IB Chemistry SL Topic 2 — From Models to Materials Paper 1 & 2 Organic ~12 min read

Addition Polymerisation

This is the friendliest reaction in organic chemistry. One double bond opens, two new single bonds form, and the process repeats a few thousand times. Nothing is lost, nothing is added, and there is only one product. If you can draw an alkene, you can draw its polymer.

📘 What you need to know

What happens to the double bond

A C=C double bond is made of two different bonds: a strong sigma bond holding the carbons together, and a weaker pi bond sitting above and below it. The pi bond is the loose one, and it is the one that breaks.

When it goes, each carbon is left with an electron available for bonding. Reach out to the carbon of a neighbouring monomer that has done the same thing, and you have a new C–C single bond. Do this along a chain of thousands of monomers and every one of them ends up joined to the two either side of it. The carbon backbone that results is saturated — there are no double bonds left anywhere.

Ethene to poly(ethene) One bond of the pair breaks. Everything else stays exactly where it was. n C C H H H H pi bond opens C C H H H H nETHENE monomer POLY(ETHENE) repeat unit of the polymerThe bonds must be drawn passing through the brackets. That is what shows the unit is joined to more of itself on both sides.
Count the atoms on each side: two carbons and four hydrogens, before and after. Addition polymerisation never loses anything, which is why the two structures look almost identical.

Drawing the repeat unit

This is worth turning into a mechanical routine, because the marks are given for details students rush past.

🧩 From monomer to repeat unit

  1. Draw the two carbons of the old double bond side by side, joined by a single line.
  2. Copy every group across unchanged. Whatever was attached to each carbon stays attached to the same carbon.
  3. Extend a bond outwards from each carbon, to the left and to the right.
  4. Draw square brackets so those two bonds cross them. The bonds must stick out beyond the brackets.
  5. Write n as a subscript at the bottom right of the closing bracket.
Nine times out of ten, a lost mark here is one of two things: the bonds stop at the brackets instead of passing through them, or the n is missing. Both take one second to check.

Going backwards: polymer to monomer

Exams often give you a section of chain and ask what it was made from. The method is the reverse of the one above, and it hangs on one fact: every addition polymer has exactly two carbons in each repeat unit of its backbone, because that is how many were in the original double bond.

Finding the monomer in a chain Chop the backbone into pairs of carbons, then put the double bond back. one repeat unit CH₂ CH CH₂ CH CH₂ CH CH₂ CHCH₃ CH₃ CH₃ put the double bond back: CH₂=CH—CH₃, which is propeneAlways cut the backbone into pairs of carbons, never singles or threes. The side groups do not move — they stay on the carbon they were drawn on.
A useful check: the methyl groups appear every second carbon. If your chosen repeat unit does not reproduce that pattern when you copy it along, you have cut the chain in the wrong place.

The family of addition polymers

MonomerPolymerWhat changes from etheneTypical use
Ethene, CH2=CH2Poly(ethene)Nothing — this is the simplest caseBags, bottles, film
Propene, CH2=CHCH3Poly(propene)One H replaced by a methyl groupCrates, rope, food containers
Chloroethene, CH2=CHClPoly(chloroethene), PVCOne H replaced by chlorinePipes, window frames, cable insulation
Tetrafluoroethene, CF2=CF2Poly(tetrafluoroethene), PTFEAll four H replaced by fluorineNon-stick coatings, seals
Atom economy: every atom in the monomer ends up in the polymer, so addition polymerisation is 100% atom efficient. That is unusual, and it is a genuine green chemistry point worth making in an extended answer.

Worked examples

WORKED EXAMPLE

Describe the repeat unit formed when chloroethene, CH2=CHCl, polymerises.

Step 1: the two carbons, now single bonded —CH₂—CHCl— Step 2: check the groups have not moved Two H on the first carbon; one H and one Cl on the second. Same as the monomer. Step 3: brackets and n Bonds extend out through both brackets, subscript n outside the closing bracket. [ —CH₂—CHCl— ]n, called poly(chloroethene) or PVC the chlorine never moves to the other carbon — a very common slip
WORKED EXAMPLE

A polymer chain is —CF2—CF2—CF2—CF2— repeating. Identify the monomer.

Step 1: cut the backbone into pairs of carbons Each pair is —CF₂—CF₂— Step 2: put the double bond back between them CF₂=CF₂ Step 3: name it Two carbons with four fluorines: tetrafluoroethene. Monomer: tetrafluoroethene, CF2=CF2 — the polymer is PTFE every carbon here is identical, so it does not matter where you make the cut
WORKED EXAMPLE

2.00 mol of propene is polymerised completely. What mass of poly(propene) is produced?

Use Ar(C) = 12.01 and Ar(H) = 1.01.

Step 1: spot the shortcut Nothing is lost, so the mass of polymer equals the mass of monomer used. Step 2: mass of propene, C3H6 M = (3 × 12.01) + (6 × 1.01) = 42.09 g mol−1 m = 2.00 × 42.09 = 84.18 g 84.2 g of poly(propene) (3 s.f.) no by-product means no mass lost — the calculation is easier than it looks

💡 Exam tip

⚠ Common mix-up

Up next: Condensation Polymers (HL) — a different way of joining monomers, where each new link throws out a small molecule, and the link that forms can later be broken by water.

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