IB Chemistry HL Topic 6 — Electron Transfer Paper 1 & 2 Practical skill ~9 min read

Acids with Reactive Metals

Drop a piece of zinc into hydrochloric acid and it fizzes. That fizzing is redox happening right in front of you: the metal is handing electrons to hydrogen ions, no wires or electrodes required. This page is the bridge between the reactivity series and everything electrochemical that follows.

📚 What you need to know

What is actually happening

Acid meets metal: two half-reactions at once Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g) acid supplies H⁺ 2H⁺ + 2e⁻ → H₂ reduction metal gives electrons Zn → Zn²⁺ + 2e⁻ oxidationhydrogen bubbles off the fizzing you see salt stays dissolved Zn²⁺ and Cl⁻ ionsElectrons go straight from the metal to the H⁺ ions No wires needed. This is redox happening inside the beaker.
Keep this picture in mind for the next page. A voltaic cell is this same reaction, but with the two halves separated so the electrons have to travel through a wire.

From full equation to ionic equation

Start with the full equation and strip out everything that does not change.

🧩 Getting to the ionic equation

  1. Full equation: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)
  2. Split up everything aqueous: Zn(s) + 2H+ + 2Cl → Zn2+ + 2Cl + H2(g)
  3. Cancel what is identical on both sides: the 2Cl ions are spectators.
  4. Ionic equation: Zn(s) + 2H+(aq) → Zn2+(aq) + H2(g)
  5. Solids, liquids and gases never split. Only aqueous ionic compounds do.
The ionic equation is the honest version. It shows you that swapping hydrochloric acid for sulfuric acid changes nothing about the chemistry — you would still get the same ionic equation, just with a different spectator ion. Only the name of the salt changes.

Which metals react, and how hard

MetalWith dilute acidWhat you observeWhy
Potassium, sodiumDangerously violentNot done in school labsFar above hydrogen; loses electrons extremely easily
MagnesiumFastVigorous fizzing, metal gone in under a minuteWell above hydrogen
Zinc, ironSteadyGentle stream of bubblesAbove hydrogen, but not by much
Copper, silverNo reactionNothing at allBelow hydrogen; cannot reduce H+
Strong versus weak acid: at the same concentration, hydrochloric acid fizzes faster than ethanoic acid with the same metal. A strong acid is fully ionised, so it has a much higher H+ concentration and the collisions happen more often. The total gas produced can still be the same — only the rate differs.

Worked examples

WORKED EXAMPLE

0.240 g of magnesium is added to excess dilute hydrochloric acid. Calculate the volume of hydrogen produced at STP. (Ar Mg = 24.31, molar volume = 22.7 dm3 mol−1)

Step 1: Write the equation Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g) Step 2: Moles of magnesium n = 0.240 ÷ 24.31 = 9.87 × 10−3 mol Step 3: Ratio is 1 : 1, so the same moles of H2 n(H2) = 9.87 × 10−3 mol Step 4: Convert to volume V = 9.87 × 10−3 × 22.7 = 0.224 dm3 224 cm3 of hydrogen the acid is in excess, so magnesium is the limiting reactant
WORKED EXAMPLE

25.0 cm3 of 2.00 mol dm−3 hydrochloric acid reacts with excess zinc. Find the volume of hydrogen at STP and the mass of zinc used. (Ar Zn = 65.38)

Step 1: Moles of acid n = 0.0250 × 2.00 = 0.0500 mol Step 2: The ratio is 2 HCl to 1 H2 n(H2) = 0.0500 ÷ 2 = 0.0250 mol Step 3: Volume of gas V = 0.0250 × 22.7 = 0.5675 dm3 Step 4: Zinc is also 1 : 1 with H2 m = 0.0250 × 65.38 = 1.635 g 568 cm3 of hydrogen; 1.63 g of zinc reacted this time the acid is limiting, because the zinc is in excess
WORKED EXAMPLE

Explain why copper does not react with dilute sulfuric acid, but magnesium does.

Step 1: Compare each metal with hydrogen Magnesium is above hydrogen in the reactivity series; copper is below it. Step 2: Say what that means in electron terms Magnesium loses electrons more readily than hydrogen does, so it can reduce H+ to H2. Mg + 2H+ → Mg2+ + H2 Step 3: Apply it to copper Copper holds its electrons more tightly than hydrogen does, so no transfer happens. Copper cannot reduce H+, so there is no reaction this is why copper pipes can carry slightly acidic water safely

💡 Exam tip

⚠ Common mix-up

Up next: Primary Cells — take this exact reaction, pull the two halves apart into separate beakers, and force the electrons to travel through a wire. Now you have a battery.

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