IB Maths AA HL Topic 2 โ€” Functions Paper 1 & 2 ~7 min read

Graphing Functions & Their Key Features

When the IB asks you to “sketch” a graph, they want a clear picture with a small set of labelled features โ€” intercepts, turning points, and asymptotes. They don’t want a beautiful work of art and they don’t want a freehand mess. The skill here is knowing exactly what to mark, using your GDC efficiently to find the values, and not getting caught out by the difference between “sketch” and “draw”.

๐Ÿ“˜ What you need to know

“Sketch” vs “Draw” โ€” different jobs

Sketch (most common)
freehand, key features labelled
no graph paper or ruler needed. Show shape + intercepts + turning points + asymptotes
Draw (less common)
accurate, to scale, ruler & pencil
plot points from a table of values. Used mostly when graph paper is provided
If the question says “sketch”, don’t waste time being neat โ€” focus on labelling the right features. Examiners care about the labels much more than the artistic quality.

The key features to label

y-intercept
set x = 0
find f(0)
x-intercepts
solve f(x) = 0
also called zeros / roots
Turning points
local max / min
where the curve changes direction
Asymptotes
lines the curve approaches
vertical or horizontal
All the features at a glance
x y x-intercept x-intercept local max local min horizontal asymptote

Spotting asymptotes from the equation

Rational
y = 1x โˆ’ a + b
vertical: x = a
horizontal: y = b
Exponential
y = ax + c
horizontal: y = c
(no vertical asymptote)
Logarithmic
y = ln(x โˆ’ k)
vertical: x = k
(no horizontal asymptote)
GDC limitation:   most GDCs don’t actually draw the asymptote line. They just leave a “gap” or weird curve behaviour near it. Always work asymptotes out from the equation โ€” don’t rely on the calculator’s screen to spot them.

GDC workflow for sketching

๐Ÿงญ Recipe โ€” sketching with the GDC

  1. Plot the graph. Adjust the window so all important features are visible.
  2. Find the y-intercept (substitute x = 0).
  3. Find the x-intercepts using the zero/root function on the GDC.
  4. Find any turning points using the max/min function.
  5. Determine asymptotes from the equation (not from the GDC screen).
  6. Sketch on paper: axes labelled, general shape, all features marked with coordinates.

Worked examples

WE 1

Identify all key features of a quadratic

For f(x) = x2 โˆ’ 6x + 5, find the x-intercepts, y-intercept, and the coordinates of the vertex.

Step 1: x-intercepts โ€” solve f(x) = 0 xยฒ โˆ’ 6x + 5 = 0 โ†’ (x โˆ’ 1)(x โˆ’ 5) = 0 x = 1 or x = 5 Step 2: y-intercept โ€” substitute x = 0 f(0) = 5 Step 3: Vertex โ€” x = โˆ’b/(2a) x = 6/2 = 3 f(3) = 9 โˆ’ 18 + 5 = โˆ’4 x-intercepts: (1, 0), (5, 0); y-intercept: (0, 5); vertex: (3, โˆ’4) a parabola is fully determined by these three pieces of info โ€” opens upward since a = 1 > 0
WE 2

Find the key features of a cubic

For f(x) = x3 โˆ’ 3x, find the x-intercepts, y-intercept, and the coordinates of any local maximum or minimum points.

Step 1: x-intercepts xยณ โˆ’ 3x = 0 โ†’ x(xยฒ โˆ’ 3) = 0 x = 0, x = ยฑโˆš3 Step 2: y-intercept f(0) = 0 Step 3: Turning points โ€” use GDC max/min function local max at x = โˆ’1 โ†’ f(โˆ’1) = โˆ’1 + 3 = 2 local min at x = 1 โ†’ f(1) = 1 โˆ’ 3 = โˆ’2 x-intercepts: (โˆ’โˆš3, 0), (0, 0), (โˆš3, 0); local max: (โˆ’1, 2); local min: (1, โˆ’2) odd-power cubic: rotational symmetry about origin โ€” local max and local min are mirror images
WE 3

Sketch a rational function โ€” find both asymptotes

For g(x) = 1x โˆ’ 4 + 3, find the vertical asymptote, the horizontal asymptote, the y-intercept, and the x-intercept.

Step 1: Vertical asymptote โ€” denominator = 0 x โˆ’ 4 = 0 โ†’ x = 4 Step 2: Horizontal asymptote โ€” as x โ†’ ยฑโˆž, 1/(xโˆ’4) โ†’ 0 g(x) โ†’ 0 + 3 = 3 โ†’ y = 3 Step 3: y-intercept โ€” set x = 0 g(0) = 1/(โˆ’4) + 3 = โˆ’0.25 + 3 = 11/4 Step 4: x-intercept โ€” set g(x) = 0 1/(x โˆ’ 4) + 3 = 0 โ†’ 1/(x โˆ’ 4) = โˆ’3 x โˆ’ 4 = โˆ’1/3 โ†’ x = 11/3 vertical asymptote: x = 4; horizontal: y = 3; y-int: (0, 11/4); x-int: (11/3, 0) always work asymptotes out from the equation โ€” the GDC won’t draw them as lines
WE 4

Identify features of an exponential function

For f(x) = 3 ยท 2x โˆ’ 6, find the y-intercept, the x-intercept, and the equation of the horizontal asymptote.

Step 1: y-intercept f(0) = 3 ยท 1 โˆ’ 6 = โˆ’3 Step 2: x-intercept โ€” solve f(x) = 0 3 ยท 2หฃ โˆ’ 6 = 0 โ†’ 2หฃ = 2 x = 1 Step 3: Horizontal asymptote โ€” as x โ†’ โˆ’โˆž, 2หฃ โ†’ 0 f(x) โ†’ 0 โˆ’ 6 = โˆ’6 โ†’ y = โˆ’6 y-int: (0, โˆ’3); x-int: (1, 0); horizontal asymptote: y = โˆ’6 exponentials of form aยทbหฃ + c have ONE horizontal asymptote (y = c) and NO vertical asymptote
WE 5

Find features of a sum of two functions using the GDC

Let h(x) = x2 + 4x. Use a GDC to find the local minimum to 3 sf, and state the equation of the vertical asymptote.

Step 1: Vertical asymptote โ€” denominator of 4/x is 0 when x = 0 x = 0 makes the function undefined โ†’ vertical asymptote at x = 0 Step 2: Plot h(x) on the GDC and use min function local minimum at approximately x โ‰ˆ 1.26, y โ‰ˆ 4.76 Step 3: Verify by setting h'(x) = 0 h'(x) = 2x โˆ’ 4/xยฒ = 0 โ†’ 2xยณ = 4 โ†’ x = ยณโˆš2 โ‰ˆ 1.26 h(ยณโˆš2) = (ยณโˆš2)ยฒ + 4/ยณโˆš2 โ‰ˆ 1.587 + 3.175 โ‰ˆ 4.76 local min โ‰ˆ (1.26, 4.76); vertical asymptote: x = 0 GDC is the workhorse here โ€” finding the exact minimum by hand requires calculus, which is overkill for a sketch
WE 6

Identify symmetry from key features

The function f(x) = x2 โˆ’ 2x โˆ’ 8 has x-intercepts at (โˆ’2, 0) and (4, 0). State the equation of the axis of symmetry and the coordinates of the vertex.

Step 1: Axis of symmetry โ€” midway between the roots x = (โˆ’2 + 4) / 2 = 1 Step 2: Vertex โ€” substitute x = 1 into f f(1) = 1 โˆ’ 2 โˆ’ 8 = โˆ’9 axis of symmetry: x = 1; vertex: (1, โˆ’9) for a quadratic with two real roots, the axis of symmetry is always the average of the roots โ€” quick shortcut

๐Ÿ’ก Top tips

โš  Common mistakes

A clear sketch with the right labels can earn more marks than a long algebraic derivation. The next note covers intersecting graphs โ€” using sketches and the GDC’s intersect function to solve equations like f(x) = g(x), which is one of the most useful problem-solving tools across the whole syllabus.

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