IB Maths Paper 1 & 2 15 min read

Compound Interest & Depreciation

Money grows (interest) or shrinks (depreciation) by a fixed percentage each period. One simple formula handles both. Let’s go.

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What you need to know

  • What compound interest means and how it differs from simple interest
  • The compound interest formula with compounding periods
  • How to handle depreciation (just compound interest going down)
  • How to find missing values: future value, time, or interest rate

Two simple ideas: growth and decay

Compound interest (going up ↑)

Money you save earns a % each year, and next year you earn interest on the bigger amount too.

Examples:

  • Bank savings
  • Investments
  • Inflation

Depreciation (going down ↓)

The value of something drops by a % each year (cars, electronics, machinery).

Examples:

  • Car value over time
  • Mobile phone resale
  • Computer / laptop

Both work the same way. The only difference: interest adds a percentage, depreciation subtracts a percentage.

Formula for compound interest

This is the formula in your IB formula booklet:

FV = PV × (1 + r100k)kn

What each letter means

  • FV  = Future Value (what you’ll have at the end)
  • PV  = Present Value (what you start with)
  • r    = annual interest rate (as a percentage, e.g. 5)
  • k    = compounding periods per year (1, 2, 4, or 12)
  • n    = number of years

What does k mean?

k tells you how often interest gets added each year:

Important: the more often interest is compounded (bigger k), the more money you make over the same time.

Quick example: yearly compound interest

You invest $1000 at 5% per year for 3 years, compounded yearly.

  1. PV = 1000,   r = 5,   k = 1,   n = 3
  2. FV = 1000 × (1 + 5100 × 1)1 × 3
  3. FV = 1000 × (1.05)3
  4. FV = 1000 × 1.157625 = $1157.63

Formula for depreciation

Same formula — just subtract instead of add, and use k = 1 (depreciation is usually yearly):

FV = PV × (1 − r100)n

Tip: this formula is NOT in the formula booklet — but you can derive it from the compound interest one by setting k = 1 and changing the + to a .

Quick example: depreciation

A laptop worth $1200 loses 20% of its value each year. Find its value after 3 years.

  1. PV = 1200,   r = 20,   n = 3
  2. FV = 1200 × (1 − 20100)3
  3. FV = 1200 × (0.8)3
  4. FV = 1200 × 0.512 = $614.40

Worked Examples

Example 1 — Yearly interest

Aisha invests $5000 at 4% annual interest, compounded yearly. How much will she have after 6 years?

Answer:

PV = 5000,   r = 4,   k = 1,   n = 6 FV = 5000 × (1 + 4/100)6 = 5000 × (1.04)6 = 5000 × 1.26532… FV ≈ $6326.60

Example 2 — Compounded monthly

Kim invests MYR 2000 at 2.5% per year, compounded monthly. Find the amount after 5 years (to the nearest 10 MYR).

Answer:

Monthly compounding → k = 12. PV = 2000,   r = 2.5,   k = 12,   n = 5 FV = 2000 × (1 + 2.5/(100 × 12))12 × 5 = 2000 × (1 + 0.002083)60 = 2000 × 1.13300… = 2266.00… FV ≈ MYR 2270

Example 3 — Find the value of a car (depreciation)

Kyle buys a new car for AUD $14 999. The car loses 15% of its value each year. Find its value after 5 years.

Answer:

PV = 14999,   r = 15,   n = 5 FV = 14999 × (1 − 15/100)5 = 14999 × (0.85)5 = 14999 × 0.4437… FV ≈ AUD $6655

Example 4 — Find how many years (using logs)

From Example 3, after how many years will the car’s value drop to about AUD $9999?

Answer:

9999 = 14999 × (0.85)n Divide both sides: 9999 / 14999 = (0.85)n 0.6666… = (0.85)n Take logs: n = log(0.6666) / log(0.85) n = 2.495… 2 full years + 0.495 × 12 ≈ 6 months ≈ 2 years 6 months

Example 5 — Find the interest rate

$2000 grows to $2400 in 4 years compounded yearly. Find the annual interest rate r.

Answer:

2400 = 2000 × (1 + r/100)4 1.2 = (1 + r/100)4 Take 4th root: 1 + r/100 = (1.2)1/4 1 + r/100 = 1.04663… r/100 = 0.04663… r ≈ 4.66% per year
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Quick tips

  • Per annum” = “per year”. Always assume yearly unless told otherwise.
  • For depreciation, just use (1 − r/100) instead of (1 + r/100).
  • Use your GDC’s finance app as a backup. For depreciation, enter the rate as negative.
  • To find n (number of years), you’ll usually need logarithms.

Common mistakes

  • Forgetting to multiply kn in the exponent. If interest is monthly for 5 years, the power is 12 × 5 = 60, not just 5.
  • Putting r as a decimal in the formula. The formula uses r as a percentage (e.g. 5, not 0.05), because it’s already divided by 100 inside.
  • Using “+” for depreciation. Depreciation = value drops, so always .
  • Confusing k with n. k = compounding periods per year. n = number of years. Don’t mix them up.
  • Rounding too early. Keep many decimal places during calculation, only round at the end.

Final word: one formula does it all. Plug in your values, watch the signs (+ for growth, − for depreciation), and let your GDC do the heavy lifting. For “find n” or “find r” questions, use logs or the equation solver.

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