IB Chemistry SL Topic 3 — Classifying Organic Compounds Paper 1 & 2 Trends ~10 min read

Homologous Series

Keep the functional group and just keep adding carbons. What you get is a family whose chemistry stays the same while its physical properties change in a smooth, predictable way — which means you can work out the properties of a molecule you have never met.

📚 What you need to know

Catenation: why there are so many compounds

Carbon forms four strong covalent bonds, and it will happily bond to itself. That property is called catenation, and it lets carbon build straight chains, branched chains and rings of essentially any length. Add a handful of functional groups to that and the number of possible molecules becomes effectively unlimited.

Rather than treat every one as a special case, we sort them into families.

What makes a homologous series

Members of a homologous series share four things and differ in one.

CLIMBING A HOMOLOGOUS SERIESeach step adds one carbon and two hydrogensmethaneCH₄C(no C–C bond to draw)ethaneC₂H⁶+ CH₂propaneC₃H₈+ CH₂butaneC₄H₁₀+ CH₂same functional group · same general formula · gradual change in physical propertiesalkanes fit CₙH₂ₙ₊₂ at every step
Every step up the series is the same step: one more carbon, two more hydrogens, same functional group.
One extra carbon and two extra hydrogens each step — that is the whole pattern. It’s why the general formula works, and why the boiling points climb so smoothly.

General formulas

Every series can be written as a single formula in terms of n, the number of carbon atoms.

SeriesGeneral formulaExample (n = 3)
alkanesCnH2n+2propane, C3H8
alkenesCnH2npropene, C3H6
alkynesCnH2n–2propyne, C3H4
alcoholsCnH2n+1OHpropan-1-ol, C3H7OH
halogenoalkanesCnH2n+1Xchloropropane, C3H7Cl
aldehydesCnH2nO, written RCHOpropanal, C3H6O
ketonesCnH2nO, written RCORpropanone, C3H6O
carboxylic acidsCnH2n+1COOHpropanoic acid, C2H5COOH
ethersCnH2n+2O, written RORmethoxyethane, C3H8O
aminesCnH2n+1NH2propylamine, C3H7NH2
Spot the overlap. Aldehydes and ketones share the general formula CnH2nO, and so do alkenes and cycloalkanes with CnH2n. Two compounds with the same general formula are not necessarily in the same series — that becomes functional group isomerism later.

Why boiling points rise

This is the one physical trend you must be able to explain, and the reasoning has three steps.

BOILING POINT RISES ALONG A SERIES-200-100010020012345678NUMBER OF CARBON ATOMSBOILINGPOINT/ °Calkanesprimary alcoholslonger chain = stronger forces
Two effects at once. Along each line, chain length raises the boiling point; between the lines, hydrogen bonding does.

🧩 The explanation examiners want

  1. Each extra –CH2 increases the number of electrons and the surface area of the molecule.
  2. More electrons means stronger London (dispersion) forces between molecules.
  3. Stronger intermolecular forces need more energy to overcome, so the boiling point rises.

The graph also shows something the alkanes alone would hide. At every chain length, the alcohols boil far higher — ethanol boils at 78 °C while ethane boils at –89 °C. That gap is nothing to do with chain length. It is hydrogen bonding between the –OH groups, which is much stronger than dispersion forces alone.

Notice too that the two lines slowly converge. As the chain gets longer, the hydrocarbon part dominates and the single hydrogen bond matters proportionally less.

Two variables, two explanations. Along a series, it is chain length and dispersion forces. Between series, it is the type of intermolecular force the functional group allows. Say which one you’re talking about.

The same reasoning explains other trends: as the chain lengthens, melting point and viscosity increase, while solubility in water decreases — the growing non-polar chain outweighs the small polar group.

WORKED EXAMPLE

An alkane has 7 carbon atoms. Deduce its molecular formula and the formula of the alcohol with the same chain length.

Alkanes are CₙH₂ₙ₊₂, with n = 7 H = (2 × 7) + 2 = 16 C₇H₁₆ — heptane Alcohols are CₙH₂ₙ₊₁OH H = (2 × 7) + 1 = 15 C₇H₁₅OH, i.e. C₇H₁₆O
WORKED EXAMPLE

Explain why butane boils at –1 °C but butan-1-ol boils at 118 °C, even though both have four carbons.

Same chain length, so dispersion forces are similar The difference cannot be chain length — it must be the functional group. Butane is non-polar: London dispersion forces only Butan-1-ol has an –OH group Its molecules form hydrogen bonds with each other, which are much stronger. more energy needed → much higher boiling point

💡 Exam tip

⚠️ Common mix-up

Up next: IUPAC Naming — the system that turns any of these structures into a name that describes it exactly, with no ambiguity.

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