IB Maths AI HL Further Functions & Graphs Paper 2 GDC intersect, simultaneous ~7 min read

Intersecting Graphs

Where two graphs meet on the GDC is where the equation f(x) = g(x) is satisfied — the x-coordinates of the intersections are the solutions. For AI HL Paper 2, this turns nearly every “solve” question into “plot, then press intersect”.

📘 What you need to know

Finding intersections with the GDC

Two graphs intersect where their y-values agree for the same x. Numerically that’s a simultaneous solution: the x– and y-coordinates of the intersection satisfy both equations at once. The GDC’s intersect function does the heavy lifting — plot the two graphs, select the curves, tap the intersection, and the coordinates appear.

Watch the window: graphs can cross more than once. Always scroll out or change the scale until you’re confident you’ve found every intersection.

Solving equations from intersections

Any equation in x can be solved by rewriting it as LHS = RHS and finding where the two sides intersect when plotted. Solve f(x) = a by plotting y = f(x) against the horizontal line y = a. Solve f(x) = g(x) by plotting both and reading off the x-coordinates where they meet. Either way, the solutions to the equation are exactly the x-coordinates of intersection.

Solving an equation = reading the x-coordinates of intersection f(x) = a — line meets curve x y y = a x1 x2 x3 y = f(x)solutions: x₁, x₂, x₃ f(x) = g(x) — curve meets curve x y x1 x2 y = f(x) y = g(x)solutions: x₁ and x₂
The solutions of f(x) = a or f(x) = g(x) are the x-coordinates where the two graphs meet — not the y-coordinates.
Solving equations graphically solve f(x) = a: plot y = f(x) and y = a; solutions = x-coordinates of intersection solve f(x) = g(x): plot both; solutions = x-coordinates of intersection

Counting the number of solutions

Sometimes the question asks only for the number of solutions, not the values themselves. The answer is simply the number of intersection points visible on the graph. Make sure the viewing window is wide enough to include every intersection — a transcendental equation like 2x = 3x can have two solutions you’d miss with a default window.

🧭 Recipe — solving an equation using graphs

  1. Rearrange the equation into the form f(x) = g(x) (or f(x) = a if one side is constant).
  2. Plot y = f(x) and y = g(x) on the GDC.
  3. Adjust the window until all intersections are visible.
  4. Use the intersect tool for each intersection point.
  5. Read off the x-coordinates as the solutions; if asked, state the y-coordinates too for the intersection points.

Worked examples

WE 1

Intersection of two lines

Find the point of intersection of y = 2x + 1 and y = −x + 7.

set the right-hand sides equal 2x + 1 = −x + 7 3x = 6 ⇒ x = 2 substitute back y = 2(2) + 1 = 5 intersection: (2, 5) check: −2 + 7 = 5 ✓
WE 2

Line meets a quadratic

Find the points of intersection of y = x2 − 3x + 2 and y = x − 1.

set f(x) = g(x) x² − 3x + 2 = x − 1 x² − 4x + 3 = 0 factor (x − 1)(x − 3) = 0 ⇒ x = 1 or x = 3 find y-values from the line (simpler) x = 1: y = 0 x = 3: y = 2 intersections: (1, 0) and (3, 2)
WE 3

Cubic meets a line

Find the coordinates of the points where f(x) = x3 − 4x and g(x) = 2x intersect, to 2 d.p.

set f = g x³ − 4x = 2x x³ − 6x = 0 factor x(x² − 6) = 0 ⇒ x = 0, ±√6 numerical values x ≈ 0, ±2.45 y = 2x: 0, ±4.90 (−2.45, −4.90), (0, 0), (2.45, 4.90) a cubic and a line can meet up to 3 times.
WE 4

Number of solutions

Write down the number of real solutions to the equation 2x = 3x.

plot y = 2ⁿ and y = 3x at x = 0: 2⁰ = 1, 3(0) = 0 ⇒ exponential above at x = 1: 2¹ = 2, 3 ⇒ line above at x = 4: 2⁴ = 16, 12 ⇒ exponential above the graphs cross twice in (0, 4) 2 real solutions the GDC gives x ≈ 0.46 and x ≈ 3.31.
WE 5

Solve a transcendental equation

Solve ex = 5 − x, giving your answer to 2 d.p.

plot y = eⁿ and y = 5 − x eⁿ is always increasing, 5 − x always decreasing they meet at exactly one point use the GDC intersect tool x ≈ 1.3066 x ≈ 1.31 no algebraic solution exists for this equation; the GDC is essential.
WE 6

Multi-part: sketch, count, intersect, solve

Let f(x) = x2 − 2x − 3 and g(x) = 1 − x. (a) State the vertex and intercepts of f. (b) How many solutions does f(x) = 0 have? (c) Find the intersections of f and g to 2 d.p. (d) Hence solve x2 − 2x − 3 = 1 − x.

(a) vertex: x = 2/2 = 1, f(1) = 1 − 2 − 3 = −4 vertex (1, −4); roots x = −1, 3; y-int (0, −3) (b) f(x) = 0 means the parabola meets the x-axis 2 solutions (the two x-intercepts) (c) f = g: x² − 2x − 3 = 1 − x x² − x − 4 = 0 x = (1 ± √17)/2 ≈ −1.56 or 2.56 y = 1 − x: 2.56 or −1.56 (−1.56, 2.56) and (2.56, −1.56) · (d) x ≈ −1.56, 2.56

💡 Top tips

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Next up: Quadratic Functions & Graphs — the parabola family in detail, with its vertex, axis of symmetry and root behaviour.

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