IB Biology SL Gas Exchange Systems Paper 1 & 2 Practical skill ~10 min read

Determining Stomatal Density

Paint a leaf with clear nail varnish, peel it off, and you have a perfect cast of its surface — every stoma preserved in plastic. Count them under a microscope, work out the area you were looking at, and you have a number you can compare between species or between habitats.

📚 What you need to know

The method

Five steps from leaf to number You are not looking at the leaf itself, only at an impression of its surface. 1 TAKE A LEAF Cut a leaf from a living plant, e.g. a geranium 2 PAINT Paint clear nail varnish onto the underside 3 PEEL Once dry, peel the cast off using sticky tape 4 MOUNT Lay the cast flat on a slide. No coverslip needed 5 COUNT Count stomata in at least 3 fields of view, then mean No coverslip and no water are needed — the cast is not living tissue. Just lay it flat, and it will stay in focus across the whole field of view.
Geraniums and spider plants work well because their leaves take a clean imprint. Some species have surfaces too hairy or too waxy to cast properly, which is a genuine limitation of the technique.

Apparatus

Counting rules that matter

A quiet detail worth getting right: the stage micrometer must be used at the same magnification you counted at. Change the objective lens and the field of view changes size, which changes the area, which changes your answer completely.

Turning a count into a density

Count, then work out the area you counted in The field of view is a circle, so its area comes from pi times the radius squared. diameter = 0.42 mm count = 14 stomata in this field of view STEP 1 radius r = 0.42 ÷ 2 = 0.21 mm STEP 2 area of the circle A = 3.14 × 0.21 × 0.21 A = 0.1385 mm² STEP 3 divide 14 ÷ 0.1385 = 101.1 101 stomata per mm² The units come from the working: a count divided by an area. Keep everything in millimetres and the answer lands in stomata per square millimetre.
Note how small the field of view is. At high magnification you are typically looking at an area well under a square millimetre, which is why the density number comes out so much larger than the raw count.
The calculation stomatal density = mean count ÷ (π × r²)    where r = diameter ÷ 2

Limitations of the technique

NOS: repeats are what make the number trustworthy

Reliability is the level of trust you can place in a numerical measurement. Stomatal counts are quantitative data, so reliability matters.

Terminology: anomalous results are also called outliers. Either word is fine, but be clear that you omit them from the mean rather than deleting them from the raw data.

Worked examples

WORKED EXAMPLE

A student counts 14 stomata in a field of view whose diameter is 0.42 mm. Calculate the stomatal density in stomata per mm², using π = 3.14 and giving your answer to the nearest whole stoma. [3]

Step 1: radius of the field of view r = 0.42 ÷ 2 = 0.21 mm Step 2: area of the field of view A = πr² = 3.14 × 0.21² = 3.14 × 0.0441 A = 0.1385 mm² Step 3: divide the count by the area 14 ÷ 0.1385 = 101.1 Stomatal density = 101 stomata per mm² Do not round the area too early — rounding to 0.14 would give 100, a different answer.
WORKED EXAMPLE

Four fields of view give counts of 22, 25, 24 and 51. Calculate the mean count to use, and justify your choice. [3]

Step 1: identify the anomaly 51 deviates far from the other three values, which cluster around 22 to 25. It is an anomalous result, or outlier. Step 2: omit it and calculate the mean (22 + 25 + 24) ÷ 3 = 71 ÷ 3 = 23.67 Mean count = 23.7 stomata per field of view Step 3: justify Anomalies are omitted from a mean because including them distorts it. Including 51 would give 30.5, which represents none of the readings well.
WORKED EXAMPLE

Two leaves from the same species are compared. Leaf A, grown in a dry sunny spot, has a density of 180 per mm². Leaf B, grown in shade, has 95 per mm². Suggest why a researcher should be cautious about concluding that dry conditions cause higher stomatal density. [3]

Point 1: only two leaves A sample of one leaf per condition is far too small to be reliable. Many leaves from each condition would be needed. Point 2: more than one variable differs The sunny spot differs in light intensity and temperature as well as water availability, so the cause cannot be isolated. Point 3: what would be needed Repeat counts across many leaves, with only water availability varied and other conditions controlled

💡 Exam tip

⚠ Common mix-up

That completes Gas Exchange Systems. Up next: Transport Systems — once gases have crossed the exchange surface, something has to carry them to the cells that need them.

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