IB Maths AA HL Topic 1 โ€” Number & Algebra Paper 1 & 2 ~9 min read

Applications of Sequences & Series

Once you know the formulas for arithmetic and geometric sequences, the next skill is recognising which one a real-world problem is asking for. IB exams love application questions โ€” savings plans, populations, doses of medicine, bouncing balls, stacking patterns. The maths is the same as the previous two notes; the work is in reading the situation correctly. Get the identification right and the rest is plug-and-chug.

๐Ÿ“˜ What you need to know

How to spot which type a problem is

Before you write any formulas, look at how the quantity changes from one term to the next. The single question to ask is: is the change a fixed amount, or a fixed factor?

Identify the type โ€” fixed amount or fixed factor?
Read the word problem Look at the change between consecutive terms “each step, the quantity …” ADDS / SUBTRACTS a fixed amount each step e.g. “+5 each week” MULTIPLIES / % CHANGE by a fixed factor each step e.g. “grows 8% each year” ARITHMETIC GEOMETRIC Find d (common difference) uโ‚™ = uโ‚ + (nโˆ’1)d Sโ‚™ = (n/2)(2uโ‚ + (nโˆ’1)d) Find r (common ratio) uโ‚™ = uโ‚ ยท r^(nโˆ’1) Sโ‚™ = uโ‚(rโฟ โˆ’ 1)/(r โˆ’ 1)   or   Sโˆž = uโ‚/(1โˆ’r)

Recognising the type from real-world clues

The wording of the problem usually gives you the type immediately. Train your eye on the verbs and units used.

โž•
Arithmetic clues
The quantity increases or decreases by a fixed amount each step.
  • Simple interest โ€” same amount of interest each year
  • Stacking objects in rows of equal height
  • Saving an extra fixed amount every month
  • Counting dots or seats in a regular pattern
  • Time-based wages with a flat raise each year
โœ–๏ธ
Geometric clues
The quantity is multiplied or scales by a fixed factor each step. Watch for percentages.
  • Compound interest โ€” interest grows on interest
  • Population, bacterial, or viral growth
  • Radioactive decay or drug elimination
  • Bouncing ball heights (each bounce is a fraction of the previous)
  • Discount/depreciation by a percentage each period
Quick percentage rule:   “increases by p%” โ†’ multiply by (1 + p/100).   “decreases by p%” โ†’ multiply by (1 โˆ’ p/100).   e.g. up 8% โ†’ factor 1.08; down 15% โ†’ factor 0.85.
If you see “each year/month/day, the quantity grows by X amount“, that’s arithmetic. If you see “each year/month/day, the quantity grows by X percent” (or “doubles”, “halves”, “scales by factor”), that’s geometric. The word “percent” is the strongest tell.

A general problem-solving recipe

๐Ÿงญ Recipe โ€” any application question

  1. Identify the type โ€” fixed amount = arithmetic; fixed factor / percentage = geometric.
  2. Identify u1 โ€” the very first term in the situation. Read the wording carefully (is “year 1” the start, or after one year of growth?).
  3. Identify d or r โ€” the constant difference, or constant ratio.
  4. Decide what’s being asked: a specific term (use un), a running total (use Sn), or “how many steps until…” (set up an inequality and solve).
  5. Write the answer in context โ€” include units, and round only at the very end. “After 14 weeks” not just “14”.
If you write down “u1 = …”, “d (or r) = …”, and “I’m finding un / Sn” before doing any algebra, you’ll catch most setup mistakes before they happen.

Worked examples

WE 1

Arithmetic โ€” total saved

Sarah is saving for a holiday. In the first week she saves $50, and each week after that she saves $8 more than the previous week. How much has she saved in total after 12 weeks?

Step 1: Identify the type “$8 more each week” โ€” fixed amount โ†’ arithmetic u1 = 50,   d = 8,   n = 12 Step 2: We want a total โ†’ use Sn S12 = (12/2)(2(50) + 11(8)) = 6 ร— (100 + 88) = 6 ร— 188 S12 = $1128
WE 2

Arithmetic โ€” when does the total exceed a threshold?

A theatre has 18 seats in the front row. Each row behind has 3 more seats than the row in front. After how many rows does the total number of seats first exceed 500?

Step 1: Identify and set up “3 more each row” โ†’ arithmetic u1 = 18,   d = 3 Step 2: Solve Sn > 500 (n/2)(2(18) + 3(n โˆ’ 1)) > 500 (n/2)(33 + 3n) > 500 n(33 + 3n) > 1000 3n2 + 33n โˆ’ 1000 > 0 Step 3: Solve via GDC or quadratic formula n โ‰ˆ 13.57   (positive root) Step 4: Smallest integer above 13.57 check: S13 = 468 < 500,   S14 = 525 > 500 โœ“ After 14 rows always verify the boundary case โ€” Sโ‚โ‚ƒ vs Sโ‚โ‚„ โ€” to confirm
WE 3

Geometric โ€” percentage growth

A startup launches with 600 users in month 1. Each subsequent month, the user base grows by 8% of the previous month. (a) Find the number of users in month 12. (b) During which month does the user base first exceed 2000?

Step 1: Identify the type “8% of previous” โ†’ geometric u1 = 600,   r = 1.08 (a) Find u12 u12 = 600 ร— 1.0811 โ‰ˆ 600 ร— 2.332 = 1399.2 โ‰ˆ 1399 users in month 12 (b) Solve un > 2000 600 ร— 1.08n โˆ’ 1 > 2000 1.08n โˆ’ 1 > 10/3 (n โˆ’ 1) ln(1.08) > ln(10/3) n โˆ’ 1 > ln(10/3) / ln(1.08) โ‰ˆ 15.65 n > 16.65 Month 17 smallest integer above 16.65 โ€” verify with month 16 (1903) vs month 17 (2056)
WE 4

Geometric โ€” drug metabolism

A patient is given a 200 mg dose of medication. Each hour, 25% of the medication present in the body is metabolised. Find the amount remaining after 6 hours.

Step 1: Identify the type “25% lost each hour” โ†’ 75% remains โ†’ geometric u1 = 200 (at hour 0),   r = 0.75 Step 2: Amount after 6 hours = 200 ร— 0.756 = 200 ร— 0.17798โ€ฆ = 35.596โ€ฆ โ‰ˆ 35.6 mg remaining “after n hours” usually corresponds to multiplying by r exactly n times โ€” count carefully
WE 5

Sum to infinity โ€” bouncing ball

A ball is dropped from a height of 5 m. After each bounce, it reaches 70% of the height of the previous bounce. Assuming it bounces infinitely many times, find the total vertical distance the ball travels.

Step 1: Visualise the motion drops 5, bounces up to 3.5, falls 3.5, bounces up to 2.45, falls 2.45, … Step 2: Total = initial drop + 2 ร— (sum of all bounce heights) bounce heights: 3.5, 2.45, 1.715, …   geometric with u1 = 3.5, r = 0.7 Step 3: Check |r| < 1 โ†’ converges โ†’ use Sโˆž sum of bounces = 3.5 / (1 โˆ’ 0.7) = 3.5 / 0.3 โ‰ˆ 11.67 m Step 4: Total distance = 5 + 2 ร— 11.67 = 5 + 23.33 โ‰ˆ 28.3 m the factor of 2 is because each bounce contributes “up + down” โ€” easy to forget

๐Ÿ’ก Top tips

โš  Common mistakes

Application questions are where the IB tests whether you understand sequences as models of real-world change, not just as algebraic objects. Spend time on the identification step โ€” it’s worth more than the algebra that follows.

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