IB Maths AI HL Number Toolkit Paper 1 & 2 a × 10n form ~6 min read

Standard Form

Standard form writes any number — however huge or tiny — as a single digit-string between 1 and 10 multiplied by a power of 10. This note shows how to convert numbers into that form and how to multiply, divide, add and subtract them while keeping the answer in standard form.

📘 What you need to know

Writing numbers in standard form

A number in standard form is a × 10n: the value a carries the significant digits and must satisfy 1 ≤ a < 10, while the integer n records the size by counting decimal-point jumps.

Standard form a × 10n,   1 ≤ a < 10,   n ∈ ℤ n > 0 for large numbers — n < 0 for small numbers

For a large number, place the decimal point after the first non-zero digit and count how many places it jumped — that count is n, and it is positive. For a small number (less than 1) the decimal moves the other way, so n is negative.

The anatomy of standard forma × 10n digit-string, 1 ≤ a < 10 whole number nLARGE NUMBER 52000 4 places left 5.2 × 104 n is positiveSMALL NUMBER 0.0007 4 places right 7 × 10−4 n is negative
The decimal point jump sets n: jumping left for a large number gives a positive power, jumping right for a small number gives a negative power.

Multiplying and dividing

To multiply or divide numbers in standard form, deal with the two parts separately: combine the a-parts by ordinary arithmetic, and combine the powers of 10 using the index laws.

Index laws for the powers of 10 10m × 10n = 10m+n 10m ÷ 10n = 10mn add the powers to multiply, subtract them to divide

If the new a-part is not between 1 and 10 — for example 12 or 0.25 — rewrite that part in standard form and add its power onto the running total.

Adding and subtracting

You cannot add the a-parts directly unless the powers of 10 match. So first find the higher power of 10, then rewrite the other number with that same power — its a-part will no longer be between 1 and 10, and that is fine for this step.

Once both numbers share a power of 10, add or subtract the a-parts and write the result back in standard form.

GDC shortcut: in scientific mode your calculator will multiply, divide, add and subtract numbers in standard form directly and return the answer already in a × 10n form.

🧭 Recipe — standard form in five steps

  1. Find a: read off the significant digits as a number between 1 and 10.
  2. Find n: count how many places the decimal point moves to reach a.
  3. Fix the sign of n: positive for large numbers, negative for numbers below 1.
  4. For a calculation: handle the a-parts and the powers of 10 separately (add/subtract powers; match powers before adding numbers).
  5. Tidy up: if the a-part is outside 1 ≤ a < 10, rewrite it in standard form and combine the powers.

Worked examples

WE 1

Writing a large number

Light travels about 9 460 000 000 000 km in one year. Write this distance in standard form.

find a — digit-string between 1 and 10 a = 9.46 count the decimal jumps to reach a 9 460 000 000 000 → 9.46 — jumps 12 places left 9.46 × 1012 km large number, so the power is positive.
WE 2

Writing a small number

A red blood cell has a diameter of about 0.0000078 m. Write this length in standard form.

find a — digit-string between 1 and 10 a = 7.8 count the decimal jumps to reach a 0.0000078 → 7.8 — jumps 6 places right 7.8 × 10−6 m number below 1, so the power is negative.
WE 3

Multiplying in standard form

Evaluate (6 × 104) × (7 × 109), giving your answer in standard form.

multiply the a-parts, add the powers 6 × 7 = 42 104 × 109 = 1013 42 is not between 1 and 10 — rewrite it 42 = 4.2 × 101 ⇒ 4.2 × 101 × 1013 4.2 × 1014 when the a-part overshoots 10, bump the power up by 1.
WE 4

Dividing in standard form

Evaluate (4.5 × 106) ÷ (9 × 10−2), giving your answer in standard form.

divide the a-parts, subtract the powers 4.5 ÷ 9 = 0.5 106 ÷ 10−2 = 106−(−2) = 108 0.5 is not between 1 and 10 — rewrite it 0.5 = 5 × 10−1 ⇒ 5 × 10−1 × 108 5 × 107 subtracting a negative power adds — and a small a-part drops the power by 1.
WE 5

Adding in standard form

Evaluate (5 × 107) + (8 × 106), giving your answer in standard form.

match the powers — use the higher one, 107 8 × 106 = 0.8 × 107 now add the a-parts (5 + 0.8) × 107 = 5.8 × 107 5.8 × 107 rewrite the smaller number to share the bigger power, then add.
WE 6

Full question: a space probe

A space probe is 4.5 × 109 km from Earth. Radio signals travel at 3 × 105 km/s. (a) Write the distance as an ordinary number. (b) Find the time, in seconds, for a signal to reach the probe, in standard form. (c) A second probe is 9 × 108 km from Earth — how much further away is the first probe? Give your answer in standard form.

(a) move the decimal 9 places right 4.5 × 109 = 4 500 000 000 km (b) time = distance ÷ speed (4.5 ÷ 3) = 1.5  and  109 ÷ 105 = 104 (c) subtract — match powers at 109 9 × 108 = 0.9 × 109 ⇒ (4.5 − 0.9) × 109 (a) 4 500 000 000 km · (b) 1.5 × 104 s · (c) 3.6 × 109 km division: a-parts and powers separately; subtraction: match the powers first.

💡 Top tips

âš  Common mistakes

Next up: Approximation — rounding to significant figures and decimal places, and knowing when a context forces you to round up. The standard-form habit carries straight over: pin down the leading digits first, then decide the size of the number.

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