IB Maths AI HL Sequences & Series Paper 1 & 2 un & Sn ~6 min read

Language of Sequences & Series

A sequence is an ordered list of numbers built from a rule; a series is what you get when you add those numbers up. This note sets out the notation — un for a term, Sn for a sum — that the rest of the chapter relies on.

📘 What you need to know

What is a sequence?

A sequence is an ordered set of numbers produced by a rule — for instance “start at 1 and add 2” gives 1, 3, 5, 7, … Each number is a term, and terms are labelled with the letter u and a subscript: u1 is the first term, u2 the second, and un the general nth term.

When a formula for un is given, any term is found by substituting the term number n. For example, if un = 2n − 1, then u5 = 2(5) − 1 = 9.

What is a series?

A series is formed by adding the terms of a sequence. For the sequence 1, 3, 5, 7, … the associated series is 1 + 3 + 5 + 7 + …

The notation Sn means the sum of the first n terms.

Term and sum notation un = the nth term — substitute n into the rule Sn = u1 + u2 + u3 + … + un a sequence is the list of terms; a series is their sum
A sequence is the list — a series is the sum 4 7 10 13 16 u1 u2 u3 u4 u5 S5 = 4 + 7 + 10 + 13 + 16 = 50 the boxes are the sequence; adding them gives the series
The five terms u1 to u5 form the sequence; their total S5 is the corresponding series.

Finding the rule of a sequence

Sometimes you are given the terms and must find the rule yourself. Look at how each term changes — a constant step from one term to the next points to a formula of the form un = an + b.

Working backwards: to find which term equals a particular value, set the rule un equal to that value and solve the equation for n. The answer must be a positive whole number.

🧭 Recipe — working with sequences and series

  1. Read the rule un — the formula that generates the terms.
  2. For a single term, substitute that value of n into un.
  3. To list terms, substitute n = 1, 2, 3, … in turn.
  4. For a series sum, add the first n terms: Sn = u1 + … + un.
  5. To find a term’s position, set un equal to the value and solve for n.

Worked examples

WE 1

Finding a particular term

A sequence has nth term un = 5n − 2. Find the 8th term.

the 8th term means substitute n = 8 u8 = 5(8) − 2 = 40 − 2 u8 = 38 the subscript is the term number — put it straight into the rule.
WE 2

Listing the first terms

Write down the first four terms of the sequence with un = n2 − 1.

substitute n = 1, 2, 3, 4 in turn u1 = 12 − 1 = 0 u2 = 22 − 1 = 3 u3 = 32 − 1 = 8,   u4 = 42 − 1 = 15 0, 3, 8, 15 the rule need not be linear — here the terms grow by larger and larger steps.
WE 3

Finding a series sum

A sequence has nth term un = 3n − 2. Find S5.

list the first five terms u1…u5 = 1, 4, 7, 10, 13 S5 is the sum of those terms S5 = 1 + 4 + 7 + 10 + 13 S5 = 35 a series is just the running total — list the terms, then add.
WE 4

Finding the rule from the terms

A sequence begins 7, 11, 15, 19, … (a) Describe the rule. (b) Write down u5. (c) The nth term is un = an + b — find a and b.

(a) look at the step between terms 7 → 11 → 15 → 19: add 4 each time (b) next term after 19 u5 = 19 + 4 = 23 (c) step is 4, so a = 4; u1 = 7 gives 4 + b = 7 (a) start at 7, add 4 · (b) 23 · (c) un = 4n + 3 the constant step is the coefficient of n; fix b by checking u1.
WE 5

Finding a term’s position

A sequence has nth term un = 6n + 5. Which term of the sequence is equal to 95?

set the rule equal to 95 6n + 5 = 95 solve for n 6n = 90 ⇒ n = 15 95 is the 15th term n must be a positive whole number — if it isn’t, the value is not in the sequence.
WE 6

Full question: terms and sum

A sequence has nth term un = 9 − 3n. (a) Find the first five terms. (b) Find S5.

(a) substitute n = 1 to 5 u1 = 9 − 3 = 6,   u2 = 3,   u3 = 0 u4 = 9 − 12 = −3,   u5 = −6 (b) add the five terms S5 = 6 + 3 + 0 + (−3) + (−6) (a) 6, 3, 0, −3, −6  ·  (b) S5 = 0 a negative coefficient of n makes a decreasing sequence — the sum can be zero.

💡 Top tips

âš  Common mistakes

Next up: Sigma Notation — a compact way to write a series using the symbol Σ. It is the same idea as Sn, just written more efficiently, with limits telling you where the sum starts and stops.

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