IB Chemistry SL Topic 3 — Classifying the Elements Paper 1 & 2 Trends ~14 min read

Trends Across the Periodic Table

There are five trends on this page and only one explanation. Every single one comes down to a tug of war between the nucleus and the outer electrons, decided by three factors. Learn the three factors properly and you never have to memorise a trend again — you derive it on the spot.

📘 What you need to know

The three-factor engine

Picture the outer electron being pulled inwards by the protons and pushed outwards by nothing in particular — but partly screened from the nucleus by the electrons in between. How firmly it is held depends on three things at once.

What decides how tightly an outer electron is held Every trend on this page is one of these three winning the argument. NUCLEAR CHARGE more protons pull harder increases attractionSHIELDING inner electrons get in the way reduces attractionDISTANCE further out means weaker pull reduces attraction strength of pull on outer electronsAcross a period only one factor changes. Down a group, two do. That asymmetry is why the two directions behave so differently.
Across a period, shielding and distance barely change, so rising nuclear charge wins unopposed. Down a group, distance and shielding both rise and together they beat the extra protons.

Atomic radius

The atomic radius is the distance from the nucleus to the outermost electrons. It is awkward to define exactly — an atom has no hard edge — so it is usually measured as half the distance between the nuclei of two touching atoms of the same element.

The across-a-period trend surprises people: you are adding electrons, so surely the atom grows? No — you are adding them to a shell that is already there, while the nucleus gets stronger. The atom shrinks.

Ionic radius

Turning an atom into an ion changes its size, sometimes dramatically.

The neatest test of all this is an isoelectronic series — ions with identical electron configurations but different nuclei. Since shielding and the number of electrons are fixed, only nuclear charge varies, and the size falls steadily as the charge climbs.

An isoelectronic series: same electrons, different nucleus All four ions have 10 electrons. Only the proton count changes. O²⁻ F⁻ Na⁺ Mg²⁺8 protons 9 protons 11 protons 12 protons nuclear charge increases, so the ion gets smallerCircle sizes are illustrative, not to scale.
This is the cleanest possible demonstration of the argument. With electrons and shielding held constant, size depends on nuclear charge alone — and it does exactly what the theory predicts.

Ionisation energy

First ionisation energy X(g) → X+(g) + e the energy to remove one mole of electrons from one mole of gaseous atoms

Notice the state symbols — everything must be gaseous, or you would also be paying to separate the particles from each other. Values are in kJ mol−1 and are always positive, because you always have to pull against an attraction.

Across a period ionisation energy rises: stronger nucleus, same shielding, so the electron is harder to remove. Down a group it falls: the outer electron is further out and better shielded, so it leaves more easily. There is a sharp drop between the end of one period and the start of the next, because a brand new shell has just opened up.

Electron affinity

Electron affinity is the mirror image: the energy change when a gaseous atom gains an electron.

First electron affinity X(g) + e → X(g)

For most non-metals this releases energy, so the value is negative. Across a period it becomes more negative, because a smaller atom with a stronger nucleus attracts the incoming electron more strongly. Group 2 and group 15 break the pattern, because their subshells are full or exactly half full and an extra electron would have to pair up.

Second electron affinities are always endothermic. You are pushing a negative electron towards an ion that is already negative, and that costs energy no matter what.

Electronegativity

Electronegativity is the ability of an atom in a covalent bond to attract the shared pair of electrons towards itself. It is a comparative scale with no units, and the values are in Section 9 of the data booklet.

It increases across a period and decreases down a group, for exactly the same reasons as everything else on this page. Fluorine, at the top right of the reactive elements, is the most electronegative element of all.

Do not confuse the three. Ionisation energy is about losing an electron. Electron affinity is about gaining one. Electronegativity is about sharing one inside a bond. Only electronegativity requires a bond to exist.
PropertyAcross a period (left to right)Down a groupMain reason
Atomic radiusDecreasesIncreasesNuclear charge across; extra shells down
Ionic radiusDecreases within cations, jumps up at the first anionIncreasesCharge on the ion, then the same factors as radius
Ionisation energyIncreasesDecreasesStronger pull on the outer electron across
Electron affinityMore negativeLess negativeSmaller atom attracts the extra electron better
ElectronegativityIncreasesDecreasesBonding pair pulled closer to a small, high-charge nucleus

Worked examples

WORKED EXAMPLE

Arrange these atoms in order of decreasing atomic radius: N, Be, Mg, C.

Step 1: separate them by period Be, C and N are all in period 2. Mg is in period 3, so it has an extra shell. Step 2: place Mg An extra shell beats everything else, so Mg is the largest. Step 3: order the period 2 atoms Radius decreases across, and their groups are 2, 14 and 15. Be > C > N Mg > Be > C > N always sort by period first, then by position across the period
WORKED EXAMPLE

O2−, F, Na+ and Mg2+ all have 10 electrons. Explain why they are not the same size.

Step 1: state what is constant All four have the configuration 1s² 2s² 2p⁶, so the number of electrons and the shielding are identical. Step 2: state what varies O: 8 protons, F: 9, Na: 11, Mg: 12 Step 3: apply the argument More protons pulling on the same ten electrons means a stronger attraction and a tighter electron cloud. Radius decreases: O2− > F > Na+ > Mg2+ say “same shielding, increasing nuclear charge” explicitly — that is the mark
WORKED EXAMPLE

The first ionisation energy of caesium is far lower than that of lithium. Explain why, in terms of the three factors. [3]

Mark 1: distance Caesium’s outer electron is in the 6th shell, lithium’s is in the 2nd, so it is much further from the nucleus. Mark 2: shielding Caesium has far more inner shells, so the outer electron is much better shielded from the nuclear charge. Mark 3: the balance Caesium does have more protons, but distance and shielding together outweigh that. The outer electron is held far more weakly, so much less energy is needed to remove it notice that all three factors are named. That is what a three-mark trend answer looks like.

💡 Exam tip

⚠ Common mix-up

Up next: Group 1 Metals Reacting with Water — the first place these trends stop being abstract, because a lump of potassium skating across a water bath is the ionisation energy trend made visible.

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