IB Biology SL Topic 3 — Nerves & Signalling Paper 1 & 2 Core idea ~12 min read

Nerve Impulses

A neurone spends its whole life holding a charge across its membrane, ready. An impulse is what happens when that charge flips for about a thousandth of a second — and then flips straight back.

📚 What you need to know

What an impulse really is

This is the idea to get straight before anything else. Neurones are not wires and the impulse is not electricity flowing along them.

Instead, there is a difference in electrical charge across the cell surface membrane — a potential difference, also called the membrane potential or simply the voltage across the membrane. An impulse is a brief, local reversal of that difference, which then triggers the same reversal in the patch of membrane next door, and so on down the axon. What travels is the reversal, not the ions.

A useful picture: a line of dominoes. Nothing travels the length of the line except the falling — each domino only moves a centimetre. The wave moves; the pieces barely do.

The resting potential

When an axon is not transmitting anything, the inside is negative compared with the outside, by about 70 millivolts. That is the resting potential, and a membrane in that state is described as polarised.

The resting potential a charge held across the membrane, ready to be reversedoutside the axon + + + + + + + + inside the axon + + + + + + + +−70 mVA membrane in this state is described as polarised. Negatively charged proteins trapped inside add to the negative charge.
The minus sign in −70 mV is not decoration. It tells you the inside is the negative side, which is exactly what the reversal later undoes.

Two processes create it

The resting potential is not an accident. It is actively built and maintained by two things working together.

1. Active transport by the sodium–potassium pump

2. Different rates of diffusion back

Building the resting potential active transport sets the gradients, then diffusion does the rest outside the axon inside the axon3 Na⁺ out 2 K⁺ in K⁺ diffuses out quickly Na⁺ diffuses in slowly ATP used here 3 out for every 2 in, so the inside steadily loses positive charge The pump costs ATP. The leaking back is free. Only the pump is active transport; both channels are facilitated diffusion.
Two separate reasons the inside ends up negative: the pump’s unequal 3:2 ratio, and potassium leaking out faster than sodium leaks in.
Don’t forget the third contributor: large negatively charged proteins are stuck inside the axon and cannot cross the membrane. They add to the negative charge without moving anywhere.

The action potential

To send an impulse, the membrane has to be depolarised — the potential difference reversed. When that happens, an action potential is generated.

The reversal about −70 mV → about +40 mV → back to about −70 mV
One action potential, start to finish the whole event lasts only a few milliseconds peak, about +40 mV depolarisation repolarisation threshold, about −55 mV resting potential, about −70 mV dips below resting for a moment −70 0 +400 1 2 3 4 5 time / ms membrane potential / mVNothing happens at all until the threshold is crossed. Below threshold, the membrane simply settles back to resting.
Read the y-axis carefully. The trace passes through zero on the way up, which means the inside is briefly positive relative to the outside — a complete reversal.
Watch your vocabulary here, because three similar words do three different jobs. Polarised is the resting state. Depolarised is the reversed state. Repolarisation is the process of getting back.

Worked examples

WORKED EXAMPLE

Explain how the sodium–potassium pump helps to establish the resting potential. [3]

Step 1: name the process and its cost active transport, using ATP Step 2: give the direction and the ratio 3 Na⁺ out for every 2 K⁺ in Step 3: state the two consequences Concentration gradients are created for both ions, and more positive charge leaves than enters. Unequal active transport makes the inside more negative and sets up the gradients the 3:2 ratio is worth a mark on its own — always quote it
WORKED EXAMPLE

The inside of a resting axon is at −70 mV. During an action potential it reaches +40 mV. Calculate the total change in membrane potential.

Step 1: subtract, keeping the signs +40 − (−70) = +40 + 70 Step 2: evaluate = 110 A change of 110 mV subtracting a negative adds — answering “30 mV” means you dropped the sign
WORKED EXAMPLE

A neurone is treated with a drug that blocks ATP production. Predict the effect on the resting potential and explain why. [3]

Step 1: identify what needs ATP The sodium–potassium pump uses ATP for active transport. Step 2: what stops happening Ions are no longer pumped, so the concentration gradients gradually break down. Step 3: the consequence for the charge Ions diffuse until the difference in charge disappears. The resting potential is lost, so no impulses can be transmitted note the word “gradually” — the existing gradients take time to run down

💡 Exam tip

⚠ Common mix-up

Up next: Nerve Impulses (Skills) — what makes one axon faster than another, saltatory conduction, and how to test a correlation properly.

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