IB Chemistry HL Topic 3 — Classification of Matter Paper 1 & 2 Core idea ~12 min read

Functional Groups

There are millions of organic compounds and only a handful of reactions you need to learn. That works because the long carbon chain is mostly dead weight — the chemistry happens at one small reactive spot. Find that spot and you already know how the molecule behaves.

📘 What you need to know

What a functional group actually does

Look at hexane and hexan-1-ol. They have almost identical carbon skeletons, but hexane is unreactive and barely dissolves in water, while hexan-1-ol can be oxidised, dehydrated, turned into an ester, and mixes with water far better. One OH group did all of that.

The reason is electron density. A plain C–C or C–H bond is close to non-polar, so nothing is attracted to it. Put an oxygen or a halogen in and you create a polar bond with a partial positive carbon — a target. Put in a double bond and you create a region of loose pi electrons — also a target. Reactivity follows the group, not the chain.

This is why the chain length barely changes the chemistry. Propan-1-ol and decan-1-ol undergo the same reactions, because the reacting part is the same. The chain length changes physical properties like boiling point, not chemical behaviour.

Position matters as much as the atoms

Here is the point that costs the most marks on this topic. Two molecules can be built from exactly the same atoms and still belong to different classes, purely because of where the group sits.

End of the chain, or middle of the chain? Same atoms, different class, completely different chemistry AT THE END IN THE MIDDLE CH₃—CH₂—CHO CH₃—CO—CH₃ propanal, an aldehyde propanone, a ketone both of these are C₃H₆O AT THE END IN THE MIDDLE CH₃—CH₂—OH CH₃—O—CH₃ ethanol, an alcohol methoxymethane, an ether both of these are C₂H₆OEthanol boils at 78 °C; methoxymethane boils at −24 °C.
Ethanol and methoxymethane share a molecular formula, yet one is a liquid you can drink and the other is a gas. Ethanol’s OH can hydrogen bond to its neighbours; the ether’s buried oxygen cannot, because it has no hydrogen attached to it.
If you only remember one thing from this page, remember to check where the oxygen sits before you name the class. An oxygen with a hydrogen on it is an alcohol or an acid. An oxygen with carbons on both sides is an ether or an ester.

The carbonyl family: five classes, one group

The C=O group is called a carbonyl, and it turns up in five different classes. They all react in broadly similar ways, because they all have the same electron-poor carbon in the middle. What separates them is the single atom or group sitting on the right-hand side of that carbon.

One carbonyl, five families Only the group on the right of the C=O changes R C O H aldehyde -al R C O R ketone -one R C O OH carboxylic acid -oic acid R C O OR ester -oate R C O NH₂ amide -amideR just means “the rest of the molecule” — usually a carbon chain. An aldehyde has an H there; a ketone has carbon chains on both sides.
The aldehyde is the odd one out: it is the only carbonyl with a hydrogen bonded straight to the carbonyl carbon. That single hydrogen is why aldehydes are oxidised easily and ketones are not.
Why the H is written first in RCHO. An aldehyde is often written as RCHO rather than RCOH, because RCOH looks like an alcohol with the O and H next to each other. Putting the H before the O makes it clear the hydrogen is on the carbon, not on the oxygen.

Saturated or unsaturated?

This pair of words is only ever about carbon–carbon bonds.

A C=O double bond does not make a molecule unsaturated in the way this syllabus uses the word. Propanone has a double bond, but both of its carbon–carbon bonds are single, so it counts as saturated. Only look at carbon-to-carbon.

The classes you need to know

ClassGroup nameGroupPrefix or suffixSimplest example
alkanealkylC–C single bonds only-aneethane, C2H6
alkenealkenylC=C-eneethene, C2H4
alkynealkynylC≡C-yneethyne, C2H2
halogenoalkanehalogeno–F, –Cl, –Br, –Ifluoro-, chloro-, bromo-, iodo-chloroethane, C2H5Cl
alcoholhydroxyl–OH-ol, or hydroxy-ethanol, C2H5OH
etheralkoxy–O– between two carbonsalkoxy-methoxymethane, CH3OCH3
aldehydecarbonyl–CHO at a chain end-alethanal, CH3CHO
ketonecarbonyl–CO– inside the chain-onepropanone, CH3COCH3
carboxylic acidcarboxyl–COOH-oic acidethanoic acid, CH3COOH
esterester–COO–-yl …-oatemethyl methanoate, HCOOCH3
amineamino–NH2-amine, or amino-ethanamine, C2H5NH2
amideamido–CONH2-amideethanamide, CH3CONH2
arenephenylbenzene ring, C6H5phenyl-, or -benzenemethylbenzene, C6H5CH3

🧩 Spotting the group in an unfamiliar molecule

  1. Find every atom that is not carbon or hydrogen. Circle them. These are where all the interesting chemistry lives.
  2. For each oxygen, ask what is on either side. H on one side means alcohol or acid. Carbons on both sides means ether or ester.
  3. Look for any C=O. If you find one, check the fourth thing on that carbon: H gives aldehyde, carbon gives ketone, OH gives acid, O–C gives ester, N gives amide.
  4. Scan the carbon backbone for multiple bonds. A C=C makes it an alkene, a C≡C makes it an alkyne, a ring with delocalised electrons makes it an arene.
  5. Do not stop at the first group you find. If more than one is present, name them all — the question is usually testing exactly that.

Worked examples

WORKED EXAMPLE

Identify all the functional groups in HOCH2CH2COOH and name the classes they belong to.

Step 1: mark every non-carbon, non-hydrogen atom There are three oxygens: one in the HO at the left, and two in the COOH at the right. Step 2: work out the left-hand oxygen HO–CH2– : an oxygen with an H on one side and a carbon on the other That is a hydroxyl group, so this end is an alcohol. Step 3: work out the right-hand pair of oxygens –COOH : a C=O with an OH bonded to the same carbon That is a carboxyl group, so this end is a carboxylic acid. hydroxyl (alcohol) and carboxyl (carboxylic acid) Two groups, so this molecule shows both sets of reactions. It is 3-hydroxypropanoic acid — the acid wins the suffix and the alcohol becomes the hydroxy- prefix.
WORKED EXAMPLE

A compound is CH3CH=CHCH2Cl. State its functional groups, and say whether it is saturated or unsaturated.

Step 1: look for atoms that are not C or H one Cl, bonded to a carbon A halogen on a carbon chain makes this a halogenoalkane. The group is halogeno, and it would appear in the name as chloro-. Step 2: scan the backbone for multiple bonds CH=CH between carbons 2 and 3 A C=C is an alkenyl group, so it is also an alkene. Step 3: decide saturated or unsaturated Rule: unsaturated means at least one carbon-to-carbon multiple bond. There is one here. alkenyl and halogeno; the compound is unsaturated Both groups react. The C=C will do addition, the C–Cl will do substitution.
WORKED EXAMPLE

A student says butanal and butanone must be in the same class because both contain a carbonyl group. Explain why they are wrong.

Step 1: write out both structures butanal: CH3CH2CH2CHO butanone: CH3COCH2CH3 Step 2: check what the carbonyl carbon is bonded to In butanal the carbonyl carbon carries a hydrogen and one carbon chain. In butanone it carries two carbon chains and no hydrogen. Step 3: name the two classes Carbonyl at a chain end with an H gives an aldehyde. Carbonyl inside the chain gives a ketone. These are two different classes. aldehyde and ketone — different classes, so different chemistry They do share the molecular formula C4H8O, which makes them functional group isomers. Coming up in a couple of pages.

💡 Exam tip

⚠ Common mix-up

Up next: Homologous Series — you have the groups, so now we line up all the compounds that share one and see what changes as the chain grows.

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