IB Biology SL Topic 2 — Osmosis & Water Potential Paper 1 & 2 Practical skill ~10 min read

Osmosis: The Potato Practical

This is the classic osmosis experiment, and it does something clever: by measuring how much mass potato cylinders gain or lose in different sugar solutions, you can work out the concentration inside cells you never looked at.

📘 What you need to know

Designing it properly first

Planning is not a formality. An experiment run without it usually produces data you cannot draw a valid conclusion from, because something you never thought about was changing as well.

Preliminary research (the word just means “coming before”) should settle:

Then run preliminary trials. These reveal additional variables you had not spotted, show you how to control them, and tell you what quantities you need so you do not run out halfway through.

The method

🧩 Potato cylinders in sucrose solutions

  1. Use a cork borer to cut cylinders of potato of the same diameter, working on a white tile. Cut at least five for each solution you are testing.
  2. Trim them all to the same length with a scalpel and ruler.
  3. Blot them dry with paper towel, then measure and record the initial mass of each on a balance reading to 0.01 g.
  4. Measure equal volumes of each sucrose solution into labelled test tubes. Use a range of at least five concentrations, and include distilled water as one of them.
  5. Add one cylinder to each tube and leave for a set time (30 minutes is typical), at a controlled temperature.
  6. Remove the cylinders, blot them dry again, and record the final mass and length of each.
Blotting matters more than it sounds. A film of solution clinging to the outside of a cylinder is liquid you did not intend to weigh, and it can easily be bigger than the change you are trying to measure.
One cylinder per tube, one concentration per tube sucrose concentration / mol dm⁻³0.0 0.25 0.5 0.75 1.0 Same size cylinders, same time, same temperature Only the concentration of the solution is allowed to change
Everything except the sucrose concentration is a control variable. If the tubes sat for different lengths of time, the results would mean nothing.

Analysing the results

Raw mass changes are not comparable, because no two cylinders start at exactly the same mass. Convert everything to a percentage change:

Percentage change in mass % change = (final mass − initial mass) ÷ initial mass × 100

Here is a set of results worked through. A positive value means the cylinder gained water; a negative value means it lost water.

Sucrose / mol dm−3Initial mass / gFinal mass / gChange / g% change
0.0 (distilled water)5.005.40+0.40+8.0
0.25.005.15+0.15+3.0
0.45.004.95−0.05−1.0
0.65.004.75−0.25−5.0
0.85.004.60−0.40−8.0
1.05.004.45−0.55−11.0
Percentage change in mass against sucrose concentration change in mass (%) 10 5 0 -5 -10 crosses at 0.35 mol dm⁻³0 0.2 0.4 0.6 0.8 1.0 concentration of sucrose (mol dm⁻³)Where the line crosses zero, the potato neither gained nor lost water The error bars show how much the repeats varied at each concentration
The crossing point is the useful bit. At that concentration the solution is isotonic with the potato cells, so it tells you what is inside them.

Reading the graph

The whole point of the graph: the point where the line of best fit crosses the x-axis is the concentration of sucrose that would be isotonic with the potato cells — an estimate of the osmotic concentration inside the tissue.

Standard deviation and standard error

Repeats let you calculate a mean for each concentration, but a mean on its own hides how consistent the readings were. Two sets of results can have the same mean and look completely different.

On a graph, standard error is drawn as error bars extending above and below each plotted mean.

What the error bars doWhat it suggests
Error bars overlapThe difference between the means is not significant
Error bars do not overlapThere is a significant difference between the means
Error bars are shortThe repeats were consistent, so the mean is more trustworthy
You are not asked to memorise these formulae. What you are asked to do is use the values — look at a graph with error bars and say whether a difference is meaningful or could just be scatter.

Worked examples

WORKED EXAMPLE

Calculate a percentage change

A potato cylinder had an initial mass of 5.00 g. After 30 minutes in 0.2 mol dm−3 sucrose its mass was 5.15 g. Calculate the percentage change in mass and state what it shows.

Step 1: Find the change in mass 5.15 − 5.00 = +0.15 g Step 2: Divide by the initial mass 0.15 ÷ 5.00 = 0.03 Step 3: Multiply by 100 0.03 × 100 = 3.0 +3.0% — the cylinder gained water Keep the plus sign. It is doing real work in the answer, not decoration.
WORKED EXAMPLE

Use the graph to find what is inside the cells

Using the graph above, estimate the osmotic concentration of the potato tissue and explain how you got it.

Step 1: Find where the line crosses the x-axis Between 0.2 (+3.0%) and 0.4 (−1.0%), at about 0.35 mol dm−3 Step 2: Say what that point means At that concentration there was no net movement of water, so the solution was isotonic with the cells. Step 3: State the conclusion The tissue has the same osmotic concentration as that solution. About 0.35 mol dm−3 You never measured inside a cell. The crossing point did it for you.
WORKED EXAMPLE

Interpret error bars

On a graph of mean percentage change, the error bars for 0.0 and 0.2 mol dm−3 do not overlap, but those for 0.8 and 1.0 mol dm−3 do. What can you conclude?

For 0.0 and 0.2 The bars do not overlap, so there is a significant difference between those two means. For 0.8 and 1.0 The bars overlap, so the difference between those means is not significant — it could be down to variation between cylinders. Significant at the low end, not at the high end Use the word “suggests”. Error bars indicate significance; they do not prove it.

💡 Exam tip

⚠ Common mix-up

That completes Osmosis & Water Potential. One idea runs through all three pages: water moves down a water potential gradient, and everything a cell does about it is damage control.

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