 N
WE 2

(a) A dielectric material has a relative permittivity of 5.0. Calculate its permittivity ε and state the unit. (b) Two point charges are held a fixed distance apart. By what factor does the electric force between them change when they are moved from a vacuum into this material?

Part (a) — rearrange εr = ε ÷ ε₀ ε = εr × ε₀ = 5.0 × (8.85 × 10⁻¹²) ε = 4.4 × 10⁻¹¹ F m⁻¹ Part (b) — a medium changes k = 1 ÷ (4πε) The permittivity is εr = 5.0 times bigger, so k (and the force) is 5.0 times smaller force becomes 1/5 = 0.20 × the vacuum value Bigger permittivity → weaker force. That’s why εr is called the material’s “resistance” to forming a field.

💡 Top tips

⚠ Common mistakes

You can now put a number on the force between charges. Up next: Electric Field Strength — instead of asking about the force between two charges, we ask what one charge does to the space around it, and define the field E = F ÷ q that any other charge then feels.

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