IB Chemistry SL Topic 1 — Counting Particles by Mass Paper 1 & 2 Core skill ~10 min read

Concentration of Solutions

Concentration tells you how crowded a solution is — how much solute is packed into a given volume. It can be measured in moles, mass or parts per million, and switching between them is a core exam skill.

📘 What you need to know

What concentration means

A solution is a solute dissolved in a solvent. Concentration measures how much solute sits in each unit of volume.

Molar concentration (mol dm⁻³)

The most common measure is moles of solute per dm³ of solution. It’s often written in square brackets, e.g. [NaCl] = 0.25 mol dm⁻³.

Molar concentration concentration (mol dm-3) = moles of solute ÷ volume (dm3)

A formula triangle links moles, concentration and volume:

MOLES CONC. VOLUME × ÷ ÷
moles = concentration × volume, and concentration = moles ÷ volume. Keep volume in dm³.
WORKED EXAMPLE

Calculate the mass of sodium hydroxide, NaOH, needed to make 250 cm3 of a 0.200 mol dm-3 solution. (Ar: Na = 22.99, O = 16.00, H = 1.01)

Step 1 — find moles (convert cm³ → dm³) moles = 0.200 × 0.250 = 0.0500 mol Step 2 — molar mass of NaOH 22.99 + 16.00 + 1.01 = 40.00 g mol⁻¹ Step 3 — mass = moles × M 0.0500 × 40.00 = 2.00 g

Mass concentration (g dm⁻³)

Sometimes it’s easier to use mass per unit volume:

Mass concentration concentration (g dm-3) = mass of solute (g) ÷ volume (dm3)

Convert between the two using the molar mass:

Parts per million (ppm)

For very low concentrations — like a pollutant in water or air — we use parts per million (ppm).

WORKED EXAMPLE

Pool chlorine should be 1–3 ppm. Find the maximum mass, in kg, of chlorine in an Olympic pool of 2.5 million litres (1 litre = 1 dm3).

Step 1 — total mass in mg at 3 ppm 3 × 2.5 × 10⁶ = 7.5 × 10⁶ mg Step 2 — convert mg → kg (1 mg = 10⁻⁶ kg) 7.5 × 10⁶ × 10⁻⁶ = 7.5 kg

💡 Exam tip

Up next: Avogadro’s Law — how equal volumes of gases contain equal numbers of molecules, letting us work directly with gas volumes in reactions.

Want this explained one-to-one?

Book a free session with an experienced IB Chemistry tutor and get your trickiest topics made simple.

Book a Free Session →