IB Chemistry HL Inquiry 2 — Collecting and Processing Data Paper 3 & IA Core skill ~13 min read

Processing Data

Now the numbers have to become an answer. This is the stage students rush, and it is the stage that separates a decent investigation from a strong one — because processing is not just getting a value, it is knowing how much to trust it.

📘 What you need to know

Two tables, not one

Your raw data table shows what you measured. Your processed table shows what you worked out from it. Keeping them apart is not fussiness — it lets the examiner check your arithmetic against your measurements, which is exactly what they want to do.

A processed table for a titration might have columns for the mean titre, the moles of titrant, the moles of the unknown, and the final concentration. Every one of those came out of a calculator, so none of them belong in the first table.

Average only what deserves averaging

The rough run exists to find roughly where the endpoint is. It was run fast, it overshot, and it is not a measurement of anything. Leave it out.

After that, keep the titres that agree within 0.10 cm3. Those are your concordant results, and they are the only ones you average. If only two agree, run another titration rather than averaging in one that clearly does not fit.

An extra check worth doing: half the range of your concordant results, (max − min) ÷ 2, is a rough uncertainty on the mean. If it comes out bigger than your instrument uncertainty, your repeats are scattering more than the burette can explain — and you should quote the bigger value.

Carrying the uncertainty through

Two rules cover almost everything you will meet. Which one applies depends only on the arithmetic you just did.

The two rules that cover almost everything Look at the arithmetic you just did, then pick the matching rule. ADDING OR SUBTRACTING add the ABSOLUTE uncertainties titre = 21.50 − 0.15 ±0.05 + ±0.05 = 21.35 ± 0.10 cm³MULTIPLYING OR DIVIDING add the PERCENTAGE uncertainties n = c × V 0.47% + 0.12% = 0.59% on nAbsolutes for plus and minus. Percentages for times and divide. Mixing these two up is the most common processing mistake there is.
A third rule for HL: if you raise a quantity to a power, multiply its percentage uncertainty by that power. Squaring something doubles the percentage uncertainty.

🧩 Propagating uncertainty, step by step

  1. Start with each raw measurement and its absolute uncertainty, straight from your table headers.
  2. Do any subtractions first — titres, mass by difference, temperature rise — adding the absolutes as you go.
  3. Convert each one to a percentage before you multiply or divide anything.
  4. Add the percentages through the rest of the calculation.
  5. Convert back to an absolute at the very end: final answer × total % ÷ 100.
WORKED EXAMPLE

Processing a titration all the way to an answer with uncertainty

25.00 ± 0.03 cm3 of an iron(II) solution is titrated with 0.0200 mol dm–3 KMnO4. Titres: rough 22.10, then 21.35, 21.40 and 21.30 cm3 (each ±0.10). The equation is MnO4 + 5Fe2+ + 8H+ → Mn2+ + 5Fe3+ + 4H2O. Find the concentration of Fe2+.

Step 1: Pick the concordant titres and average them Rough excluded. Range of the other three = 0.10, so all three are concordant. mean = (21.35 + 21.40 + 21.30) ÷ 3 = 21.35 cm³ Step 2: Moles of MnO₄⁻ n = 0.0200 × 21.35 ÷ 1000 = 4.270 × 10⁻⁴ mol Step 3: Use the ratio — 1 MnO₄⁻ reacts with 5 Fe²⁺ n(Fe²⁺) = 5 × 4.270 × 10⁻⁴ = 2.135 × 10⁻³ mol Step 4: Divide by the pipetted volume in dm³ c = 2.135 × 10⁻³ ÷ 0.02500 = 0.0854 mol dm⁻³ Step 5: Add the percentage uncertainties Burette: 0.10 ÷ 21.35 × 100 = 0.47% Pipette: 0.03 ÷ 25.00 × 100 = 0.12% total = 0.59% → 0.0854 × 0.0059 = 0.0005 c(Fe²⁺) = 0.0854 ± 0.0005 mol dm⁻³ the 5:1 ratio is exact, so it adds no uncertainty at all

Which measurement is dragging you down?

Once you have those percentages, do not throw them away. They tell you exactly which piece of apparatus is limiting your whole investigation — and that is the single most useful thing you can put in an evaluation.

Percentage uncertainty from each measurement Same titration. The third bar is what happens if you grab the wrong glassware. burette titre volumetric pipette measuring cylinder0.47% 0.12% 2.00%Swap the pipette for a measuring cylinder and it becomes your worst measurement.Improve the biggest bar. Improving any other one is wasted effort. This is how you turn a number into a specific, evidenced improvement.
With a pipette, the burette dominates — so a wider titre or a finer burette is the improvement worth suggesting. Nothing you do to the pipette will matter much.
WORKED EXAMPLE

A rate, with two uncertainties feeding into it

A gas syringe collects 18.5 ± 0.5 cm3 of hydrogen in 30.0 ± 0.2 s. Find the rate and its uncertainty, and say which measurement is worth improving.

Step 1: The rate itself rate = 18.5 ÷ 30.0 = 0.6167 cm³ s⁻¹ Step 2: Percentage uncertainty in each measurement volume: 0.5 ÷ 18.5 × 100 = 2.70% time: 0.2 ÷ 30.0 × 100 = 0.67% Step 3: It is a division, so add the percentages total = 3.37% Step 4: Back to an absolute uncertainty 0.6167 × 0.0337 = 0.0208 → 0.02 rate = 0.62 ± 0.02 cm³ s⁻¹ the volume contributes four times as much as the time — collect for longer, do not buy a better stopwatch

Significant figures and how to quote the answer

Your calculator will happily give you ten digits. Almost all of them are lies. The rule is simple: your answer can be no more precise than the least precise measurement that went into it.

SituationWhat to doExample
Multiplying or dividing measurementsMatch the fewest significant figures used0.0200 (3 s.f.) and 21.35 (4 s.f.) → answer to 3 s.f.
Adding or subtractingMatch the fewest decimal places21.50 − 0.15 = 21.35, all to 2 d.p.
Quoting the uncertaintyRound it to 1 significant figure0.000503 → 0.0005
Quoting the final valueRound it to the same decimal place as the uncertainty0.08540 ± 0.0005 → 0.0854 ± 0.0005
Exact numbers (ratios, 1000, ×10 dilutions)Ignore them — they carry no uncertaintyThe 5:1 ratio adds nothing
WORKED EXAMPLE

Rounding a messy calculator answer sensibly

A calculation gives a concentration of 0.0854013 mol dm–3 with a total percentage uncertainty of 0.59%. Write down the final answer properly.

Step 1: Work out the absolute uncertainty first 0.0854013 × 0.0059 = 0.000504 Step 2: Round the uncertainty to 1 s.f. 0.000504 → 0.0005 Step 3: Round the value to the same decimal place The uncertainty sits in the fourth decimal place, so the value stops there too. 0.0854013 → 0.0854 Step 4: Sanity check against the raw data Least precise raw value was 3 s.f., and 0.0854 is 3 s.f. Consistent. 0.0854 ± 0.0005 mol dm⁻³ work out the uncertainty first — it tells you where to stop rounding

💡 Exam tip

⚠ Common mix-up

Up next: Interpreting Results — turning that processed table into a graph, describing the trend properly, and explaining it with actual chemistry.

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