IB Biology HL DNA, RNA & the Genetic Code Paper 1 & 2 ~10 min read

Nucleic Acid Structure & Function

DNA and RNA are built from the same kind of parts, but three small differences change everything about what each one does. Then there is the rule that makes accurate copying possible: A always pairs with T, and C always pairs with G.

📘 What you need to know

DNA and RNA compared

PropertyDNARNA
Pentose sugarDeoxyriboseRibose
BasesAdenine, cytosine, guanine, thymineAdenine, cytosine, guanine, uracil
Number of strandsDouble-stranded (double helix)Single-stranded
LengthVery longRelatively short
An RNA nucleotide compared with a DNA nucleotideRNA NUCLEOTIDE P RIBOSE A C G U OH OH group on carbon 2DNA NUCLEOTIDE P DEOXY- RIBOSE A C G T H H only — one less oxygen“Deoxy” literally means “missing an oxygen”. That single missing oxygen atom is the whole difference between the two sugars.
Everything else about the two nucleotides is built the same way — phosphate to sugar, sugar to base, all covalent bonds.
🧠

Memory trick: “U are RNA”

Uracil belongs to RNA. Thymine belongs to DNA — and both “thymine” and “double” have the sound of the longer, more permanent molecule. Deoxyribose vs ribose: DNA’s sugar is the one with the extra word, and the one missing the extra oxygen.

Complementary base pairing

The bases on opposite DNA strands always pair up in the same specific way:

The pairing rules Adenine (A) — Thymine (T)  ·  2 hydrogen bonds
Cytosine (C) — Guanine (G)  ·  3 hydrogen bonds

This is not a coincidence. The hydrogen bonds that hold the two strands together can only form between these particular pairs — the shapes and charges do not fit otherwise.

Complementary base pairing Dashed lines are hydrogen bonds. Count them: A–T has two, C–G has three. backbone backbone ADENINE THYMINE 2 hydrogen bonds CYTOSINE GUANINE 3 hydrogen bonds
C–G pairs are held slightly more strongly than A–T pairs because of that third hydrogen bond.

Why this matters so much

Because the pairing is fixed, the base sequence on one strand determines the sequence of the other. We say one strand acts as a template for the other.

If you know one strand reads A–T–G–C, the other must read T–A–C–G. Nothing else is possible. This is what allows DNA to be copied very precisely during replication, which in turn ensures the genetic code is accurately copied into newly formed cells.

A useful exam consequence. Because A always pairs with T and C always pairs with G, the amount of A always equals the amount of T, and the amount of C always equals the amount of G. If a question tells you a DNA molecule is 20% adenine, then it is also 20% thymine, leaving 60% shared between C and G — so 30% each.

DNA as an information storage molecule

Despite the genetic code containing only four bases, they can combine to form a very diverse range of sequences in molecules of different lengths. This gives DNA an almost limitless capacity for storing genetic information.

Measuring the storage

One way to measure it is by counting the number of genes in an organism’s DNA. Even very simple organisms carry several thousand.

OrganismApproximate number of genes
Human20 000
Dog19 000
Water flea31 000
Bacterium (E. coli)4 300
Rice plant41 500
Look carefully at that table before you assume “more complex organism = more genes”. A rice plant has roughly twice as many genes as a human. Gene number and complexity are not the same thing, and examiners love data questions built on exactly this surprise.

The other way to measure storage is the number of base pairs in the genome:

So DNA stores an enormous amount of data with great economy.

Worked examples

WE 1

Calculate base percentages in a DNA molecule

A sample of DNA is found to contain 32% guanine. Calculate the percentage of each of the other three bases. (3 marks)

Step 1: use complementary base pairing Guanine always pairs with cytosine, so cytosine = 32%. Step 2: find what is left over G + C = 32 + 32 = 64%, so A + T together make 100 − 64 = 36%. Step 3: split the remainder A pairs with T, so the remainder is shared equally: 36 ÷ 2 = 18% each. G = 32%, C = 32%, A = 18%, T = 18% always start by pairing up the base you are given — the rest is just arithmetic
WE 2

Explain the importance of complementary base pairing

Explain how complementary base pairing allows genetic information to be copied accurately. (3 marks)

Point 1: state the rule Adenine always pairs with thymine and cytosine always pairs with guanine, because hydrogen bonds can only form between these pairs. Point 2: the consequence for the strands The base sequence on one strand therefore determines the sequence on the other, so one strand acts as a template. Point 3: link to replication During replication each strand can be used to build an exact new partner strand, so the genetic code is copied precisely into new cells. Fixed pairing → each strand is a template → accurate replication the word “template” is usually worth a mark by itself

💡 Exam tips

⚠ Common mistakes

Up next: DNA Structure — the 3′ and 5′ ends, why the strands run in opposite directions, and how Watson and Crick worked out the double helix.

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