IB Biology HL Topic 1 — Life’s Building Blocks & Variety Paper 1 & 2 Core skill ~11 min read

Water Movement in Plant Tissue

A plant cell has something an animal cell does not: a wall that pushes back. That means its water potential is made of two competing parts — one pulling water in, one pushing it out. Add them together and you can predict exactly what the cell will do.

📚 What you need to know

The two parts of water potential

Solute potential

Solute potential is simply the effect that dissolved solutes have on water potential. Pure water, with nothing dissolved in it, has a solute potential of zero. As solutes are added, solute potential decreases and becomes more negative.

The mechanism is the one from the previous page. Solute molecules bind to water molecules through hydrogen bonds as they dissolve, the potential energy available in the water is transferred into those bonds, and that reduction in potential energy lowers the water potential. Provided pressure potential stays constant, a fall in solute potential means a fall in water potential.

Pressure potential

Pressure potential is the hydrostatic pressure that the water is under. In a plant cell it is normally positive, because the expanding cytoplasm and vacuole press outwards on the inside of the cell wall. That is turgor pressure, and it is what gives plant tissue its support.

It is not always positive, though. In xylem vessels, water and dissolved minerals are pulled upwards under tension, and pressure potential there is negative.

The equation to memorise Ψw = Ψs + Ψp
Notice it is a sum, not a subtraction. Because Ψs is negative and Ψp is usually positive, the two work against each other — the solutes pull water in, the pressure pushes it back out.

Following one cell through

Take a plant cell and drop it into pure water. Work through the three snapshots below and the whole idea of turgor falls out of the arithmetic.

Turgor, worked out in kPa Solute potential plus pressure potential gives water potential. PURE WATER CELL IN PURE WATER CELL WHEN TURGID Ψp = 0 Ψs = 0 Ψw = 0Ψp = 0 Ψs = −600 Ψw = −600Ψp = +600 Ψs = −600 Ψw = 0 Water stops entering when the two sides match at 0 kPa. Pressure potential rose until it cancelled the solute potential.
The solute potential never changed. All that happened was that pressure built up until it balanced it exactly.

Read across the three panels. In pure water both components are zero, so the total water potential is 0 kPa. The cell placed in that water has solutes in its cytoplasm, giving a solute potential of −600 kPa, and no pressure yet, so its water potential is −600 kPa — lower than the surroundings, so water moves in.

As water enters, the protoplast presses on the wall and pressure potential climbs. When it reaches +600 kPa, the sum is −600 + 600 = 0 kPa. The cell now has the same water potential as the pure water outside, there is no gradient, and the net inflow stops. The cell is turgid.

Plant tissue in hypotonic and hypertonic solutions

In a hypotonic solution

The cytoplasm contains dissolved substances that lower the solute potential of the cell, which lowers the water potential inside it. Water therefore moves from the surrounding solution into the cell, down the water potential gradient.

The inward movement increases the volume of the cytoplasm, so pressure potential increases as the cytoplasm presses on the cell wall. Eventually pressure potential rises to the point where the water potential is equal inside and outside, and the inward movement stops. Cells in this state are turgid and provide structural support to the plant.

In a hypertonic solution

Now the surrounding solution has the lower solute potential, which gives it the lower water potential. Water moves out of the cell down the water potential gradient.

Losing water reduces the volume of the cytoplasm, so pressure potential inside the cell decreases. The cells lose turgor pressure and the plant begins to wilt. Push it far enough and the protoplast pulls away from the wall — plasmolysis.

Surrounding solutionWhat happens to ΨpState of the tissue
Hypotonic (dilute)Increases as water entersTurgid and supportive
IsotonicStays as it isNo change in volume
Hypertonic (concentrated)Decreases as water leavesFlaccid, then plasmolysed
Why plants wilt on a hot day. Water is lost from the leaves faster than the roots can replace it, so cells lose turgor. Without turgor pressure the tissue has nothing holding it rigid, and the whole plant droops.

Worked examples

WORKED EXAMPLE

A plant cell has a solute potential of −950 kPa and a pressure potential of +420 kPa. Calculate its water potential. [2]

Step 1 — write the equation Ψw = Ψs + Ψp Step 2 — substitute and add Ψw = (−950) + (+420) = −530 Ψw = −530 kPa The cell is not yet fully turgid — if it were, the two values would cancel to 0 kPa.
WORKED EXAMPLE

Explain, in terms of water potential, what happens when plant tissue is placed in a concentrated sucrose solution. [4]

Step 1 — compare the two water potentials The concentrated solution has a lower (more negative) solute potential, and therefore a lower water potential than the cell cytoplasm. Step 2 — direction of movement Water moves out of the cell, down the water potential gradient, through the partially permeable cell surface membrane. Step 3 — effect inside the cell The volume of the cytoplasm falls, so the pressure potential decreases and the cell loses turgor pressure. Step 4 — the visible result The tissue becomes flaccid; if enough water is lost the protoplast pulls away from the cell wall and the cell is plasmolysed. 4 marks Answer in the language the question uses. It asked for water potential, so lead with potentials, not with “concentration”.

💡 Exam tip

⚠ Common mix-up

Up next: Membrane Transport — the other ways substances cross a membrane, once water has had its turn.

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