IB Maths AA SL Topic 1 โ€” Number & Algebra Paper 1 & 2 ๐ŸŽฏ Skill ~4 min practice

AA SL Geometric Series Sums skills

A geometric series multiplies each term by the same ratio. There are two formulas โ€” one for finite sums (Sn) and one for infinite sums (Sโˆž). The trick is choosing correctly and checking convergence before you reach for the infinite version.

The Method

GP: u1, u1r, u1rยฒ, u1rยณ, … u1 = first term ยท r = common ratio ยท n = number of terms
Formula 1

Finite Sum Sn

Sn = u1(rn โˆ’ 1)r โˆ’ 1
use for the first n terms
Formula 2

Infinite Sum Sโˆž

Sโˆž = u11 โˆ’ r
use when sum is infinite ยท only if |r| < 1
โš ๏ธ

Infinite sum exists ONLY when |r| < 1

If |r| โ‰ฅ 1 the terms don’t shrink and the series doesn’t converge. Always state |r| < 1 before you apply Sโˆž = u1 / (1 โˆ’ r).

Three steps every time

  1. Identify what you have. Pick out u1, r, and either n (finite) or “โˆž” (infinite). r = any term รท previous term.
  2. Choose the formula. Finite “first n terms”? โ†’ Formula 1. “Sum to infinity”? โ†’ Check |r| < 1 first, then Formula 2.
  3. Plug in carefully. Watch the order of (rn โˆ’ 1) and (r โˆ’ 1) โ€” both numerator and denominator have r minus 1, not 1 minus r.

Worked examples

WE 1 EASY

Find the sum of the first 8 terms of: 3, 6, 12, 24, …

step 1 โ€” identify uโ‚ = 3, r = 6 รท 3 = 2, n = 8step 2 โ€” Formula 1 (finite) Sโ‚ˆ = 3(2โธ โˆ’ 1) / (2 โˆ’ 1) = 3(256 โˆ’ 1) / 1 = 3 ร— 255Sโ‚ˆ = 765 r = (any term) รท (previous term) โ€” pick any pair to find it!
WE 2 MEDIUM

Find the sum to infinity of: 12, 4, 4/3, 4/9, …

step 1 โ€” identify uโ‚ = 12, r = 4 รท 12 = โ…“step 2 โ€” check convergence |โ…“| < 1 โœ“ โ†’ Sโˆž existsstep 3 โ€” Formula 2 Sโˆž = 12 / (1 โˆ’ โ…“) = 12 / (โ…”) = 12 ร— (3/2) = 18Sโˆž = 18 always state |r| < 1 before applying Sโˆž โ€” it’s a marking criterion!
WE 3 HARD

A geometric series has u1 = 5 and r = 2. Find the smallest value of n for which Sn > 1000.

step 1 โ€” set up the inequality 5(2โฟ โˆ’ 1) / (2 โˆ’ 1) > 1000 5(2โฟ โˆ’ 1) > 1000 2โฟ โˆ’ 1 > 200 2โฟ > 201step 2 โ€” solve using logs n log 2 > log 201 n > log 201 / log 2 โ‰ˆ 7.65step 3 โ€” round UP to next integer n must be a whole number โ‰ฅ 7.65smallest n = 8 “smallest n such that Sn > k” โ€” always round UP, never down!

Practice questions

Try each one yourself first, then click the question to reveal the worked answer. Identify r first โ€” that tells you which formula to use.
Q1 EASY Find the sum of the first 6 terms of: 2, 6, 18, 54, … Show answer โ–ผHide answer โ–ฒ
uโ‚ = 2, r = 3, n = 6 โ†’ Formula 1 Sโ‚† = 2(3โถ โˆ’ 1) / (3 โˆ’ 1) = 2(729 โˆ’ 1) / 2 = 728 Sโ‚† = 728
Q2 EASY Find the sum to infinity of: 16, 8, 4, 2, … Show answer โ–ผHide answer โ–ฒ
uโ‚ = 16, r = ยฝ โ€” |r| < 1 โœ“ Sโˆž = 16 / (1 โˆ’ ยฝ) = 16 / (ยฝ) Sโˆž = 32
Q3 MEDIUM A GP has uโ‚ = 80 and r = โˆ’ยฝ. Find Sโˆž. Show answer โ–ผHide answer โ–ฒ
|โˆ’ยฝ| = ยฝ < 1 โœ“ โ†’ converges Sโˆž = 80 / (1 โˆ’ (โˆ’ยฝ)) = 80 / (3/2) = 80 ร— (2/3) Sโˆž = 160/3 negative r is fine โ€” it’s |r| that matters for convergence!
Q4 MEDIUM Find the sum of the first 10 terms of: 100, 50, 25, 12.5, … Show answer โ–ผHide answer โ–ฒ
uโ‚ = 100, r = ยฝ, n = 10 โ†’ Formula 1 Sโ‚โ‚€ = 100((ยฝ)ยนโฐ โˆ’ 1) / (ยฝ โˆ’ 1) = 100(1/1024 โˆ’ 1) / (โˆ’ยฝ) = 100(โˆ’1023/1024) / (โˆ’ยฝ) = 200 ร— 1023/1024 = 199.8 (4 sf) Sโ‚โ‚€ โ‰ˆ 199.8 use the GDC for messy fractions โ€” no shame in it on Paper 2!
Q5 HARD A GP has uโ‚ = 4 and Sโˆž = 10. Find r. Show answer โ–ผHide answer โ–ฒ
step 1 โ€” set up 10 = 4 / (1 โˆ’ r)step 2 โ€” solve for r 10(1 โˆ’ r) = 4 10 โˆ’ 10r = 4 10r = 6r = 3/5 = 0.6 check: |0.6| < 1 โœ“ โ†’ series does converge as required

โš  Common mistakes

๐Ÿ“–

Want the theory?

Read the full Geometric Sequences & Series notes for the link to un = u1rnโˆ’1, why convergence requires |r| < 1, and applications to compound interest and depreciation.

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