IB Chemistry SL Topic 5 — The Rate of Reaction Paper 1 & 2 Practical skill ~13 min read

Measuring Reaction Rates

You cannot watch concentration directly. What you can do is find something that changes with concentration — a volume, a mass, a colour — and follow that instead. Choosing the right something is most of the skill.

📚 What you need to know

Continuous or one-off?

Methods divide into two families. Continuous methods let you take readings throughout, giving a full curve you can draw tangents on. Discontinuous methods give you a single number per experiment — usually the time to reach a fixed point — and you compare that across several runs.

Collecting a gas

COLLECTING THE GASGAS SYRINGEOVER WATERgas syringeworks for any gasinverted cylinderonly if the gas barely dissolveshydrogen and carbon dioxide can both be collected; ammonia cannot
Both give a volume against time curve. The syringe is more versatile; collection over water is cheaper and copes with larger volumes.

If the reaction produces a gas, measuring its volume is usually the easiest route. Start the clock the moment the reactants meet, and read the volume at fixed intervals.

The limitation to remember is solubility. Hydrogen and carbon dioxide can be collected over water without much loss, but a soluble gas such as ammonia or hydrogen chloride would simply dissolve and never reach the cylinder.

Following the mass

MEASURING THE MASS LOST97.42CO₂ escapescotton woollets gas out, keeps spray inthe reading falls by exactly the mass of gas that has leftno use for hydrogen — too light for the balance to notice
The cotton wool is not decoration. Without it, spray from a vigorous reaction escapes and the mass loss no longer measures only the gas.

When a gas escapes, the flask gets lighter, and a balance reading every few seconds gives you the data directly. The catch is sensitivity: the change in mass has to be big enough for the balance to see.

Compare the two gases. One mole of CO2 weighs about 44 g; one mole of H2 weighs about 2 g. The same amount of reaction produces twenty-two times less mass change with hydrogen, which is why hydrogen reactions are followed by volume and carbonate reactions by mass.
WORKED EXAMPLE

A flask containing calcium carbonate and hydrochloric acid loses 0.44 g in the first 50 s. Calculate the rate of reaction in g s–1 and in mol s–1 of CO2. (Mr CO2 = 44.01)

Step 1 — rate as a mass change 0.44 ÷ 50 = 8.8 × 10⁻³ g s⁻¹ Step 2 — convert the mass lost to moles n = 0.44 ÷ 44.01 = 0.0100 mol Step 3 — divide by time 0.0100 ÷ 50 = 2.0 × 10⁻⁴ 2.0 × 10⁻⁴ mol s⁻¹ All the mass lost is carbon dioxide, so the mass change converts straight to moles of gas — and from there, via the equation, to moles of carbonate consumed.

The other continuous methods

MethodWhat it followsUse it whenWatch out for
ColorimetryLight absorbed or transmitted by a coloured speciesA reactant or product is coloured, e.g. iodine or a transition metal ionUseless if a precipitate forms — it scatters light rather than absorbing it
ConductivityElectrical conductivity of the mixtureThe number or charge of the ions present changesNo use if the ion count barely changes
TitrationConcentration of a sample, measured directlyNothing observable changes during the reactionSamples must be quenched; discontinuous and laborious
Change in pHH+ concentrationAn acid is used up or producedpH is logarithmic, so the response is not linear in concentration
Quenching is worth understanding rather than memorising. Taking a sample and titrating it takes minutes, during which the reaction would carry on and spoil the reading — so the sample is frozen in time, usually by rapid cooling or dilution, before it is analysed.

Clock reactions

A CLOCK REACTIONNa₂S₂O₃(aq) + 2HCl(aq) → 2NaCl(aq) + SO₂(g) + H₂O(l) + S(s)START: cross clearly visibleEND: sulfur hides the crosstime itone run gives one number: the time for the cross to vanisha shorter time means a faster reaction, so rate is proportional to 1/t
Judging when the cross has “gone” is subjective, so the same person should judge every run in the same lighting.

Sometimes it is far easier to time one clearly visible event than to monitor anything continuously. In the thiosulfate reaction a precipitate of sulfur gradually clouds the solution until a cross beneath the flask can no longer be seen; you simply time it.

Rate from a clock reaction rate ∝ 1 / t

The logic is that the same fixed amount of product forms each time, so a shorter time means a faster rate. Plotting 1/t against concentration or temperature gives a graph that behaves like a rate.

WORKED EXAMPLE

In a disappearing-cross experiment, 1.0 mol dm–3 thiosulfate takes 42 s and 2.0 mol dm–3 takes 21 s. Use 1/t to compare the rates and comment.

Step 1 — calculate 1/t 1 ÷ 42 = 0.024 s⁻¹ 1 ÷ 21 = 0.048 s⁻¹ Step 2 — compare doubling the concentration doubles the rate A single run tells you almost nothing. The method only becomes useful when several runs are compared, which is exactly its main limitation.
WORKED EXAMPLE

Suggest, with a reason, the best method of following each reaction:
(a) Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
(b) CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l)
(c) the fading of a purple manganate(VII) solution as it is reduced

(a) magnesium and acid gas syringe Hydrogen is far too light for mass loss, but it has low solubility so any gas collection works. (b) carbonate and acid mass loss on a balance CO₂ is dense enough to give a measurable change, and no bung or syringe is needed. (c) manganate(VII) fading colorimetry No gas at all, but a strong colour that fades in proportion to concentration — and no precipitate to scatter the light.

💡 Exam tip

⚠️ Common mix-up

Up next: Collision Theory — the model that explains why any of these rates are what they are, and why almost every collision achieves nothing at all.

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