IB Chemistry HL Topic 7 — Tool 3: Mathematics Paper 1, 2 & IA Core skill ~12 min read

Applying General Mathematics

Nobody fails Chemistry because the maths was too hard. People lose marks because they left an answer as a fraction, averaged in a rough titre, or called a straight line “directly proportional” when it missed the origin. This page is about those marks.

📚 What you need to know

The kinds of maths you will actually meet

TypeWhere it shows upWatch out for
DecimalsNearly every calculationRounding too early
FractionsUncertainty workLeaving the answer as a fraction
PercentagesYield, atom economy, error, uncertaintyUsing the wrong formula
RatiosMoles, when stoichiometry is not 1:1Reading the equation coefficients wrongly
ReciprocalsGas laws (1/V), rate graphs (1/T)Forgetting to invert the units too
LogarithmspH, pKa, the Arrhenius equationMixing up log and ln
Exponentials (HL)The Arrhenius equationCalculator in the wrong mode
Section 1 of the data booklet gives you a list of equations, but it is not everything. Percentage yield, percentage error and percentage uncertainty are all expected knowledge and none of them is printed for you.

The mean average

Add all the values, divide by how many there are. The complication in chemistry is deciding which values to include.

An anomalous result is one that clearly does not fit with the others. It gets excluded from the mean, because leaving it in would drag the answer towards a measurement you already believe is wrong.

Averaging titres

Titrations have their own rule, and it is worth knowing exactly.

Which titres go into the average? Only the ones that agree with each other to within 0.10 cm³ 3 concordant not concordant rough titre 23.80 24.00 24.20 24.40 24.60 mean of the 3 = 23.87 cm³ both of these are left out Averaging all five would give 24.05 cm³ — a worse answer Two bad readings would have pulled the result up by nearly 0.2 cm³
The two green circles stacked at the same place are two identical titres of 23.85 cm3. Repeats landing on the same value is exactly what you want to see.

Range

The range measures how spread out a set of numbers is. Highest minus lowest — remember it as “hi − lo”.

You can quote it either as a span (9.2 to 8.4) or as a single number (0.8). Be careful though: if the highest or lowest value is itself anomalous, the range is misleading.

Scientific notation

Also called standard form. It is a way of writing numbers that are far too big or far too small to write out comfortably.

Standard form a × 10n   where 1 ≤ a < 10
Count the hops of the decimal point Hops to the left give a positive power, hops to the right give a negative one 3 0 0 0 0 0 0 0 0 1 2 3 4 5 6 7 8 = 3 × 10⁸ 0 . 0 0 0 0 2 1 2 3 4 5 = 2 × 10⁻⁵ When rounding, only the value of a is rounded 4.37 × 10⁶ to 2 significant figures is 4.4 × 10⁶, not 4.4 × 10⁵
The power of ten is never rounded. It is not a measurement, it is a place-value marker.

Orders of magnitude

An order of magnitude is just the power of ten. Something one order of magnitude larger is about ten times larger; two orders of magnitude is about a hundred times.

One catch: orders of magnitude follow rounding rules. The order of magnitude of 3 × 108 is 108, but the order of magnitude of 6 × 108 is 109, because 6 rounds up to 10.

Approximation, estimation and useful assumptions

These sound like sloppiness. They are the opposite — they are decisions about what you can safely ignore.

The weak acid assumption

Here is the assumption you meet most often. For a weak acid HA:

The exact expression Ka = [H+][A] ÷ [HA]

Because a weak acid barely dissociates, two things are close enough to true:

The simplified expression Ka = [H+]2 ÷ [HA]
The assumption is not equally safe for every acid. The bigger the Ka, the more the acid dissociates and the worse the approximation gets. If a question asks you to comment on validity, that is the point being tested.

The three percentage formulas

These get muddled constantly, so learn what each one compares.

FormulaWhat it comparesCalculation
Percentage changeA value before and after(final − initial) ÷ initial × 100
Percentage differenceTwo measurements of equal standing(value 1 − value 2) ÷ mean of the two × 100
Percentage errorYour result against a literature value(accepted − experimental) ÷ accepted × 100
Percentage uncertaintyInstrument uncertainty against the readinguncertainty ÷ measured value × 100
The giveaway is the denominator. Percentage change divides by the starting value. Percentage difference divides by the average, because neither value is more trustworthy. Percentage error divides by the accepted value, because that one is assumed right.

Describing data and trends

Qualitative and quantitative

Proportionality, and the trap in it

Three shapes worth recognising instantly Sketch graphs need no scale, but they do need labels DIRECTLY PROPORTIONAL INVERSELY PROPORTIONAL CONSTANT y = kx y = k / x y does not change The green dot is the origin — a directly proportional line must pass through it
An inversely proportional curve never touches either axis. It gets closer and closer but never arrives, because you cannot divide by zero.
The trap. A straight line sloping upwards is not automatically directly proportional. If it crosses the y-axis anywhere other than zero, it is proportional but not directly proportional. Examiners test this every year.

Correlation

Positive correlation means as x increases, y increases: the graph slopes upwards. Negative correlation means as x increases, y decreases. Correlation describes the direction of the trend, not its shape, so it applies to curves as well as straight lines.

Rate of change from a table

You do not always need to plot a graph. The average rate of change between two rows of a table is the change in the dependent variable divided by the change in the independent variable.

Average rate of change change in y ÷ change in x

Worked examples

WORKED EXAMPLE

A titration gives a rough titre of 24.60 cm3, then titres of 23.85, 24.10, 23.90 and 23.85 cm3. Calculate the mean titre.

Throw out the rough titre It is a scouting run, so 24.60 is never used. Test the rest for concordance 23.85, 23.90 and 23.85 all sit within 0.05 cm3 of each other. 24.10 is 0.25 away, so it is anomalous. Average the three that agree (23.85 + 23.90 + 23.85) ÷ 3 = 71.60 ÷ 3 = 23.8666… Mean titre = 23.87 cm3 quote it to 2 decimal places, matching the burette readings
WORKED EXAMPLE

An experiment gives the enthalpy of combustion of propan-1-ol as −1.50 × 103 kJ mol–1. The literature value is −2021 kJ mol–1. Calculate the percentage error.

Pick the right formula We are comparing against a literature value, so this is percentage error, and we divide by the accepted value. Substitute (2021 − 1500) ÷ 2021 × 100 Work it through 521 ÷ 2021 × 100 = 25.78… Percentage error = 26% a large error like this usually means heat loss to the surroundings
WORKED EXAMPLE

The volume of gas produced is 3.0 cm3 at 10 s and 10.0 cm3 at 30 s. Calculate the average rate of change over that interval.

Identify the variables Volume is dependent (y), time is independent (x). Find both changes ΔV = 10.0 − 3.0 = 7.0 cm3 Δt = 30 − 10 = 20 s Divide 7.0 ÷ 20 = 0.35 Rate = 0.35 cm3 s–1 this is an average over the interval, not the rate at any single instant

💡 Exam tip

⚠️ Common mix-up

Up next: Units, Symbols and Numerical Values — the SI system, the prefixes, and how many digits you are actually allowed to write down.

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