IB Chemistry SL Topic 5 — The Rate of Reaction Paper 1 & 2 Core idea ~12 min read

Factors Affecting Reaction Rate

Five things change how fast a reaction goes, and every one of them works through the same two quantities: how often particles collide, and what fraction of those collisions succeeds. Get that framing right and the explanations write themselves.

📚 What you need to know

The organising idea

TWO DIFFERENT LEVERSMORE COLLISIONSper secondconcentrationpressure, for gasessurface areatemperatureMORE OF THEM SUCCEEDa bigger fraction get over Eₐtemperaturecatalystand nothing elsetemperature is the only factor that pulls both levers at oncewhich is why heating speeds a reaction far more than it speeds the particles
Learn which column each factor belongs to and almost every explanation question in this topic becomes a one-liner.

Concentration and pressure

MORE PARTICLES IN THE SAME SPACEdiluteconcentratedmore of itcollisions become more likely simply because particles are closer together
Nothing about the individual particles has changed. There are simply more of them in the way.

A more concentrated solution has more particles in the same volume, so particles are closer together and collide more often. More collisions per second means more successful collisions per second, even though the fraction that succeed is exactly the same.

Pressure does the identical thing to gases. Squeezing the same number of gas particles into a smaller volume raises the number per unit volume — it is concentration by another name, which is why the explanation is the same.

Be careful about which questions pressure applies to. Increasing the pressure above a reaction between two solutions does essentially nothing, because liquids are almost incompressible. Pressure is a gas lever.

Surface area

BREAK IT UP AND YOU EXPOSE MOREone 6 cm cube6 × 36 = 216 cm²cut iteight 3 cm cubes8 × 6 × 9 = 432 cm²identical volume, exactly twice the surface exposed to the other reactant
Particles buried inside a lump cannot react with anything. Only those on the surface are available to be collided with.

When one reactant is a solid, the reaction can only happen at its surface. Break the solid into smaller pieces and the same mass exposes far more surface, so more of its particles are accessible and the collision frequency rises.

This is why powdered magnesium reacts vigorously with acid where a ribbon fizzes gently, and it is also why fine dusts — flour, custard powder, coal — are an explosion hazard.

Temperature

Temperature is the strong lever, because it is the only one that pulls both. Heating a mixture:

WORKED EXAMPLE

Raising the temperature from 300 K to 310 K roughly doubles the rate of many reactions. Yet the average particle speed increases by only about 1.7%. Explain the discrepancy.

Step 1 — the collision frequency effect Speed scales with the square root of temperature: √(310/300) = 1.017, so particles collide only about 1.7% more often. frequency effect ≈ +2% Step 2 — the energy effect The fraction of particles with energy ≥ Eₐ grows very steeply with temperature. For a typical Eₐ of 50 kJ mol⁻¹, that fraction is about 1.9 times larger at 310 K than at 300 K. proportion effect ≈ +90% Step 3 — combine 1.02 × 1.9 ≈ 2, so the rate doubles Almost all of the effect comes from the proportion, not the speed. An answer that mentions only “particles move faster” is describing the smaller half of the reason.
Examiners often ask about lowering the temperature rather than raising it, precisely because it catches students reciting a memorised answer. The theory is identical, applied backwards: fewer collisions, and a much smaller proportion with energy ≥ Ea, so the rate falls sharply.

Catalysts

A catalyst provides an alternative reaction pathway with a lower activation energy, and is chemically unchanged at the end of the reaction. Because the bar is lower, a greater proportion of the collisions already happening now qualify as successful.

Notice what a catalyst does not do. It does not make particles move faster, it does not increase the collision frequency, and it does not change ΔH or the amount of product you eventually get. The next two pages take this apart properly.

WORKED EXAMPLE

Marble chips react with excess dilute hydrochloric acid. Explain, in terms of collisions, the effect on the rate of (a) using the same mass of powdered marble, and (b) diluting the acid to half its concentration.

(a) powdering the marble Same mass, much greater surface area, so more carbonate particles are exposed to the acid. collision frequency ↑ → successful collisions per second ↑ faster, but the same total volume of CO₂ (b) halving the acid concentration Fewer H⁺ ions per unit volume, so collisions with the marble surface are less frequent. collision frequency ↓ → rate ↓ slower, and still the same total volume of CO₂ The acid is in excess in both cases, so the marble is limiting and decides the yield. Rate changes; amount does not.
WORKED EXAMPLE

Which of these would increase the rate of a reaction between a gas and a solid?
I  increasing the pressure of the gas
II  using larger lumps of the solid
III  lowering the temperature
A. I only   B. I and II   C. II and III   D. I, II and III

Work through them I ✓ more gas particles per unit volume, so more collisions II ✗ larger lumps mean LESS surface area, so fewer collisions III ✗ lower temperature means fewer collisions and a smaller proportion reaching Eₐ A Options II and III are both the right factor applied in the wrong direction — the standard trap in these questions.

💡 Exam tip

⚠️ Common mix-up

Up next: Activation Energy — the quantity every one of these explanations has been leaning on, drawn properly on an energy profile.

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