IB Maths AI HL Binomial Distribution Paper 1 & 2 ~7 min read

The Binomial Distribution

The binomial distribution counts the number of successes in a fixed number of independent yes/no trials. If a situation passes four conditions — fixed trials, independence, two outcomes, constant probability — you can model it with X ∼ B(n, p) and pull its mean and variance straight from two booklet formulae. The exam skill is half spotting when the model applies, and half setting it up cleanly.

📘 What you need to know

The four conditions

A discrete random variable X follows a binomial distribution if it counts successes in an experiment meeting all four conditions. A handy mnemonic is “BINS”.

🧠 Memory aid — “BINS”

Binary (exactly two outcomes: success / failure) · Independent trials · N fixed number of trials · Same probability p every trial. Miss any one and it’s not binomial.

Binomial ✓
fits BINS
Number of tails in 20 fair coin flips: B(20, 0.5). Fixed trials, independent, two outcomes, constant p.
Not binomial ✗
breaks a rule
Caramels eaten from a bag (no replacement → not independent, p changes). Or rolls of a die (more than two outcomes).

🤔 “More than two colours” — can it still be binomial?

Yes, if you frame the trial as a yes/no. Counting yellow cars in a car park of 100 has many possible colours, but the trial is “yellow or not yellow” — two outcomes. As long as the other three conditions hold, it’s binomial. Sampling without replacement from a large population also counts: each pick is approximately independent with constant p.

ScenarioWhy it fails
Emails received in an hourNumber of trials not fixed / infinite
Flips until first headsNumber of trials not fixed
Caramels eaten (no replacement)Trials not independent; p changes
Shoe size; die rollMore than two outcomes
Pool lengths swum under a minutep drops as the swimmer tires

Setting up a model

Once you’ve checked the conditions, setting up the model is a short, repeatable routine. Always state your random variable in words.

🧭 Recipe — setting up a binomial model

  1. Identify a trial — e.g. checking whether a person is immune.
  2. Define “success” — e.g. the person is immune (just a label).
  3. Find the parametersn = number of trials, p = probability of success.
  4. State the variable — “Let X be the number of … ” then write X ∼ B(n, p).
Exam habit: when a question mixes several distributions, make it clear which one each variable follows. Naming the distribution explicitly (e.g. X ∼ B(50, 0.08)) is often worth a mark on its own.

Mean, variance & shape

Two booklet formulae give the centre and spread of a binomial distribution directly from n and p — no table needed.

Mean and variance of B(n, p) E(X) = np     Var(X) = np(1 − p) both in the formula booklet ✓
How p controls the shape
p < 0.5 tail to the right p = 0.5 symmetrical p > 0.5 tail to the leftA vertical line graph; the closer p is to 0.5, the more symmetric the shape.
Small p bunches the bars on the left (tail right); large p bunches them right (tail left).

Worked examples

WE 1

State the distribution

It is known that 8% of a large population are immune to a virus. Mark samples 50 people and models the number immune with a binomial distribution. State the distribution.

trial: check if a person is immune success = the person is immune. parameters: n = 50, p = 0.08 Let X = number of immune people in the sample. X ∼ B(50, 0.08)
WE 2

State the assumptions

State two assumptions Mark must make to use a binomial model.

1. constant probability each person has an 8% chance of being immune. 2. independence the sample is random and people are independent — one person being immune doesn’t affect others (e.g. not all 50 from one family). constant p AND independent trials
WE 3

Expected number (mean)

For Mark’s model X ∼ B(50, 0.08), calculate the expected number of immune people.

E(X) = np = 50 × 0.08 = 4 E(X) = 4 people the mean comes straight from the booklet formula.
WE 4

Variance and standard deviation

For the same model X ∼ B(50, 0.08), find the variance and standard deviation.

Var(X) = np(1 − p) = 50 × 0.08 × 0.92 = 3.68 sd = √Var(X) = √3.68 = 1.918… Var = 3.68, sd ≈ 1.92 remember 1 − p = 0.92; the sd is just the square root.
WE 5

Is it binomial?

A person eats 5 sweets from a bag of 6 caramels and 4 marshmallows. Let C = number of caramels eaten. Can C be modelled binomially? Explain.

check the conditions fixed trials (5) ✓, two outcomes (caramel / not) ✓ but: no replacement eating one caramel changes what’s left, so p is NOT constant and trials are NOT independent. No — not binomial sampling without replacement from a small bag breaks two conditions.

💡 Top tips

⚠ Common mistakes

Next up — Calculating Binomial Probabilities. You’ll use your GDC’s binomial PD and CD functions to find P(X = x) and cumulative probabilities like P(aXb), plus the integer tricks for turning strict inequalities into ones your calculator can handle.

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