IB Chemistry HL Topic 3 — Classification of Matter Paper 1 & 2 HL only ~13 min read

Proton NMR Spectroscopy

Mass spectrometry weighs the molecule. Infrared finds the bonds. NMR does something better than either: it counts the hydrogen atoms and tells you what each one is sitting next to. Give a chemist an NMR spectrum and they can usually draw the whole structure.

📘 What you need to know

Counting hydrogen environments

This is the single most important skill on the page, and it comes before any spectrum. Two hydrogens are in the same environment if they are chemically equivalent — if you could swap them and the molecule would be identical. In practice that means: hydrogens on the same carbon are equivalent, and so are hydrogens on carbons that are mirror images of each other.

How many hydrogen environments? Count the groups, not the individual hydrogens ETHANOL: 3 ENVIRONMENTS CH₃CH₂OH 3 H on the methyl carbon 2 H on the middle carbon 1 H on the oxygen ratio 3 : 2 : 1 PROPANONE: 1 ENVIRONMENT CH₃COCH₃ 6 H, all equivalent the two methyl groups sit either side of the C=O, so they are identical just one signal, worth 6 HSix hydrogens can still give a single peak, if they are all equivalent. Number of signals tells you about symmetry, not about how many H there are.
Propanone is the cleanest example of why symmetry matters. Its structure is symmetrical about the carbonyl, so the six hydrogens are indistinguishable and the spectrum has exactly one line.
Symmetry is your friend here. Before counting, look for a mirror line through the molecule. Anything reflected onto itself is one environment, not two. That is why propanone gives one signal, and why 1,4-dimethylbenzene gives two rather than four.

Where the signals come from

Put a proton in a strong magnetic field and it behaves like a tiny magnet, lining up either with the field or against it. Lining up with the field is slightly lower in energy. Supply a radio-frequency photon of exactly the right energy and the proton flips to the higher state — it resonates — and the instrument records that absorption.

The clever part is that the frequency needed is not the same for every proton. The electrons around a proton create their own small magnetic field that opposes the applied one, so the proton feels a slightly weaker field than the instrument is producing. This is shielding.

The rule that explains every shift more electron density around the proton → more shielding → smaller chemical shift

Put an electronegative atom nearby and it pulls electron density away from the proton. The proton is then deshielded, feels more of the applied field, and appears further to the left of the spectrum at a higher chemical shift. That is the whole logic: a CH3 on the end of a chain sits near 1 ppm, but a CH2 next to an oxygen is dragged out to 3–4 ppm.

TMS is used as the zero point for three reasons worth remembering. Its twelve hydrogens are all equivalent, so it gives one sharp peak. Silicon is less electronegative than carbon, so those hydrogens are unusually well shielded and sit further right than almost anything else. And it is inert and volatile, so it does not react with your sample and is easy to remove afterwards.

Reading a low-resolution spectrum

Here is ethanol. Three environments means three signals, and the heights are in the ratio 3 : 2 : 1 because that is how many hydrogens each environment contains.

Low-resolution proton NMR of ethanol Three environments, so three signals CH₃ 3H CH₂ 2H OH 1H TMS integration trace8 7 6 5 4 3 2 1 0 chemical shift, δ / ppmThe red trace steps up by 1, then 2, then 3 — six hydrogens in total.
The integration trace is a running total of peak area. Its step heights, not the peak heights, are what you measure — and you only ever read them as a ratio. A 3 : 2 : 1 trace could mean 3, 2 and 1 hydrogens, or 6, 4 and 2.
The OH signal moves. The data booklet gives alcohol O–H as anything from 1.0 to 6.0 ppm, which is an enormous range. It shifts because it depends on how much hydrogen bonding is happening, which changes with concentration, temperature and solvent. So never identify an OH by its position — identify it by its integration of 1H and by the fact that nothing else fits.

Chemical shift ranges

You are given these in section 21 of the data booklet, so the job is reading the table rather than memorising it. Even so, knowing roughly where things sit lets you sanity-check an answer.

Roughly where each kind of proton sits More deshielded on the left, more shielded on the rightR-COOH acid R-CHO aldehyde benzene ring H -CH=CH₂ R-O-H alcohol -CH₂-halogen R-O-CH₂- R-CO-CH₂- -CH₂-R -CH₃ 13 12 10 8 6 4 2 0 chemical shift, δ / ppm
The pattern to notice is that everything near an oxygen or a double bond is pushed to the left. An aldehyde proton at 9–10 ppm is the most easily recognised signal in the whole of NMR, because almost nothing else appears there.

🧩 Reading a low-resolution spectrum

  1. Ignore the peak at 0 ppm. That is TMS, the reference, and it is not part of your compound.
  2. Count the remaining signals. That is the number of different hydrogen environments.
  3. Read the integration as a whole-number ratio. Divide through by the smallest step.
  4. Look up each chemical shift in section 21 and write down what kind of proton it could be.
  5. Check the total. Your hydrogen ratio must be consistent with the molecular formula — if the formula has 6 H and your ratio is 3 : 2 : 1, that works exactly.

Worked examples

WORKED EXAMPLE

Predict the number of signals and the integration ratio in the proton NMR spectrum of methyl ethanoate, CH3COOCH3.

Step 1: write out the structure and look for symmetry There are two methyl groups, but they are not equivalent. One is bonded to the carbonyl carbon; the other is bonded to an oxygen. Step 2: group the hydrogens by environment CH3 next to C=O: 3 H CH3 next to O: 3 H Step 3: check the total against the formula C3H6O2, so 6 H altogether. 3 + 3 = 6 ✓ 2 signals, in the ratio 3 : 3, which is 1 : 1 Both signals integrate the same, so integration alone cannot tell them apart. The chemical shift can: the O–CH3 sits near 3.7 ppm and the CO–CH3 near 2.0 ppm.
WORKED EXAMPLE

A compound is either propan-1-ol or propan-2-ol. Its proton NMR spectrum shows three signals in the ratio 6 : 1 : 1. Which is it?

Step 1: work out the environments in propan-1-ol CH3CH2CH2OH has four environments: the end CH3, the middle CH2, the CH2 next to the oxygen, and the OH. 4 signals, ratio 3 : 2 : 2 : 1 Step 2: work out the environments in propan-2-ol (CH3)2CHOH is symmetrical about the middle carbon, so both methyl groups are equivalent. 3 signals, ratio 6 : 1 : 1 Step 3: compare with the data The spectrum has three signals in exactly 6 : 1 : 1, which matches the second structure and not the first. propan-2-ol The number of signals was already enough here. The 6H signal is the giveaway — only equivalent methyl groups can integrate that high.
WORKED EXAMPLE

Explain why the CH2 signal in chloroethane appears at about 3.5 ppm while the CH3 signal appears at about 1.5 ppm.

Step 1: identify what is different about the two carbons In CH3CH2Cl the CH2 is bonded directly to the chlorine. The CH3 is one carbon further away. Step 2: think about electron density Chlorine is much more electronegative than carbon, so it pulls electron density towards itself and away from the CH2 hydrogens. Step 3: link electron density to chemical shift less electron density → less shielding → larger shift The CH2 protons are deshielded, so they resonate further to the left. The CH3 protons are two bonds away and barely affected. the CH2 is deshielded by the electronegative chlorine, so its shift is larger The effect drops off fast with distance. In 1-chlorobutane the carbon furthest from the chlorine is back down near 1 ppm.

💡 Exam tip

⚠ Common mix-up

Up next: Peak Splitting in Proton NMR — so far each environment gave one line. At higher resolution those lines split apart, and the way they split tells you what is on the neighbouring carbon.

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