IB Maths AA HLTopic 2 β FunctionsPaper 1 & 2~7 min read
Odd & Even Functions
Some functions have a special kind of symmetry. Even functions look the same on both sides of the y-axis (mirror image). Odd functions look the same after a 180Β° spin about the origin (rotational). Most functions are neither β but if a function is odd or even, the property often makes integration, sketching, and series questions much faster. The test is one quick algebraic check: substitute βx and see what happens.
π What you need to know
Even: f(βx) = f(x) for all x. Graph has reflective symmetry in the y-axis.
Odd: f(βx) = βf(x) for all x. Graph has rotational symmetry (180Β°) about the origin.
Most functions are neither. If f(βx) doesn’t equal f(x) AND doesn’t equal βf(x), it’s neither.
Even powers (x0, x2, x4, β¦) are even. Odd powers (x, x3, x5, β¦) are odd. That’s where the names come from.
Trig: cosx, secx are even. sinx, tanx, cosecx, cotx are odd.
|x| is even. Constants (e.g. f(x) = 7) are even.
Combination rules: even Β± even = even; odd Β± odd = odd; even Γ even = even; odd Γ odd = even; even Γ odd = odd.
The two definitions
Even β mirror in y-axis
f(βx) = f(x)
e.g. x2, x4, cosx, |x|, constants
Odd β 180Β° rotation about O
f(βx) = βf(x)
e.g. x, x3, x5, sinx, tanx
Power-rule mnemonic: an integer power xn is even when n is even, and odd when n is odd. Same word, same meaning.
What the symmetry looks like
Even is a mirror; odd is a spin
Quick GDC trick: turn your calculator upside down (180Β° rotation). If the graph looks the same, it’s odd. Sounds silly but it works.
Combination rules β predict without testing
Once you know the type of each piece, you can often work out the type of the whole expression without algebra:
Sum/difference
even Β± even = even odd Β± odd = odd
mixing even and odd β usually neither
Product (same type)
even Γ even = even odd Γ odd = even
two negatives multiply to positive
Product (mixed)
even Γ odd = odd
odd “wins” against even
Mnemonic: with multiplication, treat even = +1 and odd = β1, then multiply the signs. Two odds give +1 (even). One of each gives β1 (odd). Easy to remember.
How to test algebraically
π§ Recipe β testing for odd/even
Compute f(βx) by replacing every x with βx in the expression.
Simplify using rules like (βx)2 = x2, sin(βx) = βsinx, cos(βx) = cosx.
Compare: if it equals f(x) β even. If it equals βf(x) β odd. Otherwise β neither.
Worked examples
WE 1
Test if a polynomial is odd, even, or neither
Show that f(x) = 5x3 β 2x is odd.
Step 1: Compute f(βx)f(βx) = 5(βx)Β³ β 2(βx)= β5xΒ³ + 2xStep 2: Compare to Β±f(x)βf(x) = β(5xΒ³ β 2x) = β5xΒ³ + 2xf(βx) = βf(x) βf is oddall terms have odd powers of x β expected to be odd
WE 2
Test a polynomial β even case
Show that f(x) = 2x4 + 3x2 β 1 is even.
Step 1: Compute f(βx)f(βx) = 2(βx)β΄ + 3(βx)Β² β 1= 2xβ΄ + 3xΒ² β 1Step 2: Compare to f(x)f(βx) = f(x) βf is evenall terms have even powers (counting the β1 as xβ°) β expected to be even
WE 3
A function that is neither odd nor even
Determine whether f(x) = x3 + 4x2 + x is odd, even, or neither.
Step 1: Compute f(βx)f(βx) = (βx)Β³ + 4(βx)Β² + (βx)= βxΒ³ + 4xΒ² β xStep 2: Compare both waysf(x) = xΒ³ + 4xΒ² + x β not equal to f(βx), not evenβf(x) = βxΒ³ β 4xΒ² β x β not equal to f(βx), not oddf is neither odd nor evenmixing odd-power terms (xΒ³, x) with an even-power term (4xΒ²) usually gives neither
WE 4
Use combination rules β show even
Show, using combination rules, that g(x) = x2 cos(3x) + 7 is even.
Identify each piecexΒ² is even (even power)cos(3x) is even (cos of any expression in x: cos(β3x) = cos(3x))7 is even (constant)Apply combination rulesxΒ² Β· cos(3x): even Γ even = eveneven + even = eveng(x) is evenverify: g(βx) = (βx)Β²cos(β3x) + 7 = xΒ² cos(3x) + 7 = g(x) β
WE 5
Use combination rules β show odd
Show that h(x) = 2x3 β sin(5x) is odd.
Identify each piece2xΒ³ is odd (constant Γ odd)sin(5x) is odd (sin of an odd-input expression: sin(β5x) = βsin(5x))Apply combination rulesodd β odd = oddVerify directlyh(βx) = 2(βx)Β³ β sin(β5x) = β2xΒ³ + sin(5x)= β(2xΒ³ β sin(5x)) = βh(x) βh(x) is odda multiplicative constant (2 here) doesn’t change parity β only the structure of the variable parts does
WE 6
Identify the type from a graph description
A graph of y = f(x) is symmetric about the y-axis: every point (a, b) on the curve has a partner (βa, b). State whether f is odd, even, or neither, with a reason.
Identify the symmetry typereflection in the y-axis β even(if it had been 180Β° rotation about origin β odd)f is even, because (a, b) and (βa, b) both lie on the graph, so f(βa) = f(a) = b for all agraphs alone are usually enough β pick any input and check the partner point on the other side
π‘ Top tips
Power test for polynomials: all-even powers β even; all-odd powers β odd; mixed β neither.
Trig in one line: cos and sec are even; sin, tan, cot, cosec are odd.
Combination rules save algebra. Identify each piece’s parity, multiply/sum the parities to get the whole.
Constants count as even, including the constant term in a polynomial. So x3 + 5 is neither (odd + even).
Function inside a function: if you have sin(u) where u is an odd expression in x, sin(u) is odd. If u is even, sin(u) is even.
Use the graph test: y-axis mirror β even; 180Β° rotation about origin β odd.
If f(0) β 0 and f is odd, something’s wrong β every odd function passes through the origin.
β Common mistakes
Forgetting that the constant term breaks the parity.x3 is odd, but x3 + 1 is neither.
Treating cos as odd by analogy with sin. Cos is even β make sure you’ve memorised which is which.
Sign errors with negative powers. (βx)3 = βx3, but (βx)2 = +x2. Watch the parity of the power.
Concluding “neither” when a function is just non-trivially odd. Always factor out a minus sign at the end of f(βx) to compare with βf(x).
Applying combination rules wrong. Even Γ odd = odd, not even. The classic slip-up.
Forgetting that “neither” is a valid answer. Most polynomials with mixed-parity terms are neither.
Assuming a function with a symmetric graph must be even. Symmetry about the y-axis gives even; symmetry about the origin (rotational) gives odd. Check which kind.
Odd and even functions become especially powerful in calculus β the integral of an odd function over a symmetric interval [βa, a] is automatically zero, and integrating an even function only requires the right half (then double it). The next note shifts to periodic functions: graphs that repeat the same pattern over and over β sin, cos, tan and their relatives.
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