IB Chemistry HL Topic 2 — Models of Bonding & Structure Paper 1 & 2 Core idea ~8 min read

Coordinate (Dative) Bonds

In an ordinary covalent bond both atoms chip in one electron each. In a coordinate bond, one atom pays for the whole thing. It sounds like a special case, but it is how the ammonium ion forms, how acids work in water, and how every transition metal complex is held together.

📘 What you need to know

The one thing that makes it different

Everything about a coordinate bond is the same as a normal covalent bond except its origin story. Two electrons end up shared between two nuclei, exactly as before. The only difference is that they both started on one atom.

How to spot one on a diagram
Line or arrow? It depends where the electrons came from Both bonds contain exactly two shared electrons ORDINARY COVALENT BOND COORDINATE BOND A B one electron from each atom A B both electrons came from atom A The arrow always points away from the atom that donated the pair. Both dots are the same colour because both electrons have the same owner.
If a question asks you to show a coordinate bond, the arrow is the mark. A plain line is not wrong chemistry, but it does not answer the question that was asked.

The two ingredients you always need

A coordinate bond will not form unless both of these are present. Get into the habit of naming both when you explain one.

🎁

THE DONOR

HAS ELECTRONS SPARE N a lone pair to give away

An atom carrying a lone pair: nitrogen, oxygen and the halogens are the usual suspects.

📁

THE ACCEPTOR

HAS ROOM TO SPARE B an empty space to fill

An electron deficient atom or ion: H+, BF3, AlCl3, or a metal ion.

The ammonium ion, step by step

This is the example the IB uses most, so learn it properly rather than half remembering it.

Ammonia has a nitrogen with three bonds and one lone pair. A hydrogen ion, H+, is a bare proton — it lost its only electron, so its 1s shell is completely empty. Put them together and the deal is obvious: nitrogen has a spare pair, H+ has nowhere to put anything. Nitrogen donates both electrons and a fourth N–H bond appears.

Ammonia plus a hydrogen ion
Nitrogen pays for the fourth bond on its own The lone pair on ammonia fills the empty shell of the hydrogen ion lone pair N H H H + H + empty shell coordinate bond + N H H H H NH₃ H⁺ NH₄⁺ Two red dots on the top bond: both electrons came from nitrogen. The plus charge belongs to the whole ion, not to any one atom in it.
Nitrogen ends up with four bonds instead of three and no lone pair left, which is why the ion is positive. The proton brought a charge but no electrons.

🤔 Why are all four N–H bonds identical?

Electrons do not carry a label saying who owned them. Once the fourth bond has formed, nitrogen is sharing four pairs and every one of them sits in an equivalent position around the atom. Measure the four N–H bonds and they come out the same length, the same strength, and at the same 109.5° angles. The dative arrow is a story about how the bond was made, not a description of what it is now.

Same idea, different molecule. Water does exactly the same thing. One of oxygen’s two lone pairs grabs an H+ to give the oxonium ion, H3O+. That is what is really happening every time you write “H+ in solution” in an acids question.

Where else coordinate bonds turn up

SpeciesDonorAcceptorCoordinate bonds
NH4+Lone pair on NH+, empty 1s1
H3O+Lone pair on OH+, empty 1s1
H3N→BF3Lone pair on NB, only 6 electrons1
[Al(H2O)6]3+Lone pair on each OAl3+, empty orbitals6
Al2Cl6Lone pair on ClAl, only 6 electrons2

🧠 Spotting them in an exam

Ask two questions of any suspicious bond. Does one atom have more bonds than you would expect? Nitrogen with four, oxygen with three. Is the species positively charged or is there an electron deficient atom involved? If the answer to both is yes, you are looking at a coordinate bond.

One thing to be careful about at HL: the aluminium hexaaqua ion is officially part of the transition metal complexes material. You are not expected to learn the details of metal complexes at SL — you just need to recognise that coordinate bonding is not limited to small molecules like NH4+.

Worked examples

WE 1

Explain how the bond between NH3 and H+ forms, and state how it compares with the other three N–H bonds [3]

Mark 1: identify the donor Nitrogen in ammonia has a lone pair of electrons. Mark 2: identify the acceptor and the transfer H+ has an empty outer shell, so nitrogen donates both electrons to form a coordinate bond. Mark 3: the comparison Once formed it is identical to the other three — same length, same strength. Lone pair donated to an empty shell; all four bonds identical the word “identical” is nearly always the third mark here
WE 2

Water reacts with H+ to give H3O+. How many lone pairs are left on the oxygen?

Step 1: start with water O has 6 valence electrons: 2 bonding pairs to H, 2 lone pairs. Step 2: use one lone pair for the coordinate bond One lone pair becomes the third O–H bond. 2 − 1 = 1 Step 3: check the electron count 3 bonding pairs + 1 lone pair = 4 pairs = 8 electrons around O. Octet intact. 1 lone pair remains four domains with one lone pair means H₃O⁺ is trigonal pyramidal, just like NH₃
WE 3

State the number of coordinate bonds in [Al(H2O)6]3+ and explain which atom donates

Step 1: read the formula Six water molecules are attached to one Al3+ ion. Step 2: identify donor and acceptor Each water donates one lone pair from its oxygen. Al3+ has empty orbitals to accept them. Step 3: count 6 water molecules × 1 bond each = 6 6 coordinate bonds, all donated by oxygen the 3+ charge is written outside the brackets because it belongs to the whole complex

💡 Exam tips

⚠ Common mix-ups

Up next: Shapes of Molecules (VSEPR) — where every lone pair you have been carefully drawing finally earns its keep, and you start predicting bond angles instead of memorising them.

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