IB Maths AI HL Probability Paper 1 & 2 ~8 min read

Probability & Types of Events

Probability measures how likely something is, on a scale from 0 (impossible) to 1 (certain). The basic rule is simple — count the outcomes you want, divide by the total. From there you build up the language of events: the complement (not happening), the intersection (both happening, “and”), and the union (either happening, “or”). Get these symbols and the two combining formulas down, and most of the unit falls into place.

📘 What you need to know

Basic probability

For equally likely outcomes, probability is just a count. List or table the sample space, count what you want, divide by the total.

Theoretical probability P(A) = n(A)n(U) in the formula booklet ✓
Expected number of occurrences = np. If you roll a fair dice 60 times, you expect 60 × 16 = 10 sixes — on average, not exactly.

The complement: A′

The complement A′ is everything except A. Since one of A or A′ must happen, their probabilities sum to 1 — often the quickest route to an answer.

Complement P(A) + P(A′) = 1   ⇒   P(A′) = 1 − P(A) in the formula booklet ✓

🧠 Memory aid — “1 minus”

Whenever a question says “at least one” or “not”, reach for the complement: P(at least one) = 1 − P(none). It’s almost always faster than adding up every winning case.

Intersection (AND) and union (OR)

Two events can combine in two ways. means both (“and”); means at least one (“or”). The overlap is the key.

Intersection ∩
A and B
Both events happen together — the overlap region of the two circles.
Union ∪
A or B (or both)
At least one happens — everything inside either circle.
intersection vs union
U A B A ∩ B (“A and B”) U A B A ∪ B (“A or B or both”)
Intersection = just the overlap. Union = both circles combined.
Union (addition) formula P(AB) = P(A) + P(B) − P(AB) in the formula booklet ✓

🤔 Why subtract P(AB)?

When you add P(A) and P(B), the overlap (where both happen) gets counted twice — once in each. Subtracting P(AB) removes the double-count, so the union is correct. If the events can’t both happen (no overlap), that term is 0 and you just add.

Worked examples

WE 1

List a sample space with a table

Spinner A has sides 1, 4, 9; spinner B has sides 2, 3, 5, 7. A two-digit number is formed (A = first digit, B = second). List all possible numbers.

use a two-way table (A down, B across) 12, 13, 15, 17 42, 43, 45, 47 92, 93, 95, 97 12 outcomes in total a table lists every outcome systematically — nothing missed.
WE 2

Find P(event)

T is the event “the two-digit number is a multiple of 3”. Find P(T).

P(T) = n(T)/n(U) multiples of 3: 12, 15, 42, 45, 93 → n(T) = 5 n(U) = 12 P(T) = 5/12 count the favourable outcomes, divide by the total.
WE 3

Use the complement

Using P(T) = 512 from WE 2, find P(T′).

P(T’) = 1 − P(T) = 1 − 5/12 P(T’) = 7/12 “not a multiple of 3” is just the complement.
WE 4

Use the union formula

A student has a dog with probability 0.8, a cat with probability 0.6, and a cat or a dog with probability 0.9. Find P(has both a dog and a cat).

P(D ∪ C) = P(D) + P(C) − P(D ∩ C) 0.9 = 0.8 + 0.6 − P(D ∩ C) P(D ∩ C) = 1.4 − 0.9 P(D ∩ C) = 0.5 rearrange the union formula to get the intersection.
WE 5

Expected number of occurrences

The probability a spinner lands on red is 0.35. If it is spun 80 times, how many reds would you expect?

expected = np = 80 × 0.35 28 reds (expected) it’s an average — you won’t get exactly 28 every time.

💡 Top tips

⚠ Common mistakes

Next up — Independent & Mutually Exclusive Events. You’ve met the union and intersection; next you’ll see two special cases that simplify them: mutually exclusive events (can’t both happen, so P(AB) = 0) and independent events (one doesn’t affect the other, so P(AB) = P(A)P(B)).

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