IB Chemistry HL Topic 2 — Models of Bonding & Structure Paper 1 & 2 Trends ~9 min read

s-Block and p-Block Elements

Sodium melts at 371 K. Aluminium, two places along the same row, melts at 933 K. Both are metals with the same kind of bonding, so something must be making aluminium’s grip on its electrons far tighter. Two factors explain it, and between them they handle every metallic trend on the syllabus.

📘 What you need to know

The two factors

Metallic bonding is an electrostatic attraction, so the same logic applies as anywhere else with charges: bigger charges attract more strongly, and charges closer together attract more strongly.

MORE CHARGE

STRONGER BOND 3+ more electrons, bigger pull

Al3+ releases three electrons into the sea, so the charge difference either side is large.

📏

BIGGER RADIUS

WEAKER BOND 1+ one electron, held further out

Cs+ is huge and gives up only one electron, so its hold on the sea is feeble.

The rule in one line higher charge and smaller radius → stronger electrostatic attraction → stronger metallic bond → higher melting point

Across period 3

Sodium, magnesium and aluminium form Na+, Mg2+ and Al3+. Look at their electron configurations and you can see where the extra electrons come from:

So going across, the ionic charge climbs from 1+ to 3+, the number of delocalised electrons per atom climbs from 1 to 3, and the ionic radius gets smaller because the growing nuclear charge pulls the remaining electrons in. All three changes push in the same direction: stronger bonding.

Melting points across period 3
Only the first three bars are metallic bonding Silicon is a covalent network; phosphorus onwards are simple molecular 0 500 1000 1500 melting point / K Na Mg Al Si P S Cl Ar 371 923 933 1+ → 2+ → 3+ no longer metallic bonding Charge up, radius down, so the metallic bonding tightens from Na to Al.
Do not try to explain the whole chart with metallic bonding. From silicon onwards a different structure takes over, and that is what the huge silicon bar is really telling you.
Notice that aluminium is barely above magnesium — 933 against 923 K. If you had only the theory you would expect a much bigger jump. This is a good reminder that these are broad trends, and that other factors such as how the atoms pack can shift things slightly. The IB does not ask you to explain those; it asks you to explain the trend.

Down group 1

Going down a group the charge on the ion stays fixed at 1+, so only one thing changes: the ions get bigger as each element adds another shell.

A bigger ion means the delocalised electrons sit further from the nucleus, with more inner shells shielding them. The attraction weakens, less energy is needed to break the lattice apart, and the melting point falls steadily from lithium to caesium.

Melting points down group 1
Same charge each time, so only size matters Every one of these ions is 1+, and every one is bigger than the last 0 200 400 melting point / K 454 371 337 312 302 Li Na K Rb Cs ionic radius increases, attraction weakens Bigger ion, electrons further from the nucleus, weaker metallic bond.
Caesium melts at 302 K, which is 29°C — below body temperature. Hold a sealed ampoule of it and it turns to liquid, which is a strikingly direct demonstration of weak metallic bonding.
DirectionIonic chargeIonic radiusDelocalised electronsMetallic bondingMelting point
Across a periodincreasesdecreasesincreasesstrongerrises
Down a groupstays the sameincreasesstays the sameweakerfalls

🧠 How to structure the answer every time

Three sentences, in this order. One: state what happens to the charge and the radius. Two: say what that does to the electrostatic attraction between the cations and the delocalised electrons. Three: say what that means for the energy needed, and therefore the melting point. Get those three in and you have the marks.

Worked examples

WE 1

Explain why magnesium has a much higher melting point than sodium [3]

Mark 1: the ions and the electrons Mg forms Mg²⁺ and releases 2 delocalised electrons per atom; Na forms Na+ and releases only 1. Mark 2: the size Mg2+ is also smaller than Na+, because of the greater nuclear charge. Mark 3: link to the attraction and the energy Both factors give a stronger electrostatic attraction between the cations and the electron sea, so more energy is needed to break the lattice. 371 K → 923 K all three of charge, radius and electron count are creditable — give as many as you can
WE 2

Explain the trend in melting points from Li to Cs [3]

Mark 1: state the trend and what stays constant Melting point decreases down the group. Every ion has the same 1+ charge and gives one delocalised electron. Mark 2: what does change The ionic radius increases as each element adds a shell, and shielding increases. Mark 3: consequence The delocalised electrons are further from the nucleus, so the attraction is weaker and less energy is needed. 454 K down to 302 K saying what stays the same is what proves you understand which factor is doing the work
WE 3

Silicon has by far the highest melting point in period 3. Explain why this is not evidence of very strong metallic bonding.

Step 1: identify silicon’s structure Silicon is not a metal. It forms a giant covalent network, with each atom bonded to four others. Step 2: say what must be broken to melt it Melting requires breaking many strong covalent bonds throughout the lattice, not overcoming metallic attraction. Step 3: draw the conclusion The high value comes from a different bonding model entirely, so it cannot be compared with Na, Mg and Al. Giant covalent, not metallic — a different explanation applies only the first three period 3 elements are metallic; check this before you explain any trend

💡 Exam tips

⚠ Common mix-ups

Up next: Physical Properties of Transition Elements — the metals that break the pattern entirely, melting hundreds of degrees higher than anything in the s-block.

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