IB Physics SL Tool 3 — Mathematics Paper 1 & 2 & IA Absolute · fractional · % ~8 min read

Handling Uncertainties

No measurement is ever perfect. A ruler can only be read so finely, a stopwatch depends on your reflexes, a meter needle sits somewhere between two marks. Rather than pretend the doubt away, physics states it openly: every result comes with an uncertainty — a ± range within which the true value almost certainly lies. Handling those ranges correctly is what separates a raw number from a trustworthy result, and it’s a skill your Internal Assessment rewards heavily.

📘 What you need to know

The three kinds of uncertainty

The same doubt can be expressed three ways, and each is useful at a different moment. The absolute uncertainty is the raw ± amount in the measurement’s own units. The fractional uncertainty divides that by the value, giving a pure ratio. The percentage uncertainty is simply the fractional one as a percentage.

Percentage uncertainty % uncertainty = (uncertainty ÷ measured value) × 100

For a length measured as L = 5.0 ± 0.1 cm, the absolute uncertainty is 0.1 cm, the fractional is 0.1 ÷ 5.0 = 0.02, and the percentage is 2%.

Reading uncertainty off an instrument

Where does the ± come from in the first place? It depends on the instrument. On an analogue scale, you can reasonably read to half the smallest division; on a digital readout, the uncertainty is the last displayed digit. A meter needle sitting between the marks is the classic case.

0 5 10 15 reading = 7.4 ± 0.1 mA milliamperes (mA)
The needle falls between marks, so the reading is ± half the smallest division — here ± 0.1 mA.
SituationUncertainty to use
a single reading± half the smallest division
a measurement (two readings)at least ± 1 smallest division
repeated datahalf the range: ± ½ (largest − smallest)
digital readings± the last significant digit

Combining uncertainties

Once a result comes from several measurements, their uncertainties have to be carried through the calculation. The rule you use depends on the operation.

OperationExampleRule
add or subtracty = a ± badd the absolute uncertainties: Δy = Δa + Δb
multiply or dividey = ab or a÷badd the fractional uncertainties: Δy÷y = Δa÷a + Δb÷b
raise to a powery = anmultiply the fractional uncertainty by n: Δy÷y = na÷a)
+ or −
→ add →
absolute
uncertainties
  
× or ÷
→ add →
fractional
uncertainties
A memory hook that never fails me: plus/minus → add the pluses-and-minuses (the absolute amounts), while times/divide → add the percentages. And for powers, the exponent just scales the percentage — cubing something triples its percentage uncertainty. Get those three straight and you can propagate anything the exam throws at you.
Quick recap: uncertainty is a ± range; read it as half a division (analogue) or the last digit (digital); add absolute uncertainties for ±, add fractional/% for ×÷, and multiply the fractional by the power for an.

Quoting uncertainties properly

The final polish is presentation. An absolute uncertainty is quoted to 1 significant figure (with a rare exception when the first digit is 1). The measured value is then rounded so its last decimal place lines up with the uncertainty — it would be absurd to write 2.4173 ± 0.1.

🧭 Presenting a result

  1. Round the uncertainty to 1 significant figure
  2. Round the value so its final digit sits in the same place as the uncertainty
  3. State the units on both the value and the absolute uncertainty
  4. Add the percentage too, if the question asks for it
WE 1

A student times one swing of a pendulum five times and records: 2.41, 2.38, 2.44, 2.40 and 2.42 s. Find the mean period and its absolute and percentage uncertainty.

Mean period (2.41 + 2.38 + 2.44 + 2.40 + 2.42) ÷ 5 = 12.05 ÷ 5 = 2.41 s Uncertainty (half the range) ± ½ (2.44 − 2.38) = ½ × 0.06 = 0.03 s Percentage (0.03 ÷ 2.41) × 100 ≈ 1.2% T = 2.41 ± 0.03 s (≈ 1%) Uncertainty quoted to 1 s.f., and the mean given to the same 2 decimal places.
WE 2

The potential difference across a resistor is 6.0 ± 0.2 V and the current through it is 1.5 ± 0.1 A. Calculate the resistance R = V ÷ I and its absolute uncertainty.

This is a division, so add the fractional uncertainties, then convert back to an absolute uncertainty at the end.

Resistance R = V ÷ I = 6.0 ÷ 1.5 = 4.0 Ω Add fractional uncertainties ΔV÷V = 0.2÷6.0 = 0.033 ΔI÷I = 0.1÷1.5 = 0.067 ΔR÷R = 0.033 + 0.067 = 0.10 (10%) Convert to absolute ΔR = 0.10 × 4.0 = 0.4 Ω R = 4.0 ± 0.4 Ω (10%)

💡 Top tips

⚠ Common mistakes

Up next: Graphing in Physics — we’ll turn tables of data into graphs, draw lines of best fit, read gradients and intercepts, and see how linearising a curve unlocks the physics hidden inside it.

Want this to actually click before the exam?

Book a free meeting and let’s work through the tricky bits together.

Book your free meeting