IB Maths AI HL Exponentials & Logs Paper 1 & 2 index laws ~6 min read

Laws of Indices

The laws of indices are the rules for working with powers — multiplying, dividing and raising them to further powers. They work on numbers and on algebra alike, and they are the foundation for everything in exponentials and logarithms.

📘 What you need to know

The laws of indices

An index (or power) tells you how many times a base is multiplied by itself. The core laws come straight from that idea: a3 × a2 writes out as five factors of a, so the indices simply add.

Why aᵐ × aⁿ = aᵐ⁺ⁿ23 × 222 · 2 · 2 × 2 · 2 3 factors 2 factors= 2 · 2 · 2 · 2 · 2 = 25 5 factors in all — the indices add: 3 + 2 = 5
Multiplying powers of the same base just stacks the factors together — so the indices add. The other laws follow from the same counting idea.
Core index laws am × an = am+n  ·  am ÷ an = amn (am)n = amn  ·  (ab)n = anbn  ·  a0 = 1 these are not in the formula booklet — you must remember them

Negative and fractional powers

A negative index flips the term into its reciprocal. A fractional index is a root: the denominator gives the root, the numerator gives a power.

Negative and fractional powers an = 1an  ·  a1/n = na am/n = (na)m = n√(am) denominator = the root — numerator = the power

For a fraction raised to a negative power, take the reciprocal of the fraction and use the positive power: (a/b)n = (b/a)n.

Changing the base

The index laws only apply when terms share the same base — 23 × 52 cannot be combined. Often you can rewrite one base as a power of another: since 4 = 22, a term in base 4 can be turned into a term in base 2.

Changing the base: e.g. 25 × 43 = 25 × (22)3 = 25 × 26 = 211. Once the bases match, the laws take over.

🧭 Recipe — simplifying with index laws

  1. Match the bases — if they differ, rewrite one base as a power of another.
  2. Clear the brackets: raise every factor inside a bracket to the outside power.
  3. Combine same-base terms: add indices when multiplying, subtract when dividing.
  4. Rewrite negative powers as reciprocals and fractional powers as roots.
  5. Present the answer in the form requested — a single power, a fraction, or a number.

Worked examples

WE 1

Multiplying and dividing powers

Evaluate (34 × 32) ÷ 33.

multiply: add the indices 34 × 32 = 34+2 = 36 divide: subtract the indices 36 ÷ 33 = 36−3 = 33 = 27 work with the indices first, then evaluate the single power at the end.
WE 2

A fraction to a negative power

Evaluate 32−4.

negative power ⇒ reciprocal of the fraction (32)−4 = (23)4 raise top and bottom to the power 4 = 24 ÷ 34 = 16 ÷ 81 1681 flip the fraction, then the negative power becomes positive.
WE 3

Fractional powers

Evaluate (a) 813/4  and  (b) 64−2/3.

(a) denominator 4 = 4th root, numerator 3 = power 813/4 = (4√81)3 = 33 = 27 (b) negative ⇒ reciprocal; 3 = cube root 64−2/3 = 1 ÷ (3√64)2 = 1 ÷ 42 (a) 27  ·  (b) 116 take the root first (smaller numbers), then apply the power.
WE 4

Simplifying an algebraic fraction

Simplify  (5a3b)(4a2b4)10a4b2.

expand the numerator — add indices (5a3b)(4a2b4) = 20a5b5 divide by 10a4b2 — subtract indices 20 ÷ 10 = 2,   a5−4 = a,   b5−2 = b3 2ab3 handle the numbers and each letter as separate calculations.
WE 5

Brackets and negative powers

Simplify (2x3y−2)4(4x5y−3)−1, giving your answer with positive indices.

clear each bracket — multiply the indices (2x3y−2)4 = 16x12y−8 (4x5y−3)−1 = 14x−5y3 multiply — add indices, with 16 × 14 = 4 4x12−5y−8+3 = 4x7y−5 4x7y5 a negative index on a bracket flips it — then write y−5 as 1 ÷ y5.
WE 6

Full question: changing the base

(a) Write 8 and 16 as powers of 2. (b) Hence simplify (82 × 16) ÷ 43, giving your answer as a power of 2.

(a) express each number in base 2 8 = 23,   16 = 24  (and 4 = 22) (b) rewrite the expression in base 2 ((23)2 × 24) ÷ (22)3 = (26 × 24) ÷ 26 = 210 ÷ 26 (a) 8 = 23, 16 = 24  ·  (b) 24 change every base to 2 first — then the index laws do the rest.

💡 Top tips

âš  Common mistakes

Next up: Introduction to Logarithms — the inverse of a power. Indices and logarithms are two views of the same relationship: ax = b is exactly x = logab. Master the index laws and the log laws will feel familiar.

Need help with AI HL Exponentials & Logs?

Get 1-on-1 help from an IB examiner who knows exactly what Paper 1 & 2 are looking for.

Book Free Session →