IB Physics HL Rigid Body Mechanics HL only Paper 1 & 2 ~11 min read

Angular Displacement, Velocity & Acceleration

Everything you know about straight-line motion — displacement, velocity, acceleration — has a rotational twin. A spinning wheel doesn’t travel in a line, but it still turns through an angle, at some rate, and that rate can change. These three “angular” quantities describe rotating bodies, and the beautiful part is that each one links back to its linear cousin through a single factor: the radius. Learn those links and rotational motion stops feeling foreign — it’s just circular geometry wrapped around the motion you already understand.

📘 What you need to know

Angular displacement

Angular displacement is the change in angle through which a rigid body has rotated relative to a fixed point. It’s measured in radians — the natural unit for rotation, where one radian is the angle that makes the arc length equal to the radius.

Linear and angular displacement s = rΔθ

where s is the arc length (the linear distance travelled along the circular path) in metres (m), r is the radius of the circular path in metres (m), and Δθ is the angular displacement in radians (rad). Rearranged, this gives the very definition of an angle in radians: θ = s / r, the arc length divided by the radius.

axis r r s θ θ (rad) = s / r
An angle in radians is the arc length s divided by the radius r. Multiplying back gives the linear distance s = rΔθ.
WE 1

A point on the edge of a wheel of radius 0.35 m rotates through an angular displacement of 4.0 rad. Calculate the linear distance (arc length) it travels.

Step 1 — use s = rΔθ s = r × Δθ Step 2 — substitute (angle already in radians) s = 0.35 × 4.0 s = 1.4 m The angle must be in radians for this to work — that’s the whole point of the radian.

Angular velocity

Angular velocity ω is the rate of change of angular displacement with respect to time — how fast the body is turning. It’s measured in radians per second (rad s−1):

Angular velocity ω = Δθ / Δt

The linear speed v of a point on the rotating body is related to the angular velocity by the radius:

Linear and angular velocity v =

Because one complete rotation is an angular displacement of 2π radians, angular velocity can also be written in terms of the frequency f or the time period T:

Angular velocity, frequency and period ω = v / r = 2πf = 2π / T
WE 2

A fan spins at 1200 revolutions per minute (rpm). Calculate its angular velocity, and the linear speed of a point on a blade tip 0.25 m from the axis.

Step 1 — convert rpm to rev per second, then use ω = 2πf f = 1200 ÷ 60 = 20 rev s⁻¹ ω = 2π × 20 = 125.7 rad s⁻¹ Step 2 — find the tip speed with v = rω v = 0.25 × 125.7 ω = 126 rad s⁻¹, v = 31.4 m s⁻¹ Every point turns at the same ω, but points further out (bigger r) move faster.
Here’s the intuition that ties it all together: every point on a rigid rotating body shares the same angular velocity — they all sweep the same angle in the same time. But their linear speeds differ, because v = means points further from the axis cover more distance. It’s why the outer edge of a merry-go-round whips past faster than the middle, even though the whole thing turns as one.

Angular acceleration

Angular acceleration α is the rate of change of angular velocity with time — how quickly the spin is speeding up or slowing down. It’s measured in radians per second squared (rad s−2):

Angular acceleration α = Δω / Δt

And, completing the pattern, linear acceleration a (specifically the tangential acceleration of a point) links to angular acceleration through the radius:

Linear and angular acceleration a =
WE 3

A disc speeds up from an angular velocity of 5.0 rad s−1 to 20.0 rad s−1 in 3.0 s. Calculate its angular acceleration, and the tangential linear acceleration of a point 0.10 m from the axis.

Step 1 — use α = Δω ÷ Δt α = (20.0 − 5.0) ÷ 3.0 = 15 ÷ 3.0 = 5.0 rad s⁻² Step 2 — find the linear acceleration with a = rα a = 0.10 × 5.0 α = 5.0 rad s⁻², a = 0.50 m s⁻² The same radius factor links all three pairs of quantities — displacement, velocity and acceleration.

Graphs of rotational motion

Rotational-motion graphs behave exactly like their linear counterparts — the same gradient and area rules apply, just with angular quantities. Read them the same way you read displacement, velocity and acceleration graphs.

θ time t gradient = ω ω time t gradient = α area = θ α time t area = ω
The gradient of the θ–t graph gives ω; the gradient of the ω–t graph gives α. Areas work in reverse: the area under ω–t gives θ, and the area under α–t gives ω.

Summary of linear and angular variables

Each rotational quantity is its linear partner divided by the radius (or multiplied, going the other way). This table is worth committing to memory — it turns every rotational problem into a familiar linear one:

VariableLinearAngular
Displacements = θ = s / r
Velocityv = ω = v / r
Accelerationa = α = a / r
Linear
s, v, a
÷ r →
Angular
θ, ω, α
← × r
back to linear

🛠️ Switching between linear and angular

  1. Spot which quantity you have — displacement, velocity or acceleration.
  2. Angle must be in radians — convert degrees or revolutions first (1 rev = 2π rad).
  3. Multiply by r to go from angular to linear (s = , v = , a = ).
  4. Divide by r to go from linear to angular.
  5. For spinning rates, use ω = 2πf = 2π / T to bring in frequency or period.

💡 Top tips

Quick recap: Angular displacement (rad), velocity (rad s−1) and acceleration (rad s−2) mirror their linear partners, each linked by the radius: s = , v = , a = . Angular velocity is also 2πf = 2π / T, and rotational graphs follow the same gradient and area rules as linear ones.

⚠ Common mistakes

Now you have the angular quantities and how they connect to linear motion. The next step is to describe changing rotation with equations — and just as linear motion has its four SUVAT equations, rotation has its own set of kinematic equations. That’s the angular acceleration formula set, coming up next.

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