IB Maths AA HL Topic 2 — Functions Paper 1 & 2 ~7 min read

Odd & Even Functions

Some functions have a special kind of symmetry. Even functions look the same on both sides of the y-axis (mirror image). Odd functions look the same after a 180° spin about the origin (rotational). Most functions are neither — but if a function is odd or even, the property often makes integration, sketching, and series questions much faster. The test is one quick algebraic check: substitute −x and see what happens.

📘 What you need to know

The two definitions

Even — mirror in y-axis
f(−x) = f(x)
e.g. x2, x4, cosx, |x|, constants
Odd — 180° rotation about O
f(−x) = −f(x)
e.g. x, x3, x5, sinx, tanx
Power-rule mnemonic:   an integer power xn is even when n is even, and odd when n is odd. Same word, same meaning.

What the symmetry looks like

Even is a mirror; odd is a spin
EVEN — reflection in y-axis y-axis (−a, b) (a, b) f(−x) = f(x) — same height on both sides ODD — 180° rotation about O (−a, −b) (a, b) f(−x) = −f(x) — opposite sign on both sides
Quick GDC trick: turn your calculator upside down (180° rotation). If the graph looks the same, it’s odd. Sounds silly but it works.

Combination rules — predict without testing

Once you know the type of each piece, you can often work out the type of the whole expression without algebra:

Sum/difference
even ± even = even
odd ± odd = odd
mixing even and odd → usually neither
Product (same type)
even × even = even
odd × odd = even
two negatives multiply to positive
Product (mixed)
even × odd = odd
odd “wins” against even
Mnemonic:   with multiplication, treat even = +1 and odd = −1, then multiply the signs. Two odds give +1 (even). One of each gives −1 (odd). Easy to remember.

How to test algebraically

🧭 Recipe — testing for odd/even

  1. Compute f(−x) by replacing every x with −x in the expression.
  2. Simplify using rules like (−x)2 = x2, sin(−x) = −sinx, cos(−x) = cosx.
  3. Compare: if it equals f(x) → even. If it equals −f(x) → odd. Otherwise → neither.

Worked examples

WE 1

Test if a polynomial is odd, even, or neither

Show that f(x) = 5x3 − 2x is odd.

Step 1: Compute f(−x) f(−x) = 5(−x)³ − 2(−x) = −5x³ + 2x Step 2: Compare to ±f(x) −f(x) = −(5x³ − 2x) = −5x³ + 2x f(−x) = −f(x) ✓ f is odd all terms have odd powers of x → expected to be odd
WE 2

Test a polynomial — even case

Show that f(x) = 2x4 + 3x2 − 1 is even.

Step 1: Compute f(−x) f(−x) = 2(−x)⁴ + 3(−x)² − 1 = 2x⁴ + 3x² − 1 Step 2: Compare to f(x) f(−x) = f(x) ✓ f is even all terms have even powers (counting the −1 as x⁰) → expected to be even
WE 3

A function that is neither odd nor even

Determine whether f(x) = x3 + 4x2 + x is odd, even, or neither.

Step 1: Compute f(−x) f(−x) = (−x)³ + 4(−x)² + (−x) = −x³ + 4x² − x Step 2: Compare both ways f(x) = x³ + 4x² + x   → not equal to f(−x), not even −f(x) = −x³ − 4x² − x   → not equal to f(−x), not odd f is neither odd nor even mixing odd-power terms (x³, x) with an even-power term (4x²) usually gives neither
WE 4

Use combination rules — show even

Show, using combination rules, that g(x) = x2 cos(3x) + 7 is even.

Identify each piece x² is even (even power) cos(3x) is even (cos of any expression in x: cos(−3x) = cos(3x)) 7 is even (constant) Apply combination rules x² · cos(3x): even × even = even even + even = even g(x) is even verify: g(−x) = (−x)²cos(−3x) + 7 = x² cos(3x) + 7 = g(x) ✓
WE 5

Use combination rules — show odd

Show that h(x) = 2x3 − sin(5x) is odd.

Identify each piece 2x³ is odd (constant × odd) sin(5x) is odd (sin of an odd-input expression: sin(−5x) = −sin(5x)) Apply combination rules odd − odd = odd Verify directly h(−x) = 2(−x)³ − sin(−5x) = −2x³ + sin(5x) = −(2x³ − sin(5x)) = −h(x) ✓ h(x) is odd a multiplicative constant (2 here) doesn’t change parity — only the structure of the variable parts does
WE 6

Identify the type from a graph description

A graph of y = f(x) is symmetric about the y-axis: every point (a, b) on the curve has a partner (−a, b). State whether f is odd, even, or neither, with a reason.

Identify the symmetry type reflection in the y-axis ↔ even (if it had been 180° rotation about origin → odd) f is even, because (a, b) and (−a, b) both lie on the graph, so f(−a) = f(a) = b for all a graphs alone are usually enough — pick any input and check the partner point on the other side

💡 Top tips

⚠ Common mistakes

Odd and even functions become especially powerful in calculus — the integral of an odd function over a symmetric interval [−a, a] is automatically zero, and integrating an even function only requires the right half (then double it). The next note shifts to periodic functions: graphs that repeat the same pattern over and over — sin, cos, tan and their relatives.

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